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Suppose \(W\) is proportional to \(r^{3} .\) The derivative \(d W / d r\) is proportional to what power of \(r ?\)

Short Answer

Expert verified
The derivative \( dW/dr \) is proportional to \( r^2 \).

Step by step solution

01

Understand the Proportional Relationship

If a quantity, say \( W \), is proportional to another quantity, like \( r^3 \), it means \( W = k \cdot r^3 \), where \( k \) is a constant of proportionality.
02

Differentiate with Respect to \( r \)

To find \( \frac{dW}{dr} \), we differentiate the function \( W = k \cdot r^3 \) with respect to \( r \). Using the power rule of differentiation, which states that \( \frac{d}{dx}(x^n) = n \cdot x^{n-1} \), we get \[ \frac{dW}{dr} = k \cdot 3r^{3-1} = 3k \cdot r^2. \]
03

Determine the Proportional Power

From the differentiated expression \( \frac{dW}{dr} = 3k \cdot r^2 \), we see that \( \frac{dW}{dr} \) is proportional to \( r^2 \). The power of \( r \) in this relation is 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The Power Rule is a fundamental concept in calculus used for finding the derivative of functions in the form of a power of a variable. It simplifies the process of differentiation, which is essential for calculus applications.

Here's how it works:
  • If you have a function expressed as \[ f(x) = x^n \], where \( n \) is a constant,

  • the derivative, denoted by \( f'(x) \), is found using the rule:

  • \[ f'(x) = n \cdot x^{n-1} \]
For example, to differentiate \( x^3 \) according to the Power Rule, follow these steps:

1. Multiply the exponent by the coefficient (which is 1 if not specified), so it becomes \( 3 \cdot x \).
2. Subtract one from the exponent: \( x^{3-1} = x^2 \).

The derivative will then be \( 3 \cdot x^2 \).

This rule quickly gives you derivatives without fuss, making it easier for students to tackle derivative calculations.
Proportional Relationship
In mathematics, a proportional relationship means that two quantities change in relation to each other at a constant rate. When we say a variable \( W \) is proportional to \( r^3 \), it is expressed as:

\[ W = k \cdot r^3 \]
Here, \( k \) is a constant that doesn't change as \( r \) changes. This constant of proportionality ensures that even as one variable changes, their comparative relation remains consistent.

Proportional relationships are crucial:
  • They help predict how one quantity changes in response to another.
  • They simplify complex phenomena into manageable equations.
  • In our example with \( W \) and \( r^3 \), knowing \( W = k \cdot r^3 \) lets us explore how changes in \( r \) affect \( W \). This understanding is foundational in further manipulating the function via differentiation.
    Derivative Calculation
    Derivative calculation is the process of finding the rate at which a function is changing at any given point. It is essential in understanding the behavior of functions and is widely used across various scientific fields.

    For functions like \( W = k \cdot r^3 \), differentiating involves applying the Power Rule:

    1. Recognize the function form, \( k \cdot r^n \), where \( n = 3 \).2. Apply the Power Rule: \( n \cdot k \cdot r^{n-1} \), giving us \( 3k \cdot r^2 \).
    3. Resulting derivative:
    • \( \frac{dW}{dr} = 3k \cdot r^2 \)
    This derivative tells us the rate of change of \( W \) concerning \( r \). Significantly, the process exemplifies how differentiation can simplify and illuminate the core behavior of complex mathematical relationships. Understanding derivative calculation provides insights into the dynamics of any given model or phenomenon.

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    Most popular questions from this chapter

    A rubber duck bounces up and down in a pool after a stone is dropped into the water. The height of the duck, in inches, above the equilibrium position of the water is given as a function of time \(t,\) in seconds, by $$d(t)=e^{-t}(\cos t+\sin t)$$ (a) Find and interpret the practical meaning of the derivative \(d^{\prime}(t)\) (b) Determine when \(d^{\prime}(t)=0\) for \(t \geq 0 .\) What can you say about the duck when \(d^{\prime}(t)=0 ?\) (c) Determine \(\lim _{t \rightarrow \infty} d(t)\) and explain why this limit makes sense in practical terms.

    give an example of: Two different functions that have the same linear approximation near \(x=0\)

    Give an example of: A function that is equal to a constant multiple of its derivative but that is not equal to its derivative.

    Suppose that \(f\) is continuous on \([a, b]\) and differentiable on \((a, b)\) and that \(m \leq f^{\prime}(x) \leq M\) on \((a, b) .\) Use the Racetrack Principle to prove that \(f(x)-f(a) \leq M(x-a)\) for all \(x\) in \([a, b],\) and that \(m(x-a) \leq f(x)-f(a)\) for all \(x\) in \([a, b] .\) Conclude that \(m \leq(f(b)-f(a)) /(b-a) \leq\) \(M .\) This is called the Mean Value Inequality. In words: If the instantaneous rate of change of \(f\) is between \(m\) and \(M\) on an interval, so is the average rate of change of \(f\) over the interval.

    Multiply the local linearization of \(e^{x}\) near \(x=0\) by itself to obtain an approximation for \(e^{2 x} .\) Compare this with the actual local linearization of \(e^{2 x} .\) Explain why these two approximations are consistent, and discuss which one is more accurate.

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