Chapter 2: Problem 26
Find a formula for the derivative of the function using the difference quotient. $$g(x)=x^{3}+1$$
Short Answer
Expert verified
The derivative of \( g(x) = x^3 + 1 \) is \( g'(x) = 3x^2.\)
Step by step solution
01
Understand the Concept of Derivative
The derivative of a function at any point is the limit of the difference quotient as the step size approaches zero. For a function \( g(x) \), the derivative \( g'(x) \) can be expressed as: \[g'(x) = \lim_{h \to 0} \frac{g(x + h) - g(x)}{h}.\]
02
Find the Difference Quotient
Substitute \( g(x) = x^3 + 1 \) into the difference quotient formula. First, find \( g(x + h) \):\[g(x + h) = (x + h)^3 + 1.\]Now plug it into the difference quotient:\[\frac{(x + h)^3 + 1 - (x^3 + 1)}{h}.\]
03
Expand the Expression \((x + h)^3\)
Expand \((x + h)^3\) using the binomial theorem:\[(x + h)^3 = x^3 + 3x^2h + 3xh^2 + h^3.\]Substitute this back into the difference quotient:\[\frac{x^3 + 3x^2h + 3xh^2 + h^3 + 1 - x^3 - 1}{h}.\]
04
Simplify the Difference Quotient
Cancel out the \(x^3\) and \(1\) terms, then simplify:\[\frac{3x^2h + 3xh^2 + h^3}{h}.\]Factor \(h\) out of the numerator:\[\frac{h(3x^2 + 3xh + h^2)}{h}.\]
05
Divide and Simplify Further
Cancel \(h\) in the numerator and the denominator:\[3x^2 + 3xh + h^2.\]
06
Evaluate the Limit as \(h\) Approaches Zero
Take the limit as \(h\) approaches zero:\[\lim_{h \to 0} (3x^2 + 3xh + h^2) = 3x^2.\]
07
Conclusion of Derivative Calculation
Thus, the derivative of \( g(x) = x^3 + 1 \) is \[g'(x) = 3x^2.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference Quotient
The difference quotient is a critical concept in calculus and is essential for finding the derivative of a function. It provides a formula to calculate the slope of the tangent line to the curve of the function at any given point. By definition, the difference quotient for a function \( g(x) \) is expressed as:
For example, in the function \( g(x) = x^3 + 1 \), the application of the difference quotient involves substituting \( g(x + h) \) for the incremented function, and \( g(x) \) as the base function to create the formula \( \frac{(x + h)^3 + 1 - (x^3 + 1)}{h} \). This setup is the foundation for finding the derivative.
- \( \frac{g(x + h) - g(x)}{h} \)
For example, in the function \( g(x) = x^3 + 1 \), the application of the difference quotient involves substituting \( g(x + h) \) for the incremented function, and \( g(x) \) as the base function to create the formula \( \frac{(x + h)^3 + 1 - (x^3 + 1)}{h} \). This setup is the foundation for finding the derivative.
Binomial Theorem
The binomial theorem is a powerful tool in mathematics used to expand expressions that are raised to a power, such as \((x + h)^3\). It simplifies the expansion process by using a combination of coefficients, variables, and powers. As a result, it helps in deriving lengthy polynomial expressions quickly and accurately.
- The expression \((x + h)^3\) is derived from applying the binomial theorem: \((x + h)^3 = x^3 + 3x^2h + 3xh^2 + h^3\).
Limit of a Function
The limit of a function is pivotal in calculus for defining the concept of a derivative. It allows us to analyze the behavior of functions as they approach a certain point. To find the derivative of \( g(x) = x^3 + 1 \), we take the limit of the difference quotient as \( h \) approaches zero:
Thus, as shown in the step-by-step solution, when the limit is applied to the simplified expression \( 3x^2 + 3xh + h^2 \), all terms including \( h \) disappear, resulting in the final derivative of \( g'(x) = 3x^2 \). This calculation reflects the instantaneous rate of change of the original function at any point \( x \). Understanding limits is essential to grasp derivatives fully, as it connects the difference quotient to a specific slope at a point.
- \( \lim_{h \to 0} \frac{g(x + h) - g(x)}{h} \).
Thus, as shown in the step-by-step solution, when the limit is applied to the simplified expression \( 3x^2 + 3xh + h^2 \), all terms including \( h \) disappear, resulting in the final derivative of \( g'(x) = 3x^2 \). This calculation reflects the instantaneous rate of change of the original function at any point \( x \). Understanding limits is essential to grasp derivatives fully, as it connects the difference quotient to a specific slope at a point.