Chapter 6: Problem 75
In Exercises \(66-75,\) decide if the statement is True or False by differentiating the right-hand side. $$\int x \cos x \, d x=\frac{x^{2}}{2} \sin x+C$$
Short Answer
Expert verified
The statement is False; differentiation does not yield the integrand.
Step by step solution
01
Differentiate the Right Side
To check if the integration statement is true, we need to differentiate the right-hand side of the equation. The given right-hand side is \( \frac{x^2}{2}\sin x + C \). We will apply the product rule and chain rule to differentiate.
02
Apply the Product Rule
The product rule states that if you have a product \( u(x)v(x) \), the derivative is \( u'(x)v(x) + u(x)v'(x) \). Here, consider \( u(x) = \frac{x^2}{2} \) and \( v(x) = \sin x \).
03
Differentiate \(u(x) = \frac{x^2}{2}\)
Find the derivative of \( u(x) = \frac{x^2}{2} \). Deriving with respect to \( x \), we get \( u'(x) = x \) since \( \frac{1}{2}(2x) = x \).
04
Differentiate \(v(x) = \sin x\)
Find the derivative of \( v(x) = \sin x \). Deriving, we get \( v'(x) = \cos x \).
05
Apply Product Rule Formula
Using the product rule, substitute into the formula: \( \frac{d}{dx}(\frac{x^2}{2} \sin x) = x \sin x + \frac{x^2}{2} \cos x \).
06
Simplify and Compare
The differentiation result is \( x \sin x + \frac{x^2}{2} \cos x \). Compare it to \( x \cos x \), the integrand on the left side. They are not equivalent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation
Differentiation is a key concept in calculus that focuses on finding the rate at which a function is changing at any given point. In simpler terms, differentiation allows us to determine how a particular quantity changes with respect to another quantity. When you look at a curve on a graph, differentiation gives the slope or steepness of that curve at any point.
The process of differentiation involves finding the derivative of a function. If you have a function, say, \( f(x) \), then the derivative, denoted as \( f'(x) \), provides the rate of change of \( f(x) \) with respect to \( x \).
Important points to remember about differentiation include:
The process of differentiation involves finding the derivative of a function. If you have a function, say, \( f(x) \), then the derivative, denoted as \( f'(x) \), provides the rate of change of \( f(x) \) with respect to \( x \).
Important points to remember about differentiation include:
- The derivative of a constant is zero. For example, if \( f(x) = 5 \), then \( f'(x) = 0 \).
- The derivative of a polynomial function can be found by applying the power rule: \( \frac{d}{dx}x^n = nx^{n-1} \).
- For composite functions, the chain rule is used.
Integration
Integration is the reverse process of differentiation in calculus. It's all about finding the total accumulation of a quantity, which is essential in calculating areas under curves, among other applications. If differentiation tells us how a function changes, integration helps us understand the accumulation or total value derived from those changes.
When you integrate a function, you're essentially adding up an infinite number of infinitesimally small pieces. The integral of a function \( f(x) \) gives us a new function, often referred to as the anti-derivative, denoted by \( \int f(x) \, dx \).
Key elements of integration include:
When you integrate a function, you're essentially adding up an infinite number of infinitesimally small pieces. The integral of a function \( f(x) \) gives us a new function, often referred to as the anti-derivative, denoted by \( \int f(x) \, dx \).
Key elements of integration include:
- Definite Integrals: These provide a number, representing the area under the curve from one point to another.
- Indefinite Integrals: These give a general form of the function that could generate the original function when differentiated.
- The constant \( C \): In indefinite integrals, \( C \) represents any constant because the derivative of a constant is zero.
Product Rule
The product rule is an important tool used in differentiation. It handles functions that are multiplied together, providing a way to differentiate a product of two functions. For instance, if you have functions \( u(x) \) and \( v(x) \), the product rule states that their derivative is given by:
\[ \frac{d}{dx}[u(x)v(x)] = u'(x)v(x) + u(x)v'(x) \]
This rule is crucial when dealing with equations involving products of two different polynomial or trigonometric functions.
Let's break down how this rule is typically used:
\[ \frac{d}{dx}[u(x)v(x)] = u'(x)v(x) + u(x)v'(x) \]
This rule is crucial when dealing with equations involving products of two different polynomial or trigonometric functions.
Let's break down how this rule is typically used:
- Select your two functions, \( u(x) \) and \( v(x) \).
- Find the derivatives \( u'(x) \) and \( v'(x) \).
- Apply the product rule: first derivative times the second function plus the second derivative times the first function.