Chapter 9: Problem 56
For \(1 \leq n \leq 10,\) find a formula for \(p_{n},\) the payment in year \(n\) on a loan of \(\$ 100,000 .\) Interest is \(5 \%\) per year, compounded annually, and payments are made at the end of each year for ten years. Each payment is \(\$ 10,000\) plus the interest on the amount of money outstanding.
Short Answer
Step by step solution
Understand the Loan Conditions
Determine the Formula for Annual Payment
Calculate the Remaining Balance Recursively
Calculate Each Year's Payment
Generalize the Formula for Any Year
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Compound Interest
- Interest on the remaining balance is calculated annually.
- The interest rate for this problem is compounded annually at 5%.
- Compound interest ensures that each year, you pay more on interest compared to the linear calculation of simple interest.
Recursive Formula
- The initial balance in year 1 is \(100,000 - 10,000 = 90,000\).
- The remaining balance for any year \(n\) is previous year's remaining balance minus \(10,000\).
- This recursive pattern makes it easier to calculate each year's payment sequentially.
Fixed Principal Payment
- Every payment includes this principal repayment, reducing the loan balance.
- The remaining interest is adjusted annually based on the reduced balance from the fixed principal payment.
- In our formula, it simplifies to a deduction of $10,000 from the balance each year.
Annual Payments
- Each annual payment consists of \)10,000 and interest from the previous year's outstanding balance.
- The pattern of payments changes as the principal reduces consistently, impacting the interest paid each year.
- The formula for annual payment \(p_n = 10,000 + 0.05 \times (100,000 - 10,000 \times n)\) provides a straightforward calculation for each year.