/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 The parametric equations describ... [FREE SOLUTION] | 91Ó°ÊÓ

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The parametric equations describe the motion of a particle. Find an equation of the curve along which the particle moves. $$\begin{aligned}&x=3 t+1\\\&y=t-4\end{aligned}$$

Short Answer

Expert verified
The curve equation is \( x = 3y + 13 \).

Step by step solution

01

Express t in terms of x

Start with the equation for x: \( x = 3t + 1 \). Solve for \( t \) by isolating it on one side of the equation. This involves subtracting 1 from both sides and then dividing by 3. The result is \( t = \frac{x - 1}{3} \).
02

Substitute t in the equation for y

Now that we have \( t \) in terms of \( x \), substitute \( t = \frac{x - 1}{3} \) into the equation for y: \( y = t - 4 \). Replacing \( t \) gives us \( y = \frac{x - 1}{3} - 4 \).
03

Simplify the equation for y

Simplify the expression for \( y \). Start with \( y = \frac{x - 1}{3} - 4 \). To simplify, find a common denominator (which is 3) and rewrite: \( y = \frac{x - 1}{3} - \frac{12}{3} \). This simplifies to \( y = \frac{x - 1 - 12}{3} = \frac{x - 13}{3} \).
04

Rearrange into a standard form

The equation \( y = \frac{x - 13}{3} \) can be rearranged into a more standard form: start by multiplying both sides by 3 to eliminate the fraction: \( 3y = x - 13 \). This can be written as \( x = 3y + 13 \), which represents the equation of the curve in Cartesian form.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian Equations
Parametric equations describe a curve or path by specifying coordinates \(x\) and \(y\) as functions of a parameter, typically \(t\). Converting them into a Cartesian equation involves eliminating the parameter to express \(y\) explicitly in terms of \(x\). To achieve this, separate and solve one of the original equations for \(t\), and then substitute this expression into the other equation. For example, given the parametric equations \(x = 3t + 1\) and \(y = t - 4\), solving the first equation gives \(t = \frac{x - 1}{3}\). Substituting this into the second equation transforms the parametric form into a single equation in terms of \(x\) and \(y\).The result is \(y = \frac{x - 13}{3}\), an equation in Cartesian form. This form gives a clear picture of the curve, allowing us to analyze relationships between \(x\) and \(y\) without the need for the parameter \(t\). Therefore, Cartesian equations are essential for simplifying complex motion into understandable mathematical relationships.
Equation of a Curve
The equation of a curve provides a way to represent a curve in a single, cohesive formula. This formula defines how the \(x\) coordinate relates to the \(y\) coordinate along a specific path. In the context of this exercise, converting parametric equations to a curve equation means synthesizing two separate relationships into one. By substituting the expression for \(t\) into the equation of \(y\), a continuous curve equation \(3y = x - 13\) is created. This means that for any point \( (x, y) \) on the curve, this equation must hold true.Understanding these curve equations helps visualize the path or trajectory of the particle. So whether it be a line, parabola, or more complex shape, converting to an equation of a curve makes the interpretation and analysis more straightforward.
Particle Motion
In particle motion studies, parametric equations are used to describe the movement of an object in terms of time. Each component, \(x(t)\) and \(y(t)\), illustrates how each coordinate changes as time progresses. For example, with \(x = 3t + 1\) and \(y = t - 4\), we see that the particle moves along a straight line in the plane. Here, \(t\) represents time, suggesting how the position of a particle evolves. Breaking down these equations demonstrates the individual motion along each axis:
  • The \(x\)-coordinate shifts at a constant rate proportional to \(t\).
  • The \(y\)-coordinate also changes linearly but with a different rate.
By eliminating \(t\) and deriving a Cartesian form, we consolidate this into a simpler representation of the path, \(x = 3y + 13\). This consolidation is critical in studying motion as it highlights the overall trajectory of the particle without being obscured by the parameter, allowing for easier analysis of the path taken by the particle over time.

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Most popular questions from this chapter

In a romantic relationship between Angela and Brian, who are unsuited for each other, \(a(t)\) represents the affection Angela has for Brian at time \(t\) days after they meet, while \(b(t)\) represents the affection Brian has for Angela at time \(t .\) If \(a(t)>0\) then Angela likes Brian; if \(a(t)<0\) then Angela dislikes Brian; if \(a(t)=0\) then \(\mathrm{An}-\) gela neither likes nor dislikes Brian. Their affection for each other is given by the relation \((a(t))^{2}+(b(t))^{2}=c\) where \(c\) is a constant. (a) Show that \(a(t) \cdot a^{\prime}(t)=-b(t) \cdot b^{\prime}(t)\) (b) At any time during their relationship, the rate per day at which Brian's affection for Angela changes is \(b^{\prime}(t)=-a(t) .\) Explain what this means if Angela (i) Likes Brian, (ii) Dislikes Brian. (c) Use parts (a) and (b) to show that \(a^{\prime}(t)=b(t) .\) Explain what this means if Brian (i) Likes Angela. (ii) Dislikes Angela. (d) If \(a(0)=1\) and \(b(0)=1\) who first dislikes the other?

Give an example of: A family of functions, \(f(x),\) depending on a parameter \(a,\) such that each member of the family has exactly one critical point.

Determine whether the limit exists, and where possible evaluate it. $$\lim _{x \rightarrow 0}\left(\frac{1}{x}-\frac{1}{\sin x}\right)$$

Explain what is wrong with the statement. The line segment from (2,2) to (0,0) is parameterized by \(x=2 t, y=2 t, 0 \leq t \leq 1.\)

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