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Evaluate the definite integrals. Whenever possible, use the Fundamental Theorem of Calculus, perhaps after a substitution. Otherwise, use numerical methods. $$\int_{1}^{3} \frac{1}{x} d x$$

Short Answer

Expert verified
The definite integral \( \int_{1}^{3} \frac{1}{x} \, dx \) is \( \ln(3) \).

Step by step solution

01

Identify the Integral

The integral we need to evaluate is \( \int_{1}^{3} \frac{1}{x} \, dx \). This is a definite integral from 1 to 3 of the function \( \frac{1}{x} \).
02

Recognize the Antiderivative

The antiderivative of \( \frac{1}{x} \) is \( \ln|x| \). This step involves recognizing the natural logarithm function as the antiderivative of \( \frac{1}{x} \).
03

Apply the Fundamental Theorem of Calculus

According to the Fundamental Theorem of Calculus, to evaluate \( \int_{a}^{b} f(x) \, dx \), where \( F(x) \) is an antiderivative of \( f(x) \), we use \( F(b) - F(a) \). Here, the antiderivative is \( \ln|x| \).
04

Substitute the Limits of Integration

Substitute the upper limit 3 into the antiderivative: \( \ln|3| \). Then substitute the lower limit 1: \( \ln|1| \).
05

Compute the Definite Integral

Calculate \( \ln|3| - \ln|1| \). Since \( \ln|1| = 0 \), the expression simplifies to \( \ln(3) - 0 = \ln(3) \).
06

Final Result

The final result of the definite integral is \( \ln(3) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus is a cornerstone of calculus. It connects differentiation and integration—two fundamental concepts of calculus. Essentially, it provides a way to evaluate definite integrals through differentiation.

In simpler terms, if you know an antiderivative (a reverse process of differentiation) of a function, the Fundamental Theorem tells you how to calculate the integral—or the accumulated area under the curve—from one point to another.

Consider the exercise where we're trying to evaluate the integral \( \int_{1}^{3} \frac{1}{x} \, dx \).
  • The theorem states: if you have a continuous function \( f(x) \) on an interval \([a, b]\), and \( F(x) \) is an antiderivative of \( f(x) \), then the definite integral of \( f(x) \) from \( a \) to \( b \) is given by \( F(b) - F(a) \).
  • In the solution, \( \ln|x| \) serves as the antiderivative \( F(x) \) of \( \frac{1}{x} \), allowing us to easily calculate that \( \int_{1}^{3} \frac{1}{x} \, dx = \ln|3| - \ln|1| \).
Through this theorem, we can transform a problem of an area under a curve into a simple subtractive operation of function values at specified points.
Antiderivatives
Antiderivatives are essentially the opposite of derivatives. When you find the antiderivative of a function, you are essentially finding a function whose derivative is the original function.

This concept can be a bit tricky at first. But once you get the hang of it, it becomes an intuitive way to find functions that represent a wide range of slopes or increasing/decreasing behaviors.

In the exercise, observing that \( \ln|x| \) acts as an antiderivative for the function \( \frac{1}{x} \) is crucial.
  • This means when you differentiate \( \ln|x| \), you get back \( \frac{1}{x} \).
  • This is why, in the expression \( \int \frac{1}{x} \, dx \), \( \ln|x| \) becomes the key for solving it.
This understanding is essential to effectively apply the Fundamental Theorem of Calculus, as it requires finding an antiderivative to solve definite integrals.
Natural Logarithm
The natural logarithm, denoted as \( \ln \, x \), is an important function in mathematics, especially in calculus. It is the inverse of the exponential function with base \( e \).

For calculus learners, one of the most essential derivatives to know is that of the natural logarithm: \( \frac{d}{dx} \ln|x| = \frac{1}{x} \).
  • This identity is directly used in evaluating integrals like \( \int \frac{1}{x} \, dx \), where \( \ln|x| \) is recognized as the antiderivative of \( \frac{1}{x} \).
  • Natural logarithms arise frequently in calculus because of their unique derivative property.
In the provided exercise, substituting the definite integral over \( \frac{1}{x} \) with this understanding simplifies our work significantly. It lays the basis for effectively using the natural logarithm in various functions and integrals.

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Most popular questions from this chapter

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