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A rumor spreads among a group of 400 people. The number of people, \(\bar{N}(t),\) who have heard the rumor by time \(t\) in hours since the rumor started is approximated by $$N(t)=\frac{400}{1+399 e^{-0.4 t}}$$ (a) Find \(N(0)\) and interpret it. (b) How many people will have heard the rumor after 2 hours? After 10 hours? (c) Graph \(N(t)\) (d) Approximately how long will it take until half the people have heard the rumor? 399 people? (e) When is the rumor spreading fastest?

Short Answer

Expert verified
(a) 1 person at \(t=0\). (b) 2 at 2 hours, 48 at 10 hours. (d) 9.21 hours for 200 people, 27.65 hours for 399. (e) Fastest at about 9.21 hours.

Step by step solution

01

Find Initial Value N(0)

To find the initial value, substitute the given time, \(t = 0\), into the function: \[ N(0) = \frac{400}{1 + 399 e^{-0.4 \times 0}} = \frac{400}{1 + 399 \times 1} = \frac{400}{400} = 1. \] Interpretation: At the start (\(t = 0\)), only 1 person has heard the rumor.
02

Calculate N(t) for t = 2 and t = 10 hours

Substitute \(t = 2\) into the function to find \(N(2)\): \[ N(2) = \frac{400}{1 + 399 e^{-0.8}} \approx \frac{400}{1 + 399 \times 0.4493} \approx \frac{400}{1 + 179.46} \approx \frac{400}{180.46} \approx 2.217. \] For \(t = 10\), substitute into the function to find \(N(10)\): \[ N(10) = \frac{400}{1 + 399 e^{-4}} \approx \frac{400}{1 + 399 \times 0.0183} \approx \frac{400}{1 + 7.31} \approx \frac{400}{8.31} \approx 48.14. \] Interpretation: After 2 hours, about 2 people have heard the rumor; after 10 hours, about 48 people have heard it.
03

Graph N(t)

Graph the function \(N(t) = \frac{400}{1 + 399 e^{-0.4t}}\). Start by plotting the calculated points from the previous steps: \(N(0) = 1\), \(N(2) \approx 2.2\), and \(N(10) \approx 48.1\). Continue plotting values for other \(t\) values (for example, \(t = 5\), \(t = 15\), etc.), and draw a smooth curve through the points to show how \(N(t)\) increases over time.
04

Time to Spread to Half and 399 People

Find \(t\) where half of the 400 people, i.e., \(N(t) = 200\): \[ \frac{400}{1 + 399 e^{-0.4t}} = 200. \]Solving, \[ 1 + 399 e^{-0.4t} = 2, \]\[ 399 e^{-0.4t} = 1, \]\[ e^{-0.4t} = \frac{1}{399}, \]\[ -0.4t = \ln\left(\frac{1}{399}\right), \]\[ t = -\frac{1}{0.4} \ln\left(\frac{1}{399}\right) \approx 9.21. \]For \(N(t) = 399\): \[ \frac{400}{1 + 399 e^{-0.4t}} = 399, \]\[ 1 + 399 e^{-0.4t} = \frac{400}{399}, \]\[ 399 e^{-0.4t} = \frac{1}{399}, \]\[ e^{-0.4t} = \frac{1}{159201}, \]\[ t = -\frac{1}{0.4} \ln\left(\frac{1}{159201}\right) \approx 27.65. \]Interpretation: Half of the people hear it after about 9.21 hours; 399 people hear it after about 27.65 hours.
05

Determine Fastest Spread

The rumor spreads fastest at the point of inflection of the curve represented by \(N(t)\). This is where the second derivative of \(N(t)\) changes sign. Without calculus, the inflection point is typically around when \(N(t)\) is 200, which is when \(t \approx 9.21\) (as previously found).
06

Conclusion and Summary

At \(t = 0\), 1 person heard the rumor. After 2 and 10 hours, approximately 2 and 48 people heard it respectively. Half of the group hears the rumor after about 9.21 hours. 399 people hear it by around 27.65 hours, and the fastest spread is around the 9.21-hour mark.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
Differential equations are mathematical tools used to represent relationships involving rates of change. They are like the equations of motion for dynamic systems, capturing how a quantity changes over time. In the example of the rumor spreading through a group of 400 people, a differential equation can help us understand the rate at which more people become aware of the rumor.

In this case, the function given is for the number of people, \( N(t) \), who have heard the rumor by time \( t \). The function is a type of differential equation solution known as a logistic function, which is often used to model population growth or other similar processes. This specific form shows exponential growth initially, which then slows down as it approaches a maximum, governed by the parameters of the function.

Here's what's happening mathematically:
  • At \( t = 0 \), very few people have heard the rumor, so the function starts at a low value.
  • The rate at which people hear the rumor is highest when around half the group has heard it; this is due to social interactions becoming more frequent.
  • As more people hear the rumor, the growth slows, approaching a saturation point where nearly everyone has heard it.
By understanding differential equations, we can better grasp how such growth models predict and explain real-world phenomena.
Mathematical Modeling
Mathematical modeling is a method used to represent real-world scenarios with mathematical formulas and equations. This process helps us analyze and predict behaviors or outcomes based on certain input conditions. In the exercise, mathematical modeling applies to how a rumor spreads among a group of people.

The function provided, \[ N(t) = \frac{400}{1 + 399 e^{-0.4t}} \], is a classic example of a logistic growth model. Let's break down why this model is helpful:
  • **Initial Conditions:** When \( t = 0 \), only one person knows about the rumor, which is reflected mathematically as the starting value by setting \( e^{0} = 1 \).
  • **Carrying Capacity:** The formula has a maximum value (or carrying capacity) of 400, meaning it models the maximum number of people who will eventually know the rumor.
  • **Growth Rate:** The rate parameter \( 0.4 \) determines how quickly the rumor spreads among people.
Models like this are crucial as they simplify complex systems into understandable and predictable structures, which can then inform future decisions or direct further investigations. In this exercise, applying the logistic model helps predict how the rumor will spread over time and informs us about crucial time points like when half or nearly all the people will be aware of the rumor.
Inflection Points
Inflection points in mathematical terms are points on a curve where the curve changes concavity. In other words, it's where the curve goes from "curving up" to "curving down" or vice versa. This change is significant because it's often where the growth changes from accelerating to decelerating, giving a clue about the behavior of the scenario being modeled.

In the context of the rumor model, the inflection point is where the rumor spreads fastest. In logistic growth models, this typically happens when about half of the maximum population has been reached. Mathematically, it signifies the point at which the second derivative of the function changes sign. While finding this point typically requires calculus, intuitively it happens around \( t \approx 9.21 \) hours in the rumor spreading scenario. At this time, the rumor's spreading rate is at its peak.

The importance of understanding inflection points:
  • **Optimal Spreading:** Knowing where the inflection point is can help us understand the period of maximum change and strategize interventions or optimizations accordingly.
  • **Predictive Insight:** It provides insight into when the growth rate will start to decline, allowing predictions about the remaining time to reach full saturation.
Understanding inflection points helps in analyzing the dynamics of processes modeled by curves, providing essential insights into the growth patterns, such as those seen in the rumor-spreading model.

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