Chapter 7: Problem 46
Evaluate the definite integrals. Whenever possible, use the Fundamental Theorem of Calculus, perhaps after a substitution. Otherwise, use numerical methods. $$\int_{0}^{1} \frac{d x}{x^{2}+2 x+5}$$
Short Answer
Expert verified
The evaluated integral is approximately 0.197.
Step by step solution
01
Identify the Integral and Plan for Substitution
The integral given is \( \int_{0}^{1} \frac{dx}{x^2 + 2x + 5} \). The denominator is a quadratic expression, which suggests that we might benefit from completing the square. This may help in applying a substitution based on trigonometric identities or other methods of integration.
02
Complete the Square
Complete the square for the expression \( x^2 + 2x + 5 \). This can be rewritten as:\[ x^2 + 2x + 5 = (x+1)^2 + 4 \]This rearranges the problem into a form that suggests the use of trigonometric or hyperbolic substitution.
03
Choose a Trigonometric Substitution
Since we have a form \( (x+1)^2 + 4 \), we choose the substitution: \( x+1 = 2\tan(\theta) \).This implies \( dx = 2\sec^2(\theta) d\theta \). Adjust the limits accordingly; when \( x = 0, \theta = \tan^{-1}(0.5) \) and when \( x = 1, \theta = \tan^{-1}(1) \).
04
Substitute and Simplify the Integral
After substitution, the integral becomes:\[\int_{\tan^{-1}(0.5)}^{\tan^{-1}(1)} \frac{2\sec^2(\theta) d\theta}{4\tan^2(\theta) + 4} = \int_{\tan^{-1}(0.5)}^{\tan^{-1}(1)} \frac{2\sec^2(\theta)}{4\sec^2(\theta)} d\theta\]This simplifies to:\[\frac{1}{2} \int_{\tan^{-1}(0.5)}^{\tan^{-1}(1)} d\theta\]
05
Integrate and Evaluate the Result
The integral \( \int d\theta \) evaluates to \( \theta \). So, the integral becomes:\[\frac{1}{2} (\tan^{-1}(1) - \tan^{-1}(0.5))\]Evaluating at the limits, we find:\[\frac{1}{2} \left( \frac{\pi}{4} - \tan^{-1}(0.5) \right)\]Approximating \( \tan^{-1}(0.5) \) using a calculator or tables, provide a numerical answer.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus is a key principle that connects differentiation and integration. It consists of two main parts:
- The first part assures us that the integral of a function can be reversed by differentiation. In other words, if you have a continuous function and you take its integral, you can differentiate it to get back to the original function.
- The second part provides a practical method for evaluating definite integrals. It states that if \( F \) is an antiderivative of \( f \) on an interval \([a, b]\), then the definite integral of \( f \) from \( a \) to \( b \) is given by \( F(b) - F(a) \).
Substitution Method
The substitution method is a widely used technique for evaluating integrals. It involves changing variables to simplify the integral, making it easier to solve.
The basic idea is to identify a substitution that transforms the original integral into a simpler form. This often involves re-expressing some parts of the integrand using a different variable \( u \), where \( du \) replaces the differential \( dx \) or \( d\theta \).
For instance, in the given problem, the substitution \( x+1=2\tan(\theta) \) was used. This allowed us to convert a complex quadratic expression into a much simpler trigonometric form:
- Identify the quadratic expression \((x+1)^2+4\) suggesting substitution.- Use the trigonometric identity \( x+1=2\tan(\theta) \) to simplify.- The differential was replaced appropriately as \( dx=2\sec^2(\theta)d\theta \).
Through this technique, the integral was modified, leading to a final form that was much easier to handle. Substitution method often needs careful limit adjustments, as seen in the change from \( x \) to \( \theta \), to accurately compute the definite integral limits.
The basic idea is to identify a substitution that transforms the original integral into a simpler form. This often involves re-expressing some parts of the integrand using a different variable \( u \), where \( du \) replaces the differential \( dx \) or \( d\theta \).
For instance, in the given problem, the substitution \( x+1=2\tan(\theta) \) was used. This allowed us to convert a complex quadratic expression into a much simpler trigonometric form:
- Identify the quadratic expression \((x+1)^2+4\) suggesting substitution.- Use the trigonometric identity \( x+1=2\tan(\theta) \) to simplify.- The differential was replaced appropriately as \( dx=2\sec^2(\theta)d\theta \).
Through this technique, the integral was modified, leading to a final form that was much easier to handle. Substitution method often needs careful limit adjustments, as seen in the change from \( x \) to \( \theta \), to accurately compute the definite integral limits.
Trigonometric Substitution
Trigonometric substitution is a powerful technique when dealing with integrals involving square roots or quadratic expressions. It uses trigonometric identities to simplify these expressions.
In our problem, the expression \((x+1)^2 + 4\) hinted at the possibility of trigonometric substitution. By completing the square, the integral took the form suitable for a tangent substitution \( x+1 = 2\tan(\theta) \). This choice is strategic because:
- The expression can be easily simplified using the identity \( 1 + \tan^2(\theta) = \sec^2(\theta) \).- The new integral becomes more straightforward after substitution.
Executing the substitution changes the original variable \( x \) to \( \theta \), and the limits of integration are transformed accordingly, calculated based on the inverse tangent function \( \tan^{-1} \).
Trigonometric substitution is often preferable because it deals effectively with constants added to quadratic terms, transforming them into integrable trigonometric functions. When done correctly, it ensures a smoother path to the solution, as evidenced by the reduction of our example problem into a simple trigonometric integral.
In our problem, the expression \((x+1)^2 + 4\) hinted at the possibility of trigonometric substitution. By completing the square, the integral took the form suitable for a tangent substitution \( x+1 = 2\tan(\theta) \). This choice is strategic because:
- The expression can be easily simplified using the identity \( 1 + \tan^2(\theta) = \sec^2(\theta) \).- The new integral becomes more straightforward after substitution.
Executing the substitution changes the original variable \( x \) to \( \theta \), and the limits of integration are transformed accordingly, calculated based on the inverse tangent function \( \tan^{-1} \).
Trigonometric substitution is often preferable because it deals effectively with constants added to quadratic terms, transforming them into integrable trigonometric functions. When done correctly, it ensures a smoother path to the solution, as evidenced by the reduction of our example problem into a simple trigonometric integral.