Chapter 3: Problem 39
Give an example of: A value of \(k\) such that \(\lim _{x \rightarrow \infty} e^{k x}\) cosh \(x\) does not exist.
Short Answer
Expert verified
Choose \(k > -1\).
Step by step solution
01
Understanding the Exercise
We need to find a value of \(k\) such that the limit \(\lim_{x \rightarrow \infty} e^{kx} \cosh{x}\) does not exist. Consider the behavior of exponential functions and \(\cosh{x}\) as \(x\) approaches infinity.
02
Analyzing \(\cosh{x}\)
The hyperbolic cosine function \(\cosh{x}\) is defined as \(\cosh{x} = \frac{e^x + e^{-x}}{2}\). As \(x\) approaches infinity, \(e^x\) dominates, so \(\cosh{x} \approx \frac{e^x}{2}\).
03
Substituting and Simplifying
Substitute \(\cosh{x} \approx \frac{e^x}{2}\) into the original expression, yielding \(\lim_{x \rightarrow \infty} e^{kx} \cdot \frac{e^x}{2} = \lim_{x \rightarrow \infty} \frac{1}{2} e^{(k+1)x}\).
04
Determining the Behavior of the Expression
The expression \(\frac{1}{2} e^{(k+1)x}\) depends on the value of \(k+1\). If \((k+1) > 0\), the limit tends to infinity; if \((k+1) < 0\), the limit tends to zero. If \((k+1) = 0\), the limit remains constant. We need to choose \(k\) such that the limit does not exist.
05
Conclusion: Finding \(k\)
For the limit \(\lim_{x \rightarrow \infty} \frac{1}{2} e^{(k+1)x}\) not to exist, the function must neither converge to a value nor diverge in a simple manner. The simplest case is when \((k+1) > 0\), hence the limit diverges to infinity and does not exist as a finite value.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. For example, the function \(e^x\) is an exponential function, where \(e\) is known as Euler's number, approximately equal to 2.718. As the variable \(x\) increases, the value of \(e^x\) grows rapidly—a property that makes exponential functions crucial for modelling growth or decay processes.
- Exponential Growth: If the base of the exponential is greater than 1, as in \(e^x\), the function exhibits growth as \(x\) becomes larger.
- Exponential Decay: If the base lies between 0 and 1, the function decays as \(x\) increases.
Hyperbolic Functions
Hyperbolic functions are analogs to trigonometric functions but are expressed using exponential functions. The hyperbolic cosine function, represented as \(\cosh{x}\), is one such example that arises naturally in calculations involving exponential growth. The formula is given by:\[\cosh{x} = \frac{e^x + e^{-x}}{2}\]This definition shows how \(\cosh{x}\) blends exponential growth and decay. As \(x\) approaches infinity, the \(e^x\) term dominates the \(e^{-x}\) term, making the function behave approximately like an exponential function:\[\cosh{x} \approx \frac{e^x}{2}\] By substituting this approximation in our expression, it simplifies the analysis of limits, along with the exponential function \(e^{kx}\). Hyperbolic functions, therefore, mix the rapid growth or decay characteristic of exponential terms, influencing the limit behavior significantly.
Infinity
Infinity is not a real number but a concept that describes something that is unbounded or limitless. When analyzing limits, especially as a variable approaches infinity, we seek to understand the behavior of functions rather than calculating specific values.
- An expression like \(x \to \infty\) indicates that \(x\) is increasing without bounds.
- Limits involving infinity can result in various scenarios: a finite limit, growth to infinity, decay to zero, or non-existence.