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True or false? Give an explanation for your answer. If \(y=f(t)\) is a particular solution to a first-order differential equation, then the general solution is \(y=\) \(f(t)+C,\) where \(C\) is an arbitrary constant.

Short Answer

Expert verified
True. The general solution is \( y = f(t) + C \).

Step by step solution

01

Understand the Problem

We need to determine whether the relationship between a particular solution and a general solution of a first-order differential equation is as stated.
02

Define a First-Order Differential Equation

A first-order differential equation is typically of the form \( \frac{dy}{dt} = g(t, y) \). It has solutions that satisfy this equation.
03

Identify a Particular Solution

A particular solution \( y = f(t) \) satisfies the differential equation \( \frac{dy}{dt} = g(t, y) \) for specific initial conditions.
04

Understand the General Solution

The general solution of a differential equation includes all possible solutions, often expressed as \( y = F(t) + C \), where \( C \) is an arbitrary constant.
05

Relate the Particular and General Solutions

If \( y = f(t) \) is a particular solution, then \( y = f(t) + C \) forms a family of solutions, representing the general solution, since adjusting \( C \) allows for any initial condition to be satisfied.
06

Conclusion

The statement is true. For a first-order differential equation, adding an arbitrary constant \( C \) to a particular solution \( f(t) \) results in the general solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Particular Solution
A particular solution is a specific solution to a differential equation that meets certain initial conditions or constraints. It exemplifies a single solution that fits within the context of the equation's requirements. When solving a first-order differential equation, like \( \frac{dy}{dt} = g(t, y) \), the particular solution \( y = f(t) \) will precisely satisfy the equation for a given initial condition, such as \( y(t_0) = y_0 \).

In simpler terms, think of the particular solution as a specific pathway or outcome predicted by the differential equation under a particular scenario. This pathway best captures the behavior described by the differential equation when given a certain starting point or condition.
General Solution
The general solution to a first-order differential equation represents a comprehensive family of solutions. Unlike a particular solution, it is not tied to a specific set of initial conditions.

The general solution typically takes the form \( y = F(t) + C \), where \( C \) is an arbitrary constant. This is crucial as it essentially describes an entire set of possible solutions covering all potential initial conditions. By varying the value of the arbitrary constant \( C \), you can shift the solution in various directions to meet any initial condition you might want.

This means that the general solution isn't just one path, but rather a multitude of paths. It provides the blueprint for finding every other possible specific solution (like a particular solution), depending on initial conditions.
Arbitrary Constant
The arbitrary constant \( C \) is a pivotal component of the general solution in differential equations. It represents the freedom we have to adjust a solution to meet a particular set of initial conditions.

When you add this constant to a particular solution \( y = f(t) \), you obtain \( y = f(t) + C \). This transformed equation provides a framework for any possible solution to the differential equation. Adjusting \( C \) allows you to tailor the solution to satisfy specific initial values, such as \( y(t_0) = y_0 \).

This flexibility is what makes \( C \) so important – it unlocks the ability to transition from a single specific solution to a family of solutions. The arbitrary constant ensures that for every possible starting condition, there is a solution represented within the general solution's framework.

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