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Let \(F(x)=\int_{2}^{x}(1 / \ln t) d t\) for \(x \geq 2\) (a) Find \(F^{\prime}(x)\) (b) Is \(F\) increasing or decreasing? What can you say about the concavity of its graph? (c) Sketch a graph of \(F(x)\)

Short Answer

Expert verified
(a) \( F'(x) = \frac{1}{\ln x} \); (b) F is decreasing on \([2, e)\) and increasing on \((e, \infty)\); concave down everywhere. (c) The graph is concave down, decreasing to increasing at \(x = e\).

Step by step solution

01

Differentiate the Function

The given function is defined by the integral:\[ F(x) = \int_{2}^{x} \frac{1}{\ln t} \ dt \]To find the derivative \( F'(x) \), we can use the Fundamental Theorem of Calculus. The theorem states that if \( F(x) = \int_{a}^{x} f(t) \, dt \), then \( F'(x) = f(x) \). Applying this, we obtain:\[ F'(x) = \frac{1}{\ln x} \]
02

Determine Increasing or Decreasing Nature

To determine whether the function \( F \) is increasing or decreasing, we look at the sign of \( F'(x) = \frac{1}{\ln x} \). The derivative is positive if \( \ln x > 0 \), which happens for \( x > e \). Since \( F'(x) \) does not change sign for \( x > e \), \( F(x) \) is increasing when \( x > e \). Conversely, \( F(x) \) is decreasing for \( 2 \leq x < e \).
03

Examine Concavity and Second Derivative

To determine the concavity of the function, we find the second derivative. Start by differentiating \( F'(x) = \frac{1}{\ln x} \) using the chain rule:\[ F''(x) = -\frac{1}{(\ln x)^2 \cdot x} \]The second derivative \( F''(x) < 0 \) for all \( x \geq 2 \), indicating that the graph of \( F(x) \) is concave down everywhere.
04

Sketch the Graph

Based on the derivative information, we know \( F(x) \) is decreasing on \( [2, e) \) and increasing on \( (e, \infty) \), while it is concave down everywhere. Start the sketch at point \( x = 2 \), and draw a curve that decreases until \( x = e \), then increases while remaining concave down.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Derivative: What it Tells Us
The derivative of a function gives us the rate at which the function is changing at any given point. It is an essential tool in calculus that provides insights into the behavior of a function. For the function given by the integral \( F(x) = \int_{2}^{x} \frac{1}{\ln t} \ dt \), the Fundamental Theorem of Calculus states that its derivative \( F'(x) \) is simply the integral's integrand evaluated at \( x \). Here, this means \( F'(x) = \frac{1}{\ln x} \).

This derivative, \( F'(x) = \frac{1}{\ln x} \), helps us quickly determine how the function is behaving. If \( F'(x) > 0 \), the function \( F(x) \) is increasing at that point. Conversely, if \( F'(x) < 0 \), the function is decreasing.
  • The derivative tells us if the function is growing or shrinking in value.
  • By analyzing \( F'(x) \), we gain insight into how \( F(x) \) behaves over its domain.
  • It reflects the local behavior of the function around any point \( x \).
Understanding Concavity: The Role of the Second Derivative
Concavity of a function describes the direction a curve bends, letting us know if it's bulging upwards or downwards. To explore this, we need to find the second derivative. For the function \( F(x) = \int_{2}^{x} \frac{1}{\ln t} \ dt \), the second derivative \( F''(x) \) is found by further differentiating \( F'(x) = \frac{1}{\ln x} \).

Using the chain rule, \( F''(x) = -\frac{1}{(\ln x)^2 \cdot x} \). The negative sign in front indicates that \( F''(x) < 0 \) for all \( x \geq 2 \). This tells us:
  • The graph of \( F(x) \) is concave down across its entire domain.
  • A concave-down graph curves downwards, like an upside-down bowl.
  • This property can help in sketching the graph since every part of \( F(x) \) will have this downward curvature.
Increasing and Decreasing Functions: Analyzing the Sign of the Derivative
Knowing when a function is increasing or decreasing is crucial for understanding its overall behavior. A function is increasing in intervals where its derivative \( F'(x) \) is positive and decreasing where \( F'(x) \) is negative. For \( F(x) = \int_{2}^{x} \frac{1}{\ln t} \ dt \), the critical factor is \( F'(x) = \frac{1}{\ln x} \).

For \( x > e \), \( \ln x > 0 \) which makes \( F'(x) > 0 \). Therefore, \( F(x) \) is increasing in the interval \((e, \infty)\). For \( 2 \leq x < e \), however, we have \( \ln x < 0 \) and thus \( F'(x) < 0 \), indicating that \( F(x) \) is decreasing in this interval.
  • Identifying intervals of increase and decrease helps in predicting long-term behavior.
  • The intervals of increase and decrease directly affect how the graph of \( F(x) \) is sketched.
  • This information can also confirm or predict specific features such as local maxima or minima.

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