Chapter 7: Problem 56
Evaluate the indefinite integral, using a trigonometric substitution and a triangle to express the answer in terms of \(x .\) Assume \(-\pi / 2 \leq \theta \leq \pi / 2\) $$\int \frac{x^{2}}{\sqrt{9-x^{2}}} d x$$
Short Answer
Expert verified
\( \frac{27}{2} \left( \sin^{-1}\left(\frac{x}{3}\right) - \frac{x\sqrt{9-x^2}}{9} \right) + C \)
Step by step solution
01
Choose the Substitution
Analyze the integral \( \int \frac{x^2}{\sqrt{9-x^2}} \ dx \) and notice that it corresponds to a form suitable for trigonometric substitution. Let \( x = 3\sin\theta \). This choice stems from the identity \( \sin^2\theta = 1 - \cos^2\theta \).
02
Differentiate the Substitution
Differentiate \( x = 3\sin\theta \) to find \( dx \):\[dx = 3\cos\theta\ d\theta.\]
03
Substitute into the Integral
Substitute \( x = 3\sin\theta \) and \( dx = 3\cos\theta\ d\theta \) into the integral. The integral becomes:\[ \int \frac{(3\sin\theta)^2}{\sqrt{9-(3\sin\theta)^2}} \cdot 3\cos\theta\ d\theta. \] Simplify to obtain:\[ \int \frac{9\sin^2\theta}{3\cos\theta} \cdot 3\cos\theta\ d\theta = 27\int \sin^2\theta\ d\theta. \]
04
Simplify and Use Trigonometric Identity
Use the trigonometric identity \( \sin^2\theta = \frac{1}{2}(1-\cos(2\theta)) \). Therefore, the integral becomes:\[ 27\int \left(\frac{1}{2} - \frac{1}{2}\cos(2\theta)\right) d\theta = \frac{27}{2} \int (1 - \cos(2\theta)) d\theta. \]
05
Integrate the Expression
Integrate each term separately:\[ \frac{27}{2} \left( \theta - \frac{1}{2}\sin(2\theta) \right) + C. \]
06
Express in Terms of \( x \) Using Triangle
Given \( x = 3\sin\theta \), construct a right triangle where the opposite side is \( x \) and the hypotenuse is \( 3 \). The adjacent side is \( \sqrt{9-x^2} \). Hence, \( \theta = \sin^{-1}\left(\frac{x}{3}\right) \) and \( \sin(2\theta) = 2\sin(\theta)\cos(\theta) = \frac{2x\sqrt{9-x^2}}{9} \). Thus, substitute back: \[ \frac{27}{2} \left( \sin^{-1}\left(\frac{x}{3}\right) - \frac{x\sqrt{9-x^2}}{9} \right) + C. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Substitution
When tackling integrals that involve expressions like \(\sqrt{a^2 - x^2}\), trigonometric substitution can be quite useful. Trigonometric substitution is a technique used to simplify integrals by substituting trigonometric functions for algebraic ones.
In our exercise, we have the integral \(\int \frac{x^2}{\sqrt{9-x^2}}\ dx\). Recognizing that \(9-x^2\) fits the form \(a^2-x^2\) where \(a = 3\), a common substitution is \(x = 3\sin\theta\). This substitution leverages the identity \(\sin^2\theta + \cos^2\theta = 1\), aligning perfectly with the integral's square root component.
In our exercise, we have the integral \(\int \frac{x^2}{\sqrt{9-x^2}}\ dx\). Recognizing that \(9-x^2\) fits the form \(a^2-x^2\) where \(a = 3\), a common substitution is \(x = 3\sin\theta\). This substitution leverages the identity \(\sin^2\theta + \cos^2\theta = 1\), aligning perfectly with the integral's square root component.
- The substitution leads to \(x = 3\sin\theta\), which implies \(dx = 3\cos\theta\ d\theta\).
- By expressing \(x\) in terms of \(\theta\), the integral simplifies by transforming the radical expression into a trigonometric identity, replacing the square root \(\sqrt{9-x^2}\) with \(3\cos\theta\).
Indefinite Integral
An indefinite integral refers to the process of finding a function’s antiderivative, in this case, without specific limits or boundaries. These types of integrals add a constant \(C\) at the end, representing an unknown constant arising from the fact that antiderivatives are not unique.
For the exercise integral \(\int \frac{x^2}{\sqrt{9-x^2}}\ dx\), after substituting and simplifying using trigonometric substitution, the integral transforms to \(27\int \sin^2\theta\ d\theta\).
For the exercise integral \(\int \frac{x^2}{\sqrt{9-x^2}}\ dx\), after substituting and simplifying using trigonometric substitution, the integral transforms to \(27\int \sin^2\theta\ d\theta\).
- To solve this indefinite integral, we applied a trigonometric identity: \(\sin^2\theta = \frac{1}{2}(1 - \cos(2\theta))\).
- This results in the integrable expression \(\frac{27}{2}\left(\int 1\ d\theta - \int \cos(2\theta)\ d\theta\right)\), which integrates to \(\frac{27}{2}(\theta - \frac{1}{2}\sin(2\theta)) + C\).
Integration Techniques
Integration techniques are essential tools in calculus used to solve more complex integrals that are not straightforward. In this discussion, we've made use of trigonometric substitution, a vital technique when dealing with expressions under a square root.
For the exercise at hand, the approach required several integration techniques:
For the exercise at hand, the approach required several integration techniques:
- **Trigonometric Identity:** We've used \(\sin^2\theta = \frac{1}{2}(1 - \cos(2\theta))\), an identity that allows simplification of the integral \(27\int \sin^2\theta\ d\theta\).
- **Integration by Substitution:** The original variable \(x\) was substituted into a trigonometric form \(x = 3\sin\theta\), simplifying the integral process.
- **Geometric Interpretation:** Lastly, interpreting \(\theta = \sin^{-1}\left(\frac{x}{3}\right)\) through a right triangle helps express the antiderivative in terms of \(x\).