/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Find an equation for the line th... [FREE SOLUTION] | 91Ó°ÊÓ

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Find an equation for the line that passes through the given points. (0,2) and (2,3)

Short Answer

Expert verified
The equation of the line is \(y = \frac{1}{2}x + 2\).

Step by step solution

01

Determine the slope of the line (m)

The slope of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) can be calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]For the points (0, 2) and (2, 3), substitute the values into the formula:\[ m = \frac{3 - 2}{2 - 0} = \frac{1}{2} \]Thus, the slope \(m\) is \(\frac{1}{2}\).
02

Use point-slope form to find the equation

Use the point-slope form of the equation of a line, which is:\[ y - y_1 = m(x - x_1) \]Here, the slope \(m = \frac{1}{2}\) and you can use one of the points, let's use (0, 2). Substitute these values into the formula:\[ y - 2 = \frac{1}{2}(x - 0) \]This simplifies the equation to:\[ y - 2 = \frac{1}{2}x \]
03

Convert to slope-intercept form

Rewrite the equation to the slope-intercept form, which is \(y = mx + b\). Starting from the equation:\[ y - 2 = \frac{1}{2}x \]Add 2 to both sides:\[ y = \frac{1}{2}x + 2 \]This equation \(y = \frac{1}{2}x + 2\) is the slope-intercept form of the line that passes through the points (0, 2) and (2, 3).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope
The slope of a line is a measure of its steepness and direction. When examining a line on a coordinate plane, the slope represents how much the line rises or falls vertically for each unit it moves horizontally. It's vital in determining not just the angle of a line, but also how two lines interact—whether they are parallel, intersect, or perpendicular.

The formula for the slope, represented as 'm', is given by the difference in y-coordinates divided by the difference in x-coordinates of two distinct points on the line:
\[m = \frac{y_2 - y_1}{x_2 - x_1}\]
From this, you can quickly see that:
  • A positive slope means the line rises as it moves from left to right.
  • A negative slope indicates the line falls.
  • A slope of zero results in a horizontal line.
  • An undefined slope corresponds to a vertical line.
In our current exercise, the slope calculated for the points (0, 2) and (2, 3) is \(\frac{1}{2}\), meaning for every two units the line moves to the right, it rises by one unit.
Point-Slope Form
The point-slope form of a line's equation is a useful format when you know the slope of a line and one specific point through which the line passes. It's particularly handy for quickly forming the equation of a line, especially in situations where these two data points are the most direct information available.

The point-slope form is structured as follows:
\[y - y_1 = m(x - x_1)\]
Where:
  • \(m\) is the slope of the line.
  • \((x_1, y_1)\) is a point on the line.
This form gives you a direct way to substitute known values of the slope and a specific point to find the equation of the line. In our exercise, given the slope \(\frac{1}{2}\) and the point (0, 2), substituting into the point-slope form yields:
\[y - 2 = \frac{1}{2}(x - 0)\]
Ultimately simplifying to \[y - 2 = \frac{1}{2}x\]. This expression illustrates how quickly and efficiently a point and a slope can construct the framework of a line's equation.
Slope-Intercept Form
The slope-intercept form is perhaps the most familiar form of a linear equation. It provides a direct way to identify both the slope of the line and the y-intercept at a glance, making it invaluable for graphing and quick analysis.

This form of a linear equation is structured as:
  • \(y = mx + b\)
Where:
  • \(m\) denotes the slope.
  • \(b\) represents the y-intercept, which is the value where the line crosses the y-axis.
In the exercise, the equation was transformed from the point-slope form to the slope-intercept form by solving for y and simplifying the terms. After starting with:
\[y - 2 = \frac{1}{2}x\]
Adding 2 to both sides provides:
\[y = \frac{1}{2}x + 2\]
This results in a clear depiction of the line's slope \(\frac{1}{2}\) and its y-intercept at (0, 2). This form makes it easy to predict and plot the line's behavior and understand its interaction with other lines on a graph.

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