Chapter 9: Problem 28
Use the alternating series test to show that the series in converge. $$\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{e^{n}}$$
Short Answer
Expert verified
The series converges by the alternating series test.
Step by step solution
01
Identify the Sequence
First, identify the sequence you will analyze: \( a_n = \frac{1}{e^n} \). This is the positive part of the series \( \sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{e^n} \).
02
Check for Alternation
The given series is alternating because it has a \((-1)^{n-1}\) term, which causes the sign of each term to alternate.
03
Verify that the Sequence is Decreasing
To apply the alternating series test, ensure that \( a_n \) is decreasing. Show that \( a_{n+1} = \frac{1}{e^{n+1}} < \frac{1}{e^n} = a_n \), which is true since \( e^n < e^{n+1} \). Thus, the sequence is decreasing.
04
Check for the Limit Condition
Check that \( \lim_{n \to \infty} a_n = 0 \). Since \( a_n = \frac{1}{e^n} \), we have \( \lim_{n \to \infty} \frac{1}{e^n} = 0 \).
05
Conclude Convergence
Since both conditions of the alternating series test are fulfilled (\(a_n\) is decreasing and \(\lim_{n \to \infty} a_n = 0\)), the series \( \sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{e^n} \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Series Convergence
Understanding series convergence is essential when dealing with infinite series. In general, a series converges when the partial sums approach a specific value as the number of terms increases. For alternating series—series in which the terms alternate in sign—convergence can be assessed using specific tests. The Alternating Series Test is a popular method that is particularly effective for sequences of the form \(\sum (-1)^{n} b_n\), where \(b_n\) are positive sequences.There are two primary conditions to show convergence of alternating series:
- The sequence \(b_n\), excluding the alternating signs, must be decreasing.
- The limit of \(b_n\) as \(n\) approaches infinity must be zero.
Decreasing Sequence
A decreasing sequence is one where each term is less than or equal to the preceding term. In mathematical terms, a sequence \(a_n\) is decreasing if \(a_{n+1} \leq a_n\) for all \(n\). This is crucial for the Alternating Series Test.In the given problem, we identified the sequence \(a_n = \frac{1}{e^n}\). To demonstrate that this sequence is decreasing, we compare consecutive terms.Let's observe:
- \(a_{n+1} = \frac{1}{e^{n+1}}\)
- \(a_n = \frac{1}{e^n}\)
Limit Condition
The limit condition is a critical part of using the Alternating Series Test. It ensures that as the sequence progresses, its terms tend closer and closer to zero. Specifically, for a series to converge via this test, the sequence \(a_n\) must satisfy:\[ \lim_{n \to \infty} a_n = 0 \]In our example, we have:
- \(a_n = \frac{1}{e^n}\)