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Determine whether each function is a solution to the differential equation and justify your answer: $$x \frac{d y}{d x}=4 y$$ (a) \(y=x^{4}\) (b) \(y=x^{4}+3\) (c) \(y=x^{3}\) (d) \(y=7 x^{4}\)

Short Answer

Expert verified
Solutions: (a) \(y=x^4\), (d) \(y=7x^4\).

Step by step solution

01

Differentiate Each Function

(a) For \( y = x^4 \), the derivative is \( \frac{dy}{dx} = 4x^3 \).(b) For \( y = x^4 + 3 \), the derivative is \( \frac{dy}{dx} = 4x^3 \).(c) For \( y = x^3 \), the derivative is \( \frac{dy}{dx} = 3x^2 \).(d) For \( y = 7x^4 \), the derivative is \( \frac{dy}{dx} = 28x^3 \).
02

Substitute into Differential Equation

Substitute each function and its derivative back into the differential equation \( x \frac{dy}{dx} = 4y \).(a) Substitute \( \frac{dy}{dx} = 4x^3 \) and \( y = x^4 \): \[ x \cdot 4x^3 = 4(x^4) \quad \Rightarrow \quad 4x^4 = 4x^4 \] True.(b) Substitute \( \frac{dy}{dx} = 4x^3 \) and \( y = x^4 + 3 \): \[ x \cdot 4x^3 = 4(x^4 + 3) \quad \Rightarrow \quad 4x^4 = 4x^4 + 12 \] False.(c) Substitute \( \frac{dy}{dx} = 3x^2 \) and \( y = x^3 \): \[ x \cdot 3x^2 = 4(x^3) \quad \Rightarrow \quad 3x^3 = 4x^3 \] False.(d) Substitute \( \frac{dy}{dx} = 28x^3 \) and \( y = 7x^4 \): \[ x \cdot 28x^3 = 4(7x^4) \quad \Rightarrow \quad 28x^4 = 28x^4 \] True.
03

Conclude Which Functions Are Solutions

From the substitution, the functions \( y = x^4 \) and \( y = 7x^4 \) satisfy the differential equation, so they are solutions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivatives
Understanding derivatives is crucial in solving differential equations. A derivative represents how a function changes as its input changes. In simpler terms, it captures the rate of change or the slope of the function at any point along its curve.
To determine if a function solves a differential equation, we first need to find its derivative. This involves using rules of differentiation and applying them to each specific function.
For instance:
  • In part (a), the derivative of the function \( y = x^4 \) is \( \frac{dy}{dx} = 4x^3 \).
  • In part (b), the derivative of \( y = x^4 + 3 \) remains \( 4x^3 \) since the derivative of a constant, like 3, is zero.
  • For \( y = x^3 \) in part (c), the derivative is \( 3x^2 \).
  • And for \( y = 7x^4 \) in part (d), the derivative becomes \( 28x^3 \) as a result of the constant multiplier.
Once these derivatives are known, they can be substituted into the differential equation to check for consistency.
Solution Verification
Verification of a solution to a differential equation involves substituting both the function and its derivative back into the equation to see if both sides are equal. This process ensures that no mathematical errors were made during differentiation.
For the given differential equation \( x \frac{dy}{dx} = 4y \), verification requires:
  • Substituting the derived \( \frac{dy}{dx} \) and the original function \( y \).
  • Confirming that the left-hand side (LHS) equals the right-hand side (RHS) of the equation.
For example:
  • In (a) where \( y = x^4 \), substitution results in \( 4x^4 = 4x^4 \), confirming it as a solution.
  • In (b) with \( y = x^4 + 3 \), LHS becomes \( 4x^4 \) while RHS is \( 4x^4 + 12 \), leading to a discrepancy.
  • In (c), the lack of equality \( 3x^3 eq 4x^3 \) clearly denotes it's not a solution.
  • For (d), perfect equality \( 28x^4 = 28x^4 \) reaffirms it as a correct solution.
Hence, verification shows which functions satisfy the differential equation.
Mathematical Justification
Justifying the solutions mathematically involves explaining why certain functions satisfy the differential equation, while others do not. A key aspect of this justification is examining any constants present in the functions.
  • Functions that maintain proportional relationships, like \( y = x^4 \) and \( y = 7x^4 \), are solutions because their derivatives maintain the equation's balance.
  • Functions with additive constants, such as \( y = x^4 + 3 \), disrupt the balance after differentiation, resulting in an inconsistency in values when substituted back.
  • Simplicity plays a role as well. \( y = x^3 \) fails because its derivative's factor does not align with the given differential equation demands.
  • Multiple solutions often indicate the differential equation's allowance for scalar multiples, as shown with \( y = 7x^4 \).
Justification gives insights into the structural requirements of valid solutions.

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Most popular questions from this chapter

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