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Explain what is wrong with the statement. The function \(P(t)=e^{-t^{2}}\) is a cumulative distribution function.

Short Answer

Expert verified
\(P(t) = e^{-t^2}\) does not have the properties of a CDF due to incorrect behavior at \(\pm\infty\) and it not being non-decreasing.

Step by step solution

01

Define Cumulative Distribution Function (CDF)

A cumulative distribution function, or CDF, is a function that describes the probability that a random variable is less than or equal to a certain value. For a function \(F(x)\) to be a valid CDF, it must satisfy the following properties: 1) \( F(-\infty) = 0 \), 2) \( F(\infty) = 1 \), 3) \( F(x) \) is a non-decreasing function.
02

Check End Behavior

Let's evaluate the behavior of \(P(t) = e^{-t^2}\) as \(t\) approaches \(-\infty\) and \(\infty\). As \(t \to -\infty\), \(t^2\) becomes very large, making \(e^{-t^2}\) approach zero. As \(t \to \infty\), the same reasoning applies, and \(e^{-t^2}\) also approaches 0. So, \(P(t)\) does not meet the requirements that \(P(-\infty) = 0\) and \(P(\infty) = 1\).
03

Check Monotonicity

For \(P(t)\) to be a valid CDF, it needs to be non-decreasing. Taking the derivative \(P'(t) = -2t \cdot e^{-t^2}\), we observe that this is negative for \(t > 0\), zero at \(t = 0\), and positive for \(t < 0\). Thus, the function decreases for \(t > 0\), increasing for \(t < 0\), and hence is not non-decreasing overall.
04

Identify the Issue

Given the observations in the previous steps, \(P(t) = e^{-t^2}\) is neither a non-decreasing function nor does it have the correct boundary values. Thus, it cannot be a valid cumulative distribution function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

CDF properties
A cumulative distribution function (CDF) is essential for describing the behavior of random variables in probability and statistics. One of the main purposes of a CDF is to define the probability that a random variable takes on a value less than or equal to a specific point. To be considered a valid CDF, a function must satisfy three important properties:
  • It starts at zero: For any CDF function, the value at negative infinity must be zero, i.e., \( F(-\infty) = 0 \).
  • It ends at one: As the variable approaches positive infinity, the CDF should reach one, so \( F(\infty) = 1 \).
  • It is non-decreasing: The values should never decrease as you move from left to right along the x-axis. This means that the function must be non-decreasing for all real numbers.
Not abiding by these rules disqualifies a function from being a valid CDF, as demonstrated by the example function \( P(t) = e^{-t^2} \) which fails to meet these criteria.
end behavior
The end behavior of a function provides critical insight into whether or not a function qualifies as a cumulative distribution function. When assessing the end behavior, you analyze what happens to the function as the variable approaches both negative and positive infinity.

For a valid cumulative distribution function:
  • As \( t \) approaches \( -\infty \), the function should tend towards zero.
  • As \( t \) moves towards \( \infty \), the function must approach one.
The example function \( P(t) = e^{-t^2} \) approaches zero at both extremes \(-\infty\) and \( \infty\), which contradicts the required boundary of reaching one as \( t \) approaches \( \infty \). Thus, it does not satisfy the end behavior criteria needed for a CDF.
monotonicity
Monotonicity is a key characteristic of a cumulative distribution function, ensuring that the function does not decrease as the variable increases. A CDF must be a non-decreasing function, which mathematically means that the slope, or derivative of the function, should be zero or positive for all values of the variable.

In the case of \( P(t) = e^{-t^2} \), its derivative, \( P'(t) = -2t \cdot e^{-t^2} \), presents issues with monotonicity:
  • For \( t > 0 \), the derivative is negative, indicating a decreasing function.
  • For \( t < 0 \), the derivative is positive, showing an increasing trend.
  • At \( t = 0 \), the derivative is zero, offering brief monotonicity.
Because the derivative changes sign based on the value of \( t \), \( P(t) \) is not a non-decreasing function from \(-\infty\) to \( \infty\), thus invalidating it as a CDF.
probability function
Probability functions, specifically CDFs, are tools that ensure every possible outcome of a random variable can be captured under the probability scale of 0 to 1. This scale relies on the CDF's properties: correctly displaying the probability all possible events accumulate to one, starting at zero probability and ending at full probability, while adhering to monotonicity.

When a function does not meet this structure, it cannot provide a valid measure of total probability over the full spectrum of a random variable. The function \( P(t) = e^{-t^2} \) fails because it does not end at a probability of one as the variable approaches infinity.
  • It never encompasses all probabilities since it begins and ends at zero.
  • It cannot be considered a comprehensive representation of cumulative probabilities across an interval.
For a function to be a probability function, especially a CDF, these foundational requirements must consistently apply.

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