Chapter 7: Problem 29
Find the integrals. $$\int x^{3} e^{x^{2}} d x$$
Short Answer
Expert verified
The integral of \( x^3 e^{x^2} \, dx \) is \( \frac{1}{2} x^2 e^{x^2} - \frac{1}{2} e^{x^2} + C \).
Step by step solution
01
Identify the Integral Type
The integral \( \int x^3 e^{x^2} \, dx \) involves both a polynomial \( x^3 \) and an exponential function \( e^{x^2} \). This suggests that integration by parts might be a suitable technique, due to the product of functions.
02
Use Integration by Parts
Recall the integration by parts formula: \( \int u \, dv = uv - \int v \, du \). Choose \( u = x^2 \) (since its derivative simplifies the integral) and \( dv = x e^{x^2} \, dx \).
03
Differentiate and Integrate Parts
Differentiate \( u \): \( du = 2x \, dx \). Integrate \( dv \): \( v = \frac{1}{2} e^{x^2} \).
04
Apply Integration by Parts
Substitute into the integration by parts formula: \[ \int x^3 e^{x^2} \, dx = \frac{1}{2} x^2 e^{x^2} - \int \frac{1}{2} e^{x^2} \cdot 2x \, dx \].
05
Simplify the Integral Expression
Simplify the remaining integral: \( \int e^{x^2} x \, dx \) is solved using substitution. Let \( t = x^2 \), then \( dt = 2x \, dx \), hence \( x \, dx = \frac{1}{2} \, dt \).
06
Substitute and Solve
Substitute \( x \, dx \) in the integral: \[ \int e^t \frac{1}{2} \, dt = \frac{1}{2} \int e^t \, dt = \frac{1}{2} e^t + C \]. Substitute back \( t = x^2 \).
07
Write Final Result
Combine and write the result as: \[ \frac{1}{2} x^2 e^{x^2} - \frac{1}{2} e^{x^2} + C \].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration by Parts
Integration by parts is a powerful technique for evaluating integrals of products of functions. It is often used when the integral contains the product of a polynomial function and an exponential, trigonometric, or logarithmic function. The method is based on the product rule for differentiation and is articulated through the formula: \[ \int u \, dv = uv - \int v \, du \]Here are the important steps in using integration by parts:
- Identify parts: Choose which part of the integrand will be \( u \) and which will be \( dv \). Commonly, \( u \) is chosen as the polynomial component because its derivative simplifies quickly, and \( dv \) is the remaining factor.
- Differentiation and Integration: Differentiate \( u \) to find \( du \), and integrate \( dv \) to obtain \( v \).
- Apply the Formula: Substitute \( u \), \( du \), \( v \), and \( dv \) into the integration by parts formula and solve for the integral.
Substitution Method
The substitution method, also known as "u-substitution," is a simple yet essential integration technique. It is mainly used to simplify integrals by transforming them into an easier form by substituting part of the integral with a new variable. To effectively use substitution:
- Identify the substitution: Look for a part of the integral whose derivative is present elsewhere in the integral. This often involves functions inside functions, like \( e^{x^2} \).
- Make the substitution: Let \( t = g(x) \) where \( g(x) \) is the part of the function to replace. Differentiate it to find \( dt = g'(x) \, dx \).
- Solve the new integral: Replace the identified parts in the integral with \( t \) and \( dt \). Solve the simplified integral with respect to \( t \).
- Convert back: Once you have calculated the integral with respect to \( t \), substitute back the original variable \( x \) to obtain the final answer.
Exponential Functions
Exponential functions, represented as \( e^{x} \) or variations like \( e^{x^2} \), occur frequently in calculus due to their unique properties. They are a specific type of function where the rate of growth of the function is proportional to its value, making them quite significant in mathematics. Here are key points about exponential functions:
- The base \( e \) is an irrational number approximately equal to 2.71828, known as Euler's number.
- Exponential functions exhibit continuous and persistent growth, applicable in fields like population dynamics, compound interest, and heat dissipation.
- In integration, exponential functions are significant because they seamlessly integrate without change, which is why \( \int e^{x} \, dx = e^{x} + C \).
- When exponentiated as \( e^{x^2} \), methods like substitution are used during integration to simplify and solve the integrals.