Chapter 7: Problem 41
Calculate the integrals.$$\int \frac{x}{x^{2}-3 x+2} d x$$.
Short Answer
Expert verified
\( \frac{1}{2} \ln|x-1| + \frac{1}{2} \ln|x-2| + C \).
Step by step solution
01
Recognize the Form of the Integral
The integral is \( \int \frac{x}{x^{2}-3x+2} \, dx \). It can be approached using partial fraction decomposition because the denominator is a quadratic polynomial.
02
Factor the Denominator
Factor the quadratic expression \( x^2 - 3x + 2 \) to get \((x-1)(x-2)\). Now, rewrite the integral using these factors.
03
Set Up Partial Fraction Decomposition
Express \( \frac{x}{(x-1)(x-2)} \) as \( \frac{A}{x-1} + \frac{B}{x-2} \). Find \( A \) and \( B \) by equating:\[ x = A(x-2) + B(x-1). \]
04
Solve for Coefficients A and B
Expand and combine the terms: \( x = Ax - 2A + Bx - B \). Equate coefficients to solve for \(A\) and \(B\):\[ A + B = 1, \]\[ -2A - B = 0. \]Solve these to find that \( A = \frac{1}{2} \) and \( B = \frac{1}{2} \).
05
Rewrite the Integral with Partial Fractions
The integral can now be written as:\[ \int \left( \frac{1/2}{x-1} + \frac{1/2}{x-2} \right) \, dx. \]
06
Integrate Each Term Separately
Integrate each term individually: \( \int \frac{1/2}{x-1} \, dx = \frac{1}{2} \ln|x-1| \) and \( \int \frac{1/2}{x-2} \, dx = \frac{1}{2} \ln|x-2| \).
07
Write the Final Answer
Combine the results from the integration:\[ \int \frac{x}{x^2-3x+2} \, dx = \frac{1}{2} \ln|x-1| + \frac{1}{2} \ln|x-2| + C, \] where \( C \) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Fraction Decomposition
Partial fraction decomposition is a technique used to simplify the integration or manipulation of rational functions. These are fractions where both the numerator and the denominator are polynomials. By breaking down a complex rational expression into simpler fractions, we make integration more straightforward.Let's consider how this approach works:
- The goal of partial fraction decomposition is to express a given rational function as a sum of simpler fractions.
- This process helps us integrate each simple fraction separately, which is easier than integrating the original complex fraction.
- In the context of the exercise, by decomposing the function \( \frac{x}{(x-1)(x-2)} \) into \( \frac{A}{x-1} + \frac{B}{x-2} \), we simplify the integral calculation.
Quadratic Polynomial
A quadratic polynomial is a second-degree polynomial. It often takes the general form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). Quadratic polynomials are very common in calculus and algebra.In the exercise, we dealt with a specific quadratic: \( x^2 - 3x + 2 \).
- The first step in handling such a polynomial is to factor it if possible. Factoring turns the quadratic into a product of two linear factors, simplifying the expressions involved.
- For \( x^2 - 3x + 2 \), we factor it as \((x-1)(x-2)\). This was crucial for performing partial fraction decomposition.
Partial Fractions
Partial fractions refer to the simpler fractions that you get after decomposing a complex rational expression. They transform our original problem into easier, separate problems.Consider the usage of partial fractions in integration:
- Once we know the decomposition, instead of integrating \( \frac{x}{x^2-3x+2} \) directly, we may integrate \( \frac{1/2}{x-1} + \frac{1/2}{x-2} \).
- Each fraction can now be integrated as a natural logarithmic function because they have the pattern \( \frac{A}{x-q} \), where \( A \) is a constant and \( q \) is part of a linear denominator.
- Thus, the integration becomes simpler: \( \int \frac{1/2}{x-1} \, dx \rightarrow \frac{1}{2} \ln|x-1| \) and \( \int \frac{1/2}{x-2} \, dx \rightarrow \frac{1}{2} \ln|x-2| \).