/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 In Exercises \(2-7\), which diff... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises \(2-7\), which differential equation, ( 1 )-(VI), has the function as a solution? I. \(y^{\prime}=-2 x y\) II. \(y^{\prime}=-x y\) III. \(y^{\prime}=x y\) IV. \(y^{\prime}=-x^{2} y\) V. \(y^{\prime}=x^{-3} y\) VI. \(y^{\prime}=2 x y\) $$y=e^{-0.5 x^{2}}$$

Short Answer

Expert verified
The function is a solution to differential equation (II): \( y' = -x y \).

Step by step solution

01

Determine the derivative of the function

Given the function is \( y = e^{-0.5 x^2} \). To find the differential equation it satisfies, first determine the derivative \( y' \). Using the chain rule, the derivative of \( y \) is given by: \( y' = \frac{d}{dx}(e^{-0.5 x^2}) = -x e^{-0.5 x^2} \).
02

Compare the derivative with the given differential equations

We found \( y' = -x e^{-0.5 x^2}\). Now compare this expression with each given differential equation. Substitute \( y = e^{-0.5 x^2} \) into each equation to verify which matches: 1. I: \( y' = -2xy \Rightarrow -2x(e^{-0.5 x^2}) eq -xe^{-0.5 x^2}\) 2. II: \( y' = -xy \Rightarrow -x(e^{-0.5 x^2}) = -xe^{-0.5 x^2}\), which matches. Other equations do not match based on similar substitutions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
A derivative measures how a function changes as its input changes. For a given function, its derivative is another function that gives the rate of change of the original function with respect to its variable. For instance, if we have a function representing position over time, the derivative of that function would give us the velocity.In our example, we start with the function given by \( y = e^{-0.5 x^2} \). To find the derivative, we need to determine how \( y \) changes with respect to \( x \). This derivative will help us identify the differential equation that the function satisfies. We found that \( y' = -x e^{-0.5 x^2} \). This means that the rate of change of \( y \) with respect to \( x \) is proportional to \( -x \) times the original function itself.
Chain Rule
The Chain Rule is a fundamental technique in calculus. It allows us to differentiate composite functions, where one function is inside another. This rule essentially provides a way of computing the derivative of such nested functions.We use the chain rule when we differentiate \( y = e^{-0.5 x^2} \). The inside function is \(-0.5x^2\), and the outside function is the exponential \( e^u \). The chain rule says that to differentiate \( e^{-0.5 x^2} \), we take the derivative of the outside function \( e^u \), which is itself, and multiply it by the derivative of the inside function \(-0.5x^2\). This yields the derivative \( y' = -x e^{-0.5 x^2} \), showing how both components contribute to the rate of change.
Solution Verification
Verifying the solution of a differential equation involves checking if the derivative we compute matches with one of the given equations. We need to ensure the function satisfies the equation when substituted.For our function \( y = e^{-0.5 x^2} \), we calculated \( y' = -x e^{-0.5 x^2} \). To verify as a solution, we substitute this into the list of given differential equations and compare the results. When substituted into II, \( y' = -xy \), the left side precisely equals the right side: \(-x (e^{-0.5 x^2}) = -xe^{-0.5 x^2}\). Thus, we've verified that this differential equation is the correct one for the function given the calculated derivative.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.