Chapter 7: Problem 72
Find the integrals. $$\int z(z+1)^{1 / 3} d z$$
Short Answer
Expert verified
\( \frac{3}{7}(z+1)^{7/3} - \frac{3}{4}(z+1)^{4/3} + C \)
Step by step solution
01
Substitution
Let's use substitution to simplify the integral. Set \( u = z + 1 \). Then \( du = dz \), which means \( dz = du \). Also, \( z = u - 1 \). Then rewrite the integral in terms of \( u \):\[ \int (u - 1)u^{1/3} \, du \]
02
Expand the Expression
Next, expand the expression \((u - 1)u^{1/3}\). This results in:\[ \int (u^{4/3} - u^{1/3}) \, du \]
03
Integrate Term-by-Term
Now, integrate each term separately:For \( u^{4/3} \, du \), the antiderivative is \( \frac{u^{7/3}}{7/3} = \frac{3}{7}u^{7/3} \).For \( -u^{1/3} \, du \), the antiderivative is \( \frac{u^{4/3}}{4/3} = \frac{3}{4}u^{4/3} \).So the integral becomes:\[ \frac{3}{7}u^{7/3} - \frac{3}{4}u^{4/3} + C \]
04
Substitute Back
Substitute \( u = z + 1 \) back into the expression:\[ \frac{3}{7}(z+1)^{7/3} - \frac{3}{4}(z+1)^{4/3} + C \]
05
Simplify the Final Expression
The final expression is already in a simplified form:\[ \frac{3}{7}(z+1)^{7/3} - \frac{3}{4}(z+1)^{4/3} + C \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
u-substitution
U-substitution is a technique used in integration that allows us to simplify an integral by substituting a part of it with a single variable, usually labeled as \( u \). This method is particularly helpful when dealing with composite functions or when a straightforward integration is challenging.
To apply u-substitution, follow these steps:
To apply u-substitution, follow these steps:
- Identify a portion of the integral that can be replaced with \( u \). In this exercise, \( z+1 \) is chosen as \( u \). The derivative of \( u \) with respect to \( z \) gives \( du = dz \), which is perfect for substitution.
- Express the rest of the integrand in terms of \( u \). This usually involves solving for the original variable, \( z = u - 1 \).
- Rewrite the integral using \( u \) and carry out the integration with respect to \( u \).
antiderivatives
Antiderivatives, sometimes called indefinite integrals, are the reverse process of derivatives. They help us find a function that, when differentiated, gives back the original function. To find an antiderivative, consider integrating the function term-by-term.
In this particular problem, the expression was expanded to \( u^{4/3} - u^{1/3} \). Each term needs to be integrated separately:
In this particular problem, the expression was expanded to \( u^{4/3} - u^{1/3} \). Each term needs to be integrated separately:
- For \( u^{4/3} \), compute the antiderivative by adding 1 to the exponent, then divide by the new exponent. The result is \( \frac{u^{7/3}}{7/3} = \frac{3}{7}u^{7/3} \).
- For \( -u^{1/3} \), similarly, the antiderivative is \( \frac{u^{4/3}}{4/3} = \frac{3}{4}u^{4/3} \).
definite and indefinite integrals
In the context of integrals, it's essential to distinguish between definite and indefinite integrals.
An **indefinite integral**, like the one in this exercise, represents a family of functions. It includes an arbitrary constant \( C \) because the antiderivative could technically shift up or down vertically. The result of integrating in this example is:\[\frac{3}{7}(z+1)^{7/3} - \frac{3}{4}(z+1)^{4/3} + C\]which is a general form and not tied to any specific limit.
An **indefinite integral**, like the one in this exercise, represents a family of functions. It includes an arbitrary constant \( C \) because the antiderivative could technically shift up or down vertically. The result of integrating in this example is:\[\frac{3}{7}(z+1)^{7/3} - \frac{3}{4}(z+1)^{4/3} + C\]which is a general form and not tied to any specific limit.
- Indefinite integrals often appear in contexts where you're finding the general antiderivative without specific boundaries.