Chapter 11: Problem 43
Give an example of: A differential equation and two different solutions to the differential equation.
Short Answer
Expert verified
The differential equation \( \frac{dy}{dx} = ky \) has solutions \( y(x) = e^{kx} \) and \( y(x) = 2e^{kx} \).
Step by step solution
01
Choose a Simple Differential Equation
Let's consider the first-order linear differential equation: \( \frac{dy}{dx} = ky \), where \( k \) is a constant. This is a common and simple equation to work with in differential equations.
02
Solve the Differential Equation
To solve \( \frac{dy}{dx} = ky \), we separate variables: \( \frac{1}{y} dy = k dx \). Integrating both sides, we get \( \ln|y| = kx + C_1 \), where \( C_1 \) is a constant of integration. Solving for \( y \), we exponentiate both sides to find \( y = Ce^{kx} \), where \( C = e^{C_1} \).
03
Find the First Solution
To find a specific solution, we choose \( C = 1 \). Thus, the first solution is \( y_1(x) = e^{kx} \). This satisfies the original differential equation since substituting it back yields the left side equal to the right side.
04
Find the Second Solution
For a second solution, choose a different constant, say \( C = 2 \). Then, the second solution is \( y_2(x) = 2e^{kx} \). Like the first solution, substituting \( y_2(x) \) back into the differential equation confirms it also satisfies the equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-order Linear Differential Equations
First-order linear differential equations are a fundamental concept in calculus and differential equations. These equations involve derivatives of the first order—meaning that the highest derivative is the first derivative—in a linear form. A basic example is \( \frac{dy}{dx} = ky \), where \( k \) is a constant. This type of equation is widely used due to its simplicity and its numerous applications in fields like engineering and physics.
A linear differential equation can generally be written in the standard form:\( \frac{dy}{dx} + P(x) y = Q(x) \), where \( P(x) \) and \( Q(x) \) are functions of \( x \). These equations can often be solved using various methods, including separation of variables, integrating factors, and more.
A linear differential equation can generally be written in the standard form:\( \frac{dy}{dx} + P(x) y = Q(x) \), where \( P(x) \) and \( Q(x) \) are functions of \( x \). These equations can often be solved using various methods, including separation of variables, integrating factors, and more.
General Solution
The general solution of a differential equation represents a family of all possible solutions, capturing every possibility allowed by the equation. For a first-order linear differential equation like \( \frac{dy}{dx} = ky \), the general solution can be written as \( y = Ce^{kx} \), where \( C \) is an arbitrary constant.
The presence of the constant \( C \) means that by altering its value, we can generate different specific solutions. This is critical because in real-world applications, the specific solution depends on initial conditions or boundary values.
In practice, once you have the general solution, unique conditions would enable you to find a particular solution to the differential equation.
The presence of the constant \( C \) means that by altering its value, we can generate different specific solutions. This is critical because in real-world applications, the specific solution depends on initial conditions or boundary values.
In practice, once you have the general solution, unique conditions would enable you to find a particular solution to the differential equation.
Particular Solution
A particular solution is a specific instance of the general solution of a differential equation that satisfies certain initial or boundary conditions. Continuing with our example equation \( \frac{dy}{dx} = ky \), we found the general solution as \( y = Ce^{kx} \). By choosing different values for \( C \), we derive various particular solutions.
For instance, setting \( C = 1 \) we get the particular solution \( y_1(x) = e^{kx} \), and similarly, or if \( C = 2 \), we derive \( y_2(x) = 2e^{kx} \). These satisfy the differential equation and demonstrate that changing the constant results in a set of unique solutions all fitting within the framework of the general solution.
For instance, setting \( C = 1 \) we get the particular solution \( y_1(x) = e^{kx} \), and similarly, or if \( C = 2 \), we derive \( y_2(x) = 2e^{kx} \). These satisfy the differential equation and demonstrate that changing the constant results in a set of unique solutions all fitting within the framework of the general solution.
Separation of Variables
Separation of variables is a powerful and straightforward method for solving first-order differential equations. It works best when an equation can be written in a format where variables can be separated on different sides of the equation. In our example \( \frac{dy}{dx} = ky \), this can be transformed into \( \frac{1}{y} dy = k dx \), effectively segregating the variables.
Once the equation is separated, we integrate both sides to obtain the solution. This culminates in a relationship like \( \ln|y| = kx + C_1 \). Solving for \( y \) gives \( y = Ce^{kx} \), which is the general solution.
This technique is particularly useful for equations where direct integration is feasible, making it a go-to method for solving many types of differential equations.
Once the equation is separated, we integrate both sides to obtain the solution. This culminates in a relationship like \( \ln|y| = kx + C_1 \). Solving for \( y \) gives \( y = Ce^{kx} \), which is the general solution.
This technique is particularly useful for equations where direct integration is feasible, making it a go-to method for solving many types of differential equations.