/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Antidifferentiate using the tabl... [FREE SOLUTION] | 91Ó°ÊÓ

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Antidifferentiate using the table of integrals. You may need to transform the integrand first. $$\int \tan ^{4} x d x$$

Short Answer

Expert verified
The antiderivative is \( \tan x \sec x - 2\tan x + x + C \).

Step by step solution

01

Recognize the integral requires transformation

The given integral is \( \int \tan ^{4} x \, dx \). To use common integral forms, you need to express \( \tan^4 x \) in a more integrable form, which often involves trigonometric identities.
02

Apply trigonometric identity

Recall that \( \tan^2 x = \sec^2 x - 1 \). Therefore, \( \tan^4 x = (\tan^2 x)^2 = (\sec^2 x - 1)^2 \). Expand this expression to \( \sec^4 x - 2\sec^2 x + 1 \).
03

Break down and integrate each term separately

Now rewrite the integral as three separate integrals: \( \int (\sec^4 x - 2\sec^2 x + 1) \, dx = \int \sec^4 x \, dx - 2\int \sec^2 x \, dx + \int 1 \, dx \).
04

Use standard integrals

Use the standard integrals: 1. \( \int \sec^2 x \, dx = \tan x + C \).2. \( \int \sec^4 x \, dx = \int (\sec^2 x)^2 \, dx = \tan x \sec x + C_1 \). Therefore, simplify for \( \sec^2 x \):- \( \int \sec^2 x \, dx = \tan x \).- \( \int 1 \, dx = x \).Now substitute these into the separated integrals.
05

Combine and simplify results

Putting it all together, the integral becomes: \[ \int \sec^4 x \, dx - 2\int \sec^2 x \, dx + \int 1 \, dx = (\tan x \sec x) - 2(\tan x) + x + C \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Identity
Trigonometric identities play a crucial role in transforming complex trigonometric expressions into simpler forms that are easier to integrate. When faced with a challenging integral involving powers of trigonometric functions, these identities become invaluable tools.

Some of the most common trigonometric identities include:
  • \( \tan^2 x = \sec^2 x - 1 \)
  • \( \sin^2 x + \cos^2 x = 1 \)
  • \( 1 + \tan^2 x = \sec^2 x \)
In this exercise, the identity \( \tan^2 x = \sec^2 x - 1 \) is used twice to transform \( \tan^4 x \) into a more manageable expression, \( \sec^4 x - 2\sec^2 x + 1 \). By recognizing and applying these relationships, \( \tan^4 x \) can be expressed in a form that allows us to use standard integrals.
Secant Function
The secant function, denoted as \( \sec x \), is the reciprocal of the cosine function, i.e., \( \sec x = \frac{1}{\cos x} \). This function is often encountered in calculus, especially when dealing with integrals of trigonometric functions. Understanding the properties and behaviors of \( \sec x \) is essential for solving integrals involving secant-related expressions.

The secant function aids in transforming trigonometric integrals by simplifying expressions such as \( \tan^2 x \) into ones involving \( \sec^2 x \). For instance, when \( \tan^4 x \) is written as \( (\sec^2 x - 1)^2 \), it can be expanded and integrated term-by-term with standard forms. This enables us to separate complex expressions into simpler components, each of which can be integrated using known methods or transformations.
Integral Transformation
Integral transformation is a technique used to simplify an integrand by expressing it in a different, often more convenient form. In this exercise, an integral transformation was necessary to rewrite \( \tan^4 x \) in terms of \( \sec^2 x \) and constants, thereby allowing for straightforward integration.

Transforming an integral can involve several strategies:
  • Substituting using trigonometric identities to reduce the power of the trigonometric functions.
  • Changing variables to simplify the integral generally, such as using trigonometric or hyperbolic substitutions.
  • Factoring or expanding expressions to align them with standard integral forms.
The transformation from \( \tan^4 x \) to \( \sec^4 x - 2\sec^2 x + 1 \) is based on recognizing suitable identities and leveraging them to make the expression integrable using well-known methods.
Standard Integrals
Standard integrals are pre-derived formulas for the integration of common functions, including basic and trigonometric functions. These formulas are vital because they allow for the quick computation of integrals without having to derive the results from scratch.

Some commonly used standard integrals for trigonometric functions include:
  • \( \int \sec^2 x \, dx = \tan x + C \)
  • \( \int \sin x \, dx = -\cos x + C \)
  • \( \int \cos x \, dx = \sin x + C \)
  • \( \int 1 \, dx = x + C \)
In this exercise, the standard integrals \( \int \sec^2 x \, dx \) and \( \int 1 \, dx \) were used to solve the problem. These integrals enable the separate integration of the components derived from transforming \( \tan^4 x \) into \( \sec^4 x - 2\sec^2 x + 1 \), leading us efficiently to the final result by combining individual integrations.

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Most popular questions from this chapter

(a) Between 2005 and \(2015,\) ACME Widgets sold widgets at a continuous rate of \(R=R_{0} e^{0.125 t}\) widgets per year, where \(t\) is time in years since January 1 2005\. Suppose they were selling widgets at a rate of 1000 per year on January \(1,2005 .\) How many widgets did they sell between 2005 and \(2015 ?\) How many did they sell if the rate on January 1,2005 was 1,000,000 widgets per year? (b) In the first case ( 1000 widgets per year on January 1,2005)\(,\) how long did it take for half the widgets in the ten-year period to be sold? In the second case \((1.000 .000 \text { widgets per year on January } 1,2005)\) when had half the widgets in the ten-year period been sold? (c) In \(2015,\) ACME advertised that half the widgets it had sold in the previous ten years were still in use. Based on your answer to part (b), how long must a widget last in order to justify this claim?

Evaluate the integral. Your answer should not contain \(f,\) which is a differentiable function with the following values: (TABLE CAN'T COPY) $$\int_{1}^{3} f^{\prime}(x) e^{f(x)} d x$$

Give an example of:An integral that can be made easier to evaluate by using the trigonometric substitution \(x=\frac{3}{2} \sin \theta\).

Which technique is useful in evaluating the integral? (a) Integration by parts (b) Partial fractions (c) Long division (d) Completing the square (e) A trig substitution (f) Other substitutions $$\int \frac{x^{2}}{1-x^{2}} d x$$

Explain what is wrong with the statement. By Formula II-8 of the table with \(a=1, b=1\) $$ \int e^{x} \sin x d x=\frac{1}{2} e^{x}(\sin x-\cos x)+C $$ Therefore $$ \begin{array}{l} \int e^{2 x+1} \sin (2 x+1) d x= \\ \frac{1}{2} e^{2 x+1}(\sin (2 x+1)-\cos (2 x+1))+C \end{array} $$

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