Chapter 5: Problem 62
The limit is either a right-hand or left hand Riemann sum \(\sum f\left(t_{i}\right) \Delta t .\) For the given choice of \(t_{i}\) write the limit as a definite integral. $$\lim _{n \rightarrow \infty} \sum_{i=0}^{n-1} \frac{1}{n} e^{1+i / n} ; \quad t_{i}=1+\frac{i}{n}$$
Short Answer
Expert verified
The Riemann sum is represented by the integral \( \int_{1}^{2} e^{t} \, dt \).
Step by step solution
01
Understand the Structure of the Riemann Sum
The given expression \( \lim _{n \rightarrow \infty} \sum_{i=0}^{n-1} \frac{1}{n} e^{1+i / n} \) is a Riemann sum. The Riemann sum is generally of the form \( \sum f(t_i) \Delta t \), where \( \Delta t \) is the width of each subinterval, and \( f(t_i) \) represents the function value at chosen sample points \( t_i \) within each subinterval.
02
Identify the Components of the Riemann Sum
From the given sum \( \sum_{i=0}^{n-1} \frac{1}{n} e^{1+i / n} \), we identify \( \Delta t = \frac{1}{n} \) and \( f(t_i) = e^{t_i} \). Here, \( t_i = 1 + \frac{i}{n} \), which defines the sample points.
03
Determine the Integration Limit
The limits of integration are determined by the limits of \( t_i \) as \( i \) ranges from 0 to \( n-1 \). For the left-hand endpoint when \( i = 0 \), \( t_i = 1 + \frac{0}{n} = 1 \). For the right-hand endpoint as \( i = n-1 \), \( t_i = 1 + \frac{n-1}{n} \approx 2 \) as \( n \to \infty \). Thus, the integral will go from 1 to 2.
04
Write the Definite Integral
Replace the Riemann sum with the corresponding definite integral based on the function and limits determined. The definite integral is given by:\[\int_{1}^{2} e^{t} \, dt\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Riemann sum
A Riemann sum is a method to approximate the integral of a function over an interval. It's essentially adding up a lot of little rectangles underneath a curve to estimate the total area under the curve. Each rectangle represents a subinterval with a specific width, known as \( \Delta t \). For each subinterval, there is a sample point, \( t_i \), where the function is evaluated. This approach is fundamental in calculus because it gives us a straightforward, yet powerful, way to explore the concept of integrating functions over a continuous range.
- The width of each rectangle is \( \Delta t \), representing tiny pieces of the interval.
- \( f(t_i) \) is the height of the rectangle, given by the function value at the sample point \( t_i \).
limit of integration
The limit of integration is closely related to the endpoints between which we want to find the total area under a curve by integrating a function. It's important to determine these boundaries correctly to accurately represent the integral as a function of those limits. The integration limit is found from the sample points \( t_i \), calculated based on the given intervals and the number of rectangles (or partitions) in the sum.
- The starting point of integration corresponds to \( t_i \) when the index \( i \) is 0.
- The endpoint correlates with \( t_i \) when \( i \) increases to \( n-1 \), especially as \( n \rightarrow \infty \).
function evaluation
Function evaluation finds the specific value of a function at a given point inside the interval we are focusing on. In a Riemann sum, you use function evaluation to calculate the height of the rectangles mentioned above. When you evaluate the function at each sample point \( t_i \), you determine the contribution of that particular segment to the overall integral.In our case, the function we evaluated is \( f(t_i) = e^{t_i} \). This formula calculates the height of each rectangle at the sample point \( t_i \), which in turn is used to approximate the area under the curve of \( e^t \) over the interval from 1 to 2. Function evaluation helps us capture the change in function values across the interval which is crucial for accurate integration.
definite integral notation
Definite integral notation provides a compact and precise way to express the sum of infinite rectangles under a curve as the interval approaches a continuous scale. It's usually written as \( \int_{a}^{b} f(x) \, dx \), where \( a \) and \( b \) are the limits of integration, \( f(x) \) is the function being integrated, and \( dx \) represents an infinitesimal change in the variable \( x \).For our Riemann sum example, the definite integral that represents this sum is \( \int_{1}^{2} e^t \, dt \). By integrating \( e^t \) from 1 to 2, we find the exact total area under the curve from the point where \( t = 1 \) to when \( t = 2 \). This notation makes it clear what function is being integrated and the specific region we are considering, providing a clear picture of the task at hand.