/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 Show the two integrals are equal... [FREE SOLUTION] | 91Ó°ÊÓ

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Show the two integrals are equal using a substitution. $$\int_{0}^{\pi / 3} 3 \sin ^{2}(3 x) d x=\int_{0}^{\pi} \sin ^{2}(y) d y$$

Short Answer

Expert verified
The integrals are equal by substitution: \( u = 3x \).

Step by step solution

01

Identify the Integrals

We have two integrals that we need to show are equal. The first integral is \( \int_{0}^{\pi / 3} 3 \sin ^{2}(3 x) \, dx \), and the second one is \( \int_{0}^{\pi} \sin ^{2}(y) \, dy \). We will use substitution to demonstrate their equality.
02

Choose Appropriate Substitution

For the first integral \( \int_{0}^{\pi / 3} 3 \sin ^{2}(3 x) \, dx \), perform the substitution \( u = 3x \). This implies \( du = 3 \, dx \), or \( dx = \frac{du}{3} \). Also, recalculate limits of integration: when \( x = 0, u = 0 \), and when \( x = \frac{\pi}{3}, u = \pi \).
03

Convert the Integral Using Substitution

Substitute in the integral using \( u = 3x \) and \( dx = \frac{du}{3} \). The integral becomes:\[ \int_{0}^{\pi} 3 \sin^2(u) \cdot \frac{1}{3} \, du = \int_{0}^{\pi} \sin^2(u) \, du \].
04

Recognize the Standard Form

Notice that the transformed integral from Step 3, \( \int_{0}^{\pi} \sin^2(u) \, du \), is identical to the second integral \( \int_{0}^{\pi} \sin^2(y) \, dy \). Thus, the original integrals are shown to be equal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integrals
Definite integrals are a type of integral that calculates the area under a curve within a specific interval. Unlike indefinite integrals, which provide a general antiderivative, definite integrals have set upper and lower limits. These limits are often referred to as the boundaries of integration. When evaluating a definite integral, the result is a number that represents the accumulated quantity, such as area or total change, between the specified limits.

The notation for definite integrals uses a function and its limits of integration, like so:
  • The expression \( \int_{a}^{b} f(x) \, dx \) where \( a \) and \( b \) are the lower and upper limits, respectively.
  • This integral computes the total area under the curve \( f(x) \) from \( x = a \) to \( x = b \).
To solve a definite integral, you usually find an antiderivative first and then apply the Fundamental Theorem of Calculus. The theorem states that if \( F \) is an antiderivative of \( f \), then the integral can be evaluated as \( F(b) - F(a) \), where \( F(b) \) and \( F(a) \) are the values of the antiderivative at the bounds.
Trigonometric Functions
Trigonometric functions are functions related to angles commonly found in mathematics, particularly when dealing with triangles and waves. Common trigonometric functions include sine, cosine, and tangent.

In the context of integrals,
  • Sine and cosine functions appear frequently, often as part of periodic or oscillating systems.
  • Their integrals can be used to find amplitudes and transformations of waves.
For instance, in our exercise, the integral \( \int \sin^2(x) \, dx \) emerges from the need to calculate areas involving a sinusoidal wave.

A key property of trigonometric functions, especially sine and cosine, is their periodic nature. Over a complete cycle, such as from 0 to \(2\pi\) for sine and cosine, these functions repeat their values. When finding definite integrals involving trigonometric functions, understanding their periodicity can simplify the calculation by showing symmetries or repetitions.
Limits of Integration
Limits of integration are the bounds between which we evaluate a definite integral. They determine the interval over which we calculate the area under a curve. Changing these limits changes the result of the integral, as we look over a different section of the function.

In substitution, the limits also undergo transformation based on the substituted variable. For example, in the original exercise, we perform a substitution \( u = 3x \), which affects the limits:
  • When \( x = 0 \), \( u = 0 \).
  • When \( x = \frac{\pi}{3} \), \( u = \pi \).
Thus, the integral \( \int_{0}^{\frac{\pi}{3}} 3 \sin^2(3x) \ dx \) transfers to \( \int_{0}^{\pi} \sin^2(u) \ du \).

This method shows how, through substitution, limits help maintain the equality of integrals by adjusting the variable and the expressed interval, ensuring that the resulting integrals cover equivalent areas despite the transformation. Understanding limits of integration is essential for correctly setting up and evaluating definite integrals.

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Most popular questions from this chapter

Decide whether the statements are true or false. Give an explanation for your answer. \(\int 1 /\left(x^{2}+4 x+5\right) d x\) involves a natural logarithm.

A rumor is spread in a school. For \(00\) the time \(t\) at which a fraction \(p\) of the school population has heard the rumor is given by $$t(p)=\int_{a}^{p} \frac{b}{x(1-x)} d x$$ (a) Evaluate the integral to find an explicit formula for \(t(p) .\) Write your answer so it has only one ln term. (b) At time \(t=0\) one percent of the school population \((p=0.01)\) has heard the rumor. What is \(a ?\) (c) At time \(t=1\) half the school population \((p=0.5)\) has heard the rumor. What is \(b ?\) (d) At what time has \(90 \%\) of the school population \((p=0.9)\) heard the rumor?

(a) Between 2000 and 2010 , ACME Widgets sold widgets at a continuous rate of \(R=R_{0} e^{0.125 t}\) widgets per year, where \(t\) is time in years since January 1 2000. Suppose they were selling widgets at a rate of 1000 per year on January \(1,2000 .\) How many widgets did they sell between 2000 and \(2010 ?\) How many did they sell if the rate on January 1,2000 was 1,000,000 widgets per year? (b) In the first case ( 1000 widgets per year on January 1, 2000 ), how long did it take for half the widgets in the ten-year period to be sold? In the second case \((1,000,000 \text { widgets per year on January } 1,2000)\) when had half the widgets in the ten-year period been sold? (c) In \(2010,\) ACME advertised that half the widgets it had sold in the previous ten years were still in use. Based on your answer to part (b), how long must a widget last in order to justify this claim?

Suppose that \(f\) is continuous for all real numbers and that \(\int_{0}^{\infty} f(x) d x\) converges. Let \(a\) be any positive number. Decide which of the statements in Problems \(59-62\) are true and which are false. Give an explanation for your answer. $$\int_{0}^{\infty} a f(x) d x \text { converges. }$$

(a) Find \(\int \sin \theta \cos \theta d \theta\). (b) You probably solved part (a) by making the substitution \(w=\sin \theta\) or \(w=\cos \theta .\) (If not, go back and do it that way.) Now find \(\int \sin \theta \cos \theta d \theta\) by making the other substitution. (c) There is yet another way of finding this integral which involves the trigonometric identities \(\sin (2 \theta)=2 \sin \theta \cos \theta\) \(\cos (2 \theta)=\cos ^{2} \theta-\sin ^{2} \theta\). Find \(\int \sin \theta \cos \theta d \theta\) using one of these identities and then the substitution \(w=2 \theta\). (d) You should now have three different expressions for the indefinite integral \(\int \sin \theta \cos \theta d \theta .\) Are they really different? Are they all correct? Explain.

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