/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Give an example of: A linear s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Give an example of: A linear second-order differential equation representing spring motion that is critically damped.

Short Answer

Expert verified
The equation \( y'' + 4y' + 4y = 0 \) represents critically damped spring motion.

Step by step solution

01

Understanding Spring Motion

Spring motion can be described by the differential equation: \[ my'' + cy' + ky = 0 \]where \( m \) is the mass, \( c \) is the damping coefficient, \( k \) is the spring constant, and \( y \) is the displacement. For critical damping, we need to set \( c^2 = 4mk \).
02

Plugging in Values for Critical Damping

Choose values for \( m \), \( c \), and \( k \) that satisfy the critical damping condition. Let \( m = 1 \), \( k = 4 \). For critical damping, we need \( c^2 = 4mk = 16 \), so \( c = 4 \).
03

Writing the Differential Equation

Substitute the chosen values for \( m \), \( c \), and \( k \) into the differential equation: \[ y'' + 4y' + 4y = 0 \].This is a linear second-order differential equation representing critically damped spring motion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Damping
Critical damping is an important concept in the study of systems that exhibit oscillatory behavior, such as spring motion. It describes the state where a system returns to equilibrium as quickly as possible without oscillating. This is achieved by tuning the damping force perfectly to stop any oscillation without causing an overshoot.
In mathematical terms, critical damping occurs when the discriminant of the characteristic equation, derived from the second-order differential equation,
  • has precisely zero.
  • In the classic spring-mass-damper system, this condition is expressed as \( c^2 = 4mk \).
Here, \( c \) is the damping coefficient, \( m \) is the mass, and \( k \) is the spring constant. If you have a critically damped system, you'll find that it neither oscillates nor is overly slow to return to zero. This makes it perfect for systems where quick stabilization is crucial without the risk of overshoot.
Spring Motion
Spring motion is frequently modeled using differential equations to predict how a system behaves over time. In the context of a spring attached to a mass, we describe the motion by a second-order linear differential equation:
  • The basic form is \( my'' + cy' + ky = 0 \).
  • Each symbol in this equation represents a crucial component:
    • \( m \), the mass, accounts for inertia.
    • \( c \), the damping coefficient, represents friction or resistance.
    • \( k \), the spring constant, determines the stiffness of the spring.
These variables interact to dictate how the system moves, whether it oscillates or comes to a stop. Specifically, when analyzing spring motion, we often examine how quickly or slowly the system returns to rest after being disturbed by an external force. This understanding is vital for designing systems in engineering and physics that maintain stability even during dynamic conditions.
Second-Order Equations
Second-order differential equations are a type of equation especially prevalent in areas like physics and engineering. These equations typically involve functions and their derivatives up to the second degree. The general form for a second-order linear differential equation is:
  • \( ay'' + by' + cy = 0 \)
  • where \( a \), \( b \), and \( c \) are constants.
For spring motion, this translates to the equation \( my'' + cy' + ky = 0 \), where the second derivative \( y'' \) represents acceleration, the first derivative \( y' \) represents velocity, and \( y \) represents displacement.
Understanding these equations allows us to model dynamic systems that depend on these rates of change. They help in predicting behavior such as vibrations and oscillations in mechanical systems. Mastering these equations and their solutions provides critical insight into the natural world and technology alike, making them valuable tools for problem-solving in scientific disciplines.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(p\) and \(q\) are the number of individuals in two interacting populations with \(p, q>0\) satisfying the system of equations $$ \begin{array}{l} \frac{1}{p} \frac{d p}{d t}=0.01 q-0.3 \\ \frac{1}{q} \frac{d q}{d t}=0.02 p-0.2 \end{array} $$ What is the relative rate of change of \(p\) if \(q=10 ?\)

According to an article in The New York Times, \(^{24}\) pigweed has acquired resistance to the weedkiller Roundup. Let \(N\) be the number of acres, in millions. where Roundup-resistant pigweed is found. Suppose the relative growth rate, \((1 / N) d N / d t,\) was \(15 \%\) when \(N=5\) and \(14.5 \%\) when \(N=10 .\) Assuming the relative growth rate is a linear function of \(N\), write a differential equation to model \(N\) as a function of time, and predict how many acres will eventually be afflicted before the spread of Roundup-resistant pigweed halts.

Consider the system of differential equations $$ \frac{d x}{d t}=-y \quad \frac{d y}{d t}=-x $$ (a) Convert this system to a second order differential equation in \(y\) by differentiating the second equation with respect to \(t\) and substituting for \(x\) from the first equation. (b) Solve the equation you obtained for \(y\) as a function of \(t ;\) hence find \(x\) as a function of \(t\).

Solve the boundary value problem. $$y^{\prime \prime}+5 y^{\prime}+6 y=0, \quad y(-2)=0, y(2)=3$$

Explain what is wrong with the statement. The maximum rate of change occurs at \(t=25\) for a quantity \(Q\) growing according to the logistic equation $$\frac{d Q}{d t}=0.13 Q(1-0.02 Q)$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.