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91Ó°ÊÓ

Find the local linearization of \(f(x)=x^{2}\) near \(x=1\)

Short Answer

Expert verified
The local linearization of \( f(x) = x^2 \) at \( x = 1 \) is \( L(x) = 2x - 1 \).

Step by step solution

01

Identify the Function and Point

We are given the function \( f(x) = x^{2} \) and we need to find the local linearization at \( x = 1 \).
02

Recall the Formula for Linearization

The formula for the linearization of a function \( f \) at point \( a \) is given by \( L(x) = f(a) + f'(a)(x-a) \).
03

Calculate \( f(a) \)

Substitute \( a = 1 \) into the function: \( f(1) = 1^{2} = 1 \).
04

Find the Derivative \( f'(x) \)

Differentiate the function \( f(x) = x^{2} \). The derivative is \( f'(x) = 2x \).
05

Evaluate \( f'(a) \)

Substitute \( x = 1 \) into the derivative: \( f'(1) = 2(1) = 2 \).
06

Write the Linearization Formula

Using the linearization formula \( L(x) = f(a) + f'(a)(x-a) \), and substituting the calculated values, \( L(x) = 1 + 2(x - 1) \).
07

Simplify the Expression

Distribute and simplify the expression: \( L(x) = 1 + 2x - 2 = 2x - 1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Functions
A function in mathematics is a fundamental concept that relates inputs to outputs. In simpler terms, it's like a machine where you put in a number, it undergoes a certain process, and then it gives back a result. Functions can express real-world phenomena, like the equation for the area of a circle or the trajectory of a ball.
A function is often written as \( f(x) \), where \( f \) represents the function and \( x \) is the input variable. For example, in the function \( f(x) = x^2 \), the input \( x \) is squared to produce the output.
Functions have domains, which are the allowed values for \( x \), and ranges, which are the possible resulting values. In our specific case of \( f(x) = x^2 \), the function transforms the variable \( x \) into its square. This transformation is consistent for any \( x \) you choose, making functions predictable and powerful tools for calculations.
Derivatives
Derivatives are a key concept in calculus. They measure how a function changes as its input changes. Imagine the derivative as the function’s slope or the rate of change at any given point.
For a function \( f(x) \), its derivative is noted as \( f'(x) \) or \( \frac{df}{dx} \). In plain language, the derivative tells you how steeply the graph of a function climbs or falls at a specific \( x \) value.

To get the derivative of a basic function like \( x^2 \), you apply differentiation rules. For \( f(x) = x^2 \), the derivative is \( f'(x) = 2x \). This derivative tells us that the slope of the tangent line to the curve at any point \( x \) is twice the value of \( x \). So, derivatives not only describe how a function behaves but also provide a means to approximate functions locally through linearization.
Tangent Approximation
Tangent approximation uses linearization to give a simple way to estimate function values near a specific point. It involves finding the tangent line to a curve at that point and using the line to approximate changes in the function.
When a function is differentiable at a point, the tangent line to the curve represents the function's best linear approximation near that point. This is helpful especially when calculating actual function values directly is complex.

To linearly approximate a function \( f \) near a point \( a \), you use the formula \( L(x) = f(a) + f'(a)(x-a) \). This linear function \( L(x) \) captures the behavior of \( f \) near \( a \). For the example \( f(x) = x^2 \) at \( x=1 \):
  • The original function value is \( f(1) = 1 \).
  • The derivative value is \( f'(1) = 2 \), indicating the tangent's slope.
  • Plugging these into the linearization formula gives \( L(x) = 1 + 2(x-1) = 2x - 1 \).
This linear equation \( L(x) = 2x - 1 \) effectively approximates the curve \( x^2 \) close to \( x=1 \). It's a quick, handy method to estimate values without diving into more complicated calculations.

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