/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 Explain what is wrong with the s... [FREE SOLUTION] | 91Ó°ÊÓ

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Explain what is wrong with the statement. If \(f(x)=\frac{x^{2}-1}{x+1}\) and \(g(x)=x-1,\) then \(f=g\)

Short Answer

Expert verified
The functions are not the same because \( f(x) \) has a domain restriction at \( x = -1 \), while \( g(x) \) does not.

Step by step solution

01

Understanding the Functions

The function \( f(x) = \frac{x^{2} - 1}{x+1} \) is defined as a rational function. Notice that the numerator \( x^2 - 1 \) can be factored into \( (x-1)(x+1) \). Meanwhile, the function \( g(x) = x - 1 \) is a linear function.
02

Simplifying the Rational Function

Simplify \( f(x) \) by factoring the numerator: \( f(x) = \frac{(x-1)(x+1)}{x+1} \). When \( x + 1 eq 0 \), the \( (x+1) \) terms in the numerator and denominator cancel out, leading to \( f(x) = x - 1 \).
03

Identifying Domain Restrictions

The simplification step is valid only where the original function \( f(x) \) is defined. Since \( f(x) = \frac{(x-1)(x+1)}{x+1} \), the denominator cannot be zero, so \( x eq -1 \). Therefore, \( f(x) = x - 1 \), for all \( x eq -1 \).
04

Comparing the Functions

While \( f(x) \) simplifies to \( x - 1 \) for \( x eq -1 \), the function \( g(x) = x - 1 \) is defined for all real numbers. Since \( f(x) \) has a restriction at \( x = -1 \), the functions are not identical on the same domain.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Simplification
Simplifying functions can often help reveal their underlying structure and make comparisons easier. Consider the function \( f(x) = \frac{x^{2} - 1}{x+1} \). At first glance, this looks complicated, but simplification can help. Here, the expression \( x^{2} - 1 \) is a difference of squares, which simplifies to \((x - 1)(x + 1)\). By substituting this back into the function, you get:
  • \( f(x) = \frac{(x-1)(x+1)}{x+1} \)
This simplification allows the \( (x+1) \) terms to cancel out, as long as \( x + 1 \) is not zero. Thus, this rational function simplifies to \( f(x) = x - 1 \) under certain conditions. Simplifying functions enables us to better compare and understand them, revealing any hidden relationships or characteristics.
Domain Restrictions
A crucial aspect of working with rational functions is understanding their domain. The domain is all possible x-values for which the function is defined. For the function \( f(x) = \frac{(x-1)(x+1)}{x+1} \), a problem occurs when the denominator is zero.
  • This happens at \( x = -1 \), causing the function to be undefined at this point.
Even after simplification, this restriction must be remembered. When the function simplifies to \( f(x) = x - 1 \), it appears valid for all x-values, but actually isn’t defined at \( x = -1 \).
Ignoring domain restrictions can lead to incorrect conclusions, as observed here, where it was falsely concluded that \( f = g \). While both functions simplify to \( x - 1 \), the original domain conditions of \( f \) lead to a restriction that prevents the functions from being equal everywhere.
Linear Functions
Linear functions are some of the simplest types of functions and are defined by the equation \( y = mx + b \). The function \( g(x) = x - 1 \) is an example of a linear function, where the slope \( m \) is 1, and the y-intercept \( b \) is -1. Linear functions create straight lines on a graph.
  • They possess a constant rate of change, which makes their behavior predictable and easy to analyze.
When comparing \( g(x) = x - 1 \) with \( f(x) \), remember that \( g(x) \) has a domain that is all real numbers. There are no restrictions, unlike \( f(x) \) which has a gap at \( x = -1 \).
Linear functions like \( g(x) = x - 1 \) highlight the importance of keeping track of domain differences, especially when simplifying more complex rational functions like \( f(x) \).
This understanding aids in discerning the differences between functions that appear identical but actually have varying properties.

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