/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 Express the given limit of a Rie... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Express the given limit of a Riemann sum as a definite integral and then evaluate the integral. $$\lim _{n \rightarrow \infty} \sum_{i=1}^{n}\left(8\left(1+\frac{i}{n}\right)-8\right) \cdot \frac{1}{n}$$

Short Answer

Expert verified
The limit as a definite integral evaluates to 4.

Step by step solution

01

Identify the Function and Interval

The given Riemann sum is \( \lim_{n \rightarrow \infty} \sum_{i=1}^{n} \left( 8\left(1+\frac{i}{n}\right) - 8 \right) \cdot \frac{1}{n} \). Notice that the expression inside the sum is of the form \( f(x_i^*) \cdot \Delta x \), where \( \Delta x = \frac{1}{n} \).Here, \( f(x) = 8x - 8 \) and the limits for \(x_i^*\), which are placeholders for \( i/n \), span from 1 to \( 1 + 1 = 2 \), giving the interval \([1,2]\).
02

Express the Riemann Sum as a Definite Integral

Rewrite the Riemann sum as a definite integral:\[ \int_{1}^{2} (8x - 8) \ dx \] The Riemann sum over an interval is equivalent to evaluating \( f(x) \) using integration over the specified interval.
03

Evaluate the Integral

To evaluate \( \int_{1}^{2} (8x - 8) \ dx \), find the antiderivative of \( 8x - 8 \):The antiderivative of \( 8x \) is \( 4x^2 \) and the antiderivative of \( -8 \) is \( -8x \).Thus, the antiderivative is \( F(x) = 4x^2 - 8x \).
04

Apply the Fundamental Theorem of Calculus

Apply the Fundamental Theorem of Calculus and evaluate \( F(x) \) at the upper and lower bounds:\[ F(2) = 4(2)^2 - 8(2) = 16 - 16 = 0 \]\[ F(1) = 4(1)^2 - 8(1) = 4 - 8 = -4 \]The definite integral is the difference \( F(2) - F(1) \):\[ 0 - (-4) = 4 \]
05

Conclude the Solution

The solution to the given limit expressed as a definite integral and its evaluation is:\[ \int_{1}^{2} (8x - 8) \ dx = 4 \] The evaluated integral equals 4.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integral
A definite integral is a powerful mathematical concept that measures the area under a curve within a given interval. In simpler terms, it helps you find the accumulated total value from a starting point to an ending point on a function's graph. For the given exercise, we have expressed a Riemann sum as a definite integral. This integral captures the area between the function \( f(x) = 8x - 8 \) and the x-axis over the interval from 1 to 2.
To denote a definite integral, you use the format \( \int_{a}^{b} f(x) \ dx \), where \( a \) is the starting point and \( b \) is the endpoint. This notation tells you that the function \( f(x) \) is being integrated from \( a \) to \( b \). Integrating the function provides the exact area under its curve over the specified interval. Thus, it's more precise and easier than adding up small rectangles as in a Riemann sum.
Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus is a cornerstone in mathematics, linking the concepts of differentiation and integration. It essentially tells us two things: first, that the process of integration (finding an area) is the reverse operation of differentiation (finding a slope); second, it provides a practical way to evaluate definite integrals.
When applying this theorem, you first find the antiderivative of the function you're dealing with, which we did by finding \( F(x) = 4x^2 - 8x \) for \( f(x) = 8x - 8 \). You then evaluate this antiderivative at both the upper and lower bounds of your interval. Finally, subtract the lower bound value from the upper bound value to get the definite integral's value. In our exercise, using these steps, we evaluated the definite integral to 4.
Antiderivative
An antiderivative, sometimes called an indefinite integral, is basically a "reverse derivative." While a derivative gives you the rate of change, an antiderivative gives you a function whose derivative is the original one. For \( f(x) = 8x - 8 \), the task is to find a function, which when differentiated yields \( 8x - 8 \).
In this specific situation, the antiderivative is \( F(x) = 4x^2 - 8x \). Finding this function involves understanding some basic derivative rules and performing them in reverse. Once you find it, the antiderivative function can be used to compute definite integrals by utilizing the Fundamental Theorem of Calculus.
Limit of a Sum
The concept of the limit of a sum bridges the gap between approximation and precision in calculus. Riemann sums are used to approximate the area under a curve by summing up areas of rectangles, and their limit as these rectangles become infinitely thin (as \( n \) approaches infinity) gives us the exact value of the definite integral.
Looking at the exercise: initially, we have a sum \( \sum_{i=1}^{n} (8(1+\frac{i}{n})-8) \cdot \frac{1}{n} \). This expression represents adding areas of rectangles under a curve. By taking the limit as \( n \) goes to infinity, the rectangles become very thin and fill the space accurately under the curve of \( f(x) \). Thus, using the limit of this sum transforms it into a neat, exact integral, \( \int_{1}^{2} (8x - 8) \ dx \), which is then evaluated to find the precise area.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Assume that \(0 \leq a \leq b .\) Use geometry to construct a formula in terms of \(a\) and \(b\) for $$\int_{a}^{b} x d x$$ (b) Use the result of part (a) to find: (i) \(\int_{2}^{5} x d x\quad\) (ii) \(\int_{-3}^{8} x d x\quad\) (iii) \(\int_{1}^{3} 5 x d x\)

A bar of metal is cooling from \(1000^{\circ} \mathrm{C}\) to room temperature, \(20^{\circ} \mathrm{C}\). The temperature, \(H\), of the bar \(t\) minutes after it starts cooling is given, in \(^{\circ} \mathrm{C},\) by $$H=20+980 e^{-0.1 t}$$ (a) Find the temperature of the bar at the end of one hour. (b) Find the average value of the temperature over the first hour. (c) Is your answer to part (b) greater or smaller than the average of the temperatures at the beginning and the end of the hour? Explain this in terms of the concavity of the graph of \(H.\)

Find the area of the region between the curve and the horizontal axis. Under \(y=\ln x\) for \(1 \leq x \leq 4.\)

Estimate the integral using a left-hand sum and a right-hand sum with the given value of \(n .\) $$\int_{1}^{4} \sqrt{x} d x, n=3$$

Refer to a May \(2,2010,\) article: \(^{11}\) "The crisis began around 10 am yesterday when a 10-foot wide pipe in Weston sprang a leak, which worsened throughout the afternoon and eventually cut off Greater Boston from the Quabbin Reservoir, where most of its water supply is stored... Before water was shut off to the ruptured pipe [at 6: 40 pm], brown water had been roaring from a massive crater [at a rate of] 8 million gallons an hour rushing into the nearby Charles River." Let \(r(t)\) be the rate in gallons/hr that water flowed from the pipe \(t\) hours after it sprang its leak. Give a reasonable overestimate of \(\int_{0}^{8} r(t) d t\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.