/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Use a graph to estimate the limi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use a graph to estimate the limit. Use radians unless degrees are indicated by \(\theta^{\circ} .\) $$\lim _{\theta \rightarrow 0} \frac{\sin (2 \theta)}{\theta}$$

Short Answer

Expert verified
The limit is approximately 2.

Step by step solution

01

Plot the Function

First, we need to create a graph of the function \[ y = \frac{\sin(2\theta)}{\theta} \] near \( \theta = 0 \). Make sure your graph is focused around the origin to observe the behavior as \( \theta \) approaches 0.
02

Observe the Behavior Near Zero

Examine the graph and look at the values the function takes as \( \theta \) approaches 0. The function should approach a constant value as \( \theta \) gets very close to zero.
03

Estimate the Limit from the Graph

By observing the graph, estimate the value the function tends towards at \( \theta = 0 \). If the graph is plotted accurately, you should see that as \( \theta \rightarrow 0 \), \[ \frac{\sin(2\theta)}{\theta} \] approaches 2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphical Analysis
Graphical analysis is a powerful tool in calculus, especially when evaluating limits. By graphing a function, we can visually explore its behavior as the variable approaches a particular value. For example, consider the function \[ y = \frac{\sin(2\theta)}{\theta} \]focused around zero. When you plot this, make sure the graph is centered near the origin to capture the changes that happen as \( \theta \) gets closer to zero.

Observing the plot, check how the function behaves around \( \theta = 0 \). This function should appear to level out, indicating it nears a constant value as \( \theta \) approaches zero. This visual analysis gives an intuitive and immediate way to estimate what to expect for the limit.

A correctly plotted graph reveals the function smoothing out to approach the expected limit. It's like finding clues about a destination by observing the signs along the road. Graphs offer a visible tool to gauge behavior where traditional methods might become complex.
Sine Function
The sine function, \( \sin(\theta) \), is a fundamental component in trigonometry and calculus. It describes wave-like patterns occurring in nature. With periodicity of \( 2\pi \), it repeats its shape over intervals of \( 2\pi \) radians. This function ranges from -1 to 1 and smoothly oscillates as \( \theta \) varies.
  • Periodicity: Repeats every \( 2\pi \) radians.
  • Amplitude: Maximum and minimum values are 1 and -1, respectively.
  • Behavior around zero: Near \( \theta = 0 \), \( \sin(\theta) \) is approximately equal to \( \theta \) itself, which is useful for estimations.

When analyzing functions such as \( \frac{\sin(2\theta)}{\theta} \), understanding how \( \sin(2\theta) \) behaves is crucial.
The doubling of angle within the sine function, shown as \( \sin(2\theta) \), affects its frequency, reducing its period to \( \pi \), resulting in twice as many cycles for any span. This attribute changes the approach when calculating limits but remains elegant in its symmetry.
Limit Evaluation
Limit evaluation is a fundamental concept in calculus; it helps understand the behavior of a function as its variables approach a certain point. It’s like predicting the destination of a journey before you arrive.
For the expression \( \lim _{\theta \rightarrow 0} \frac{\sin(2\theta)}{\theta} \), evaluating this limit requires recognizing the relationship between \( \theta \) and \( \sin(2\theta) \). Since near zero, \( \sin(x) \approx x \), substituting \( 2\theta \) for \( x \), approximates \( \sin(2\theta) \approx 2\theta \). This simplifies to \[ \frac{\sin(2\theta)}{\theta} \approx \frac{2\theta}{\theta} = 2 \]
Hence, as \( \theta \rightarrow 0 \), the ratio approaches 2. Even without perfect graphs or calculations, understanding sine’s approximation near zero facilitates finding such limits.
  • Identify patterns: Notice properties of functions involved.
  • Simplify expressions: Use known function behavior toreduce complexity.
  • Verify by graph: Visualize to confirm analytical estimations.
Thus, limit evaluation characterizes how a function 'settles' at a boundary, helping delve deeper into calculus's rich landscape.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Are the statements true or false? Give an explanation for your answer. $$\cos |x|=\cos x \text { for }-2 \pi

Are the statements true or false? Give an explanation for your answer. The function \(f(\theta)=\tan (\theta-\pi / 2)\) is not defined at \(\theta=\pi / 2,3 \pi / 2,5 \pi / 2 \ldots\)

Cyanide is used in solution to isolate gold in a mine. \(^{49}\) This may result in contaminated groundwater near the mine, requiring the poison be removed, as in the following table, where \(t\) is in years since 2012. (a) Find an exponential model for \(c(t),\) the concentration, in parts per million, of cyanide in the groundwater. (b) Use the model in part (a) to find the number of years it takes for the cyanide concentration to fall to 10 ppm. (c) The filtering process removing the cyanide is sped up so that the new model is \(D(t)=c(2 t) .\) Find \(D(t).\) (d) If the cyanide removal was started three years earlier, but run at the speed of part (a), find a new model, \(E(t).\) $$\begin{array}{c|c|c|c} \hline t \text { (years) } & 0 & 1 & 2 \\ \hline c(t)(\mathrm{ppm}) & 25.0 & 21.8 & 19.01 \\ \hline \end{array}$$

For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, \(d(t),\) in meters, where \(t\) is measured in hours since midnight, is $$ d(t)=5+4.6 \sin (0.5 t) $$ (a) What is the period of the tides in hours? (b) If the boat leaves the bay at midday, what is the latest time it can return before the water becomes too shallow?

Explain what is wrong with the statement. $$\ln (A+B)=\ln A+\ln B.$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.