Chapter 3: Problem 15
In Exercises \(1-57,\) find the derivatives. Assume that \(a, b,\) and \(c\) are constants. $$w=100 e^{-x^{2}}$$
Short Answer
Expert verified
The derivative is \(-200x e^{-x^2}\).
Step by step solution
01
Identify the structure of the function
The given function is \(w = 100 e^{-x^2}\). Notice that it is a composition of an exponential function and a quadratic function. Specifically, we have \(u(x) = -x^2\), making the function into \(w = 100 e^{u(x)}\). This will require the use of the chain rule.
02
Apply the chain rule
The chain rule states that the derivative of a composite function \(f(g(x))\) is \(f'(g(x)) \cdot g'(x)\). In this problem, our outer function is \(f(u) = 100 e^u\) and the inner function is \(u(x) = -x^2\). Begin by finding the derivatives of these components.
03
Find the derivative of the outer function
The derivative of the outer function \(f(u) = 100 e^u\) with respect to \(u\) is \(f'(u) = 100 e^u\) because the derivative of \(e^u\) is \(e^u\) and the constant 100 is carried along.
04
Find the derivative of the inner function
The derivative of the inner function \(u(x) = -x^2\) with respect to \(x\) is \(u'(x) = -2x\), using the power rule.
05
Combine the derivatives using the chain rule
By using the chain rule, the derivative of \(w = 100 e^{-x^2}\) is:\[\frac{dw}{dx} = f'(u(x)) \cdot u'(x) = (100 e^{-x^2}) \cdot (-2x)\]Simplify the expression: \(-200x e^{-x^2}\).
06
Write the final derivative
The derivative of the function \(w = 100 e^{-x^2}\) with respect to \(x\) is \(-200x e^{-x^2}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental principle in calculus for finding the derivative of a composite function. Imagine a function composed of two or more nested functions. The chain rule allows us to differentiate each part individually and then combine them. This rule can be summarized by the formula: if we have two functions, say, \( f(g(x)) \), the derivative is \( f'(g(x)) \cdot g'(x) \).
This means we first take the derivative of the outer function \( f \) with respect to its input \( g(x) \), and then multiply it by the derivative of the inner function \( g \) with respect to \( x \).
This means we first take the derivative of the outer function \( f \) with respect to its input \( g(x) \), and then multiply it by the derivative of the inner function \( g \) with respect to \( x \).
- Outer function: Evaluate the derivative of the outer function but keep the inner function intact.
- Inner function: Now, evaluate the derivative of the inner function.
Exponential Function
Exponential functions are functions of the form \( e^{x} \), where \( e \) is the base of the natural logarithm, approximately equal to 2.71828. These functions have unique properties and play a crucial role in calculus, especially in growth and decay models.
- The derivative of \( e^x \) is simply \( e^x \), which means the rate of change of \( e^x \) is itself.
- Exponential functions like \( e^{-x^2} \) can represent more complex expressions and have a profound impact on solving calculus problems, especially when combined with other functions using rules like the chain rule.
Power Rule
The power rule is a shortcut for finding the derivative of functions of the form \( x^n \), where \( n \) is a real number. This rule states that the derivative of \( x^n \) is \( nx^{n-1} \). It's particularly handy for polynomials.
Here's how it is typically applied:
Here's how it is typically applied:
- Take the exponent \( n \) and multiply it by the coefficient of \( x \).
- Subtract one from the original exponent to get the new exponent of \( x \).