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91Ó°ÊÓ

Match formulas (a)-(e) with descriptions (I)-(V) of the behavior of the sequence as \(n \rightarrow \infty\) (a) \(s_{n}=n(n+1)-1\) (b) \(s_{n}=1 /(n+1)\) (c) \(s_{n}=1-n^{2}\) (d) \(s_{n}=\cos (1 / n)\) (e) \(s_{n}=(\sin n) / n\) (1) Diverges to \(-\infty\) (II) Diverges to \(+\infty\) (111) Converges to 0 through positive numbers (IV) Converges to 1 (V) Converges to 0 through positive and negative numbers

Short Answer

Expert verified
(a)-(II), (b)-(III), (c)-(I), (d)-(IV), (e)-(V)

Step by step solution

01

Analyze sequence (a)

For \( s_{n} = n(n+1) - 1 \), expand it to \( s_{n} = n^2 + n - 1 \). As \( n \rightarrow \infty \), the \( n^2 \) term dominates, hence \( s_{n} \) behaves like \( n^2 \) and diverges to \(+\infty\). So, it matches with description (II).
02

Analyze sequence (b)

For \( s_{n} = \frac{1}{n+1} \), as \( n \rightarrow \infty \), the value of \( \frac{1}{n+1} \) approaches 0. Since numerator is positive and denominator increases, \( s_{n} \) converges to 0 through positive numbers. It matches description (III).
03

Analyze sequence (c)

For \( s_{n} = 1 - n^2 \), as \( n \rightarrow \infty \), \( n^2 \) dominates and \( s_{n} \) becomes large negative. Thus, \( s_{n} \) diverges to \(-\infty\). It matches description (I).
04

Analyze sequence (d)

For \( s_{n} = \cos (\frac{1}{n}) \), as \( n \rightarrow \infty \), \( \frac{1}{n} \rightarrow 0 \) making \( \cos(\frac{1}{n}) \) approach \( \cos(0) = 1 \). Therefore, \( s_{n} \) converges to 1. It matches description (IV).
05

Analyze sequence (e)

For \( s_{n} = \frac{\sin n}{n} \), as \( n \rightarrow \infty \), sine alternates between -1 and 1, but \( n \) in the denominator grows indefinitely. This means \( s_{n} \) approaches 0 through both positive and negative values. It matches description (V).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence
Convergence in sequences refers to a sequence approaching a specific value as the value of the index, often referred to as \( n \), increases indefinitely. As \( n \) becomes very large, the terms in a convergent sequence become closer and closer to a particular value. This concept is vital in understanding how infinite processes can have finite limits.

A classic example from above is sequence (b): \( s_{n} = \frac{1}{n+1} \). Here, as \( n \rightarrow \infty \), the fraction \( \frac{1}{n+1} \) becomes exceedingly small, ultimately closing in on 0. This is a perfect illustration of a sequence converging to 0 as \( n \rightarrow \infty \). Since the terms are always positive due to the nature of the fraction, this is specifically described as converging to 0 through positive numbers. This highlights how convergence is not just about reaching a number but rather how it approaches it.
  • Steadiness towards a single point is key to the concept.
  • It can happen with real-valued sequences as seen in sequence \( s_{n} = \frac{1}{n+1} \).
  • Look for patterns as \( n \) increases to identify such behavior.
Divergence to Infinity
Divergence, particularly to infinity, implies that as \( n \) grows larger, the sequence doesn't settle to a finite limit but grows without bound. Essentially, instead of converging to a specific value, it perpetually escapes towards infinity or negative infinity. This is often observed when the terms increase in magnitude without restriction.

Sequence (a), \( s_{n} = n(n+1) - 1 \), illustrates divergence to infinity. Expanding to \( s_{n} = n^2 + n - 1 \), we see that the \( n^2 \) term clearly dominates as \( n \rightarrow \infty \). The sequence effectively mirrors the growth of \( n^2 \), showcasing divergence to positive infinity (\(+\infty\)).
  • Look for terms that perpetually increase as \( n \) grows to identify divergence.
  • Dominance of higher degree terms, like \( n^2 \), often hints at divergence to infinity.

Sequence (c) \( s_{n} = 1 - n^2 \) diverges to negative infinity (\(-\infty\)) since the \(-n^2\) term increases in magnitude negatively, showcasing how sequences can have divergent behavior in opposite directions.
Behavior as n approaches infinity
Understanding the behavior of a sequence as \( n \rightarrow \infty \) is crucial to determine whether it converges, diverges, or oscillates. This behavior dictates the long-term fate of a sequence, whether it settles towards a number, escapes beyond bounds, or behaves erratically.

Sequence (d), \( s_{n} = \cos \left( \frac{1}{n} \right) \), offers a neat example of behavior as \( n \rightarrow \infty \). As \( n \) increases, \( \frac{1}{n} \) approaches 0, leading the cosine function to converge to \( \cos(0) = 1 \). This illustrates the approach of a sequence towards a finite limit, revealing stable behavior.
  • Key factor to watch is the term's change as \( n \) increases.
  • Some sequences will converge smoothly, while others, like \( \sin(n)/n \) in sequence (e), fluctuate because of the sine’s inherent oscillatory nature.
  • Understanding helps in predicting the limit or potential for infinity.

Sequence (e) shows how the sine function, due to its oscillatory nature, results in a sequence that converges to 0 but oscillates between positive and negative values, explaining how functions intertwine through their trigonometric behavior as \( n \rightarrow \infty \).

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