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Anti differentiate using the table of integrals. You may need to transform the integrals first. $$\int \frac{d x}{\sqrt{25-16 x^{2}}}$$

Short Answer

Expert verified
The antiderivative is \( \frac{1}{4} \sin^{-1} \left( \frac{4x}{5} \right) + C \).

Step by step solution

01

Identify the Integral Form

The integral given is \( \int \frac{dx}{\sqrt{25-16x^2}} \). We need to compare this with known integral formulas from the table of integrals. The typical form that resembles this integral is \( \int \frac{dx}{\sqrt{a^2 - x^2}} = \sin^{-1}\left( \frac{x}{a} \right) + C \), where \( a \) is a constant.
02

Rewrite the Denominator

Factor out the term \( 16 \) from under the square root to match the standard integral form: \[ \sqrt{25 - 16x^2} = \sqrt{25 - (4x)^2} = \sqrt{5^2 - (4x)^2} \]This rewriting allows us to identify \( a = 5 \) and \( u = 4x \), which will help us apply the table of integrals.
03

Perform a Substitution

Let \( u = 4x \), then \( du = 4 \, dx \) or \( dx = \frac{du}{4} \). Substitute \( u \) in the integral:\[ \int \frac{dx}{\sqrt{25 - 16x^2}} = \int \frac{\frac{1}{4} \, du}{\sqrt{25 - u^2}} \]This simplifies to \( \frac{1}{4} \int \frac{du}{\sqrt{5^2 - u^2}} \).
04

Use the Table of Integrals

Now, apply the known integral result:\[ \int \frac{du}{\sqrt{a^2 - u^2}} = \sin^{-1} \left( \frac{u}{a} \right) + C \]where \( a = 5 \), so this becomes \( \frac{1}{4} \sin^{-1} \left( \frac{u}{5} \right) + C \).
05

Substitute Back

Replace \( u \) with \( 4x \) to revert to the original variable:\[ \frac{1}{4} \sin^{-1} \left( \frac{4x}{5} \right) + C \]This is the antiderivative of the given integral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Antiderivatives
Antiderivatives, also known as indefinite integrals, are functions that reverse the process of differentiation. Imagine you have a function, and you want to find another function whose derivative is the original function. That's basically an antiderivative. We write this process as \( \int f(x) \, dx \).
To identify the antiderivative of a complex function, follow these steps:
  • Identify the integral expression and compare it to known forms from a table of integrals.
  • Perform necessary algebraic transformations to match a standard integral form. For instance, factor the denominator to resemble a known integral representation.
  • Apply substitution if needed to simplify the expression further.
During this process, constants of integration, denoted as \( C \), appear. They make sure the solution covers all possible original functions.
Understanding how antiderivatives function lays the groundwork for solving integrals and applying fundamental calculus concepts, like the Fundamental Theorem of Calculus.
Table of Integrals
A table of integrals is a helpful tool for solving complex integration problems. It provides a list of integral forms along with their corresponding antiderivatives. Using this table, you can match the integral you need to solve with a known form and directly write down the antiderivative.
Knowing the most common integral forms in the table can greatly speed up solving processes. Here are some of the common entries:
  • \( \int \frac{dx}{a^2 + x^2} = \frac{1}{a} \tan^{-1} \left( \frac{x}{a} \right) + C \)
  • \( \int e^x \, dx = e^x + C \)
  • \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \) , provided \( n eq -1 \)
By comparing your integral with these forms, you can often find a direct match. In cases where matching is not straightforward, algebraic manipulation or substitution may be required, as seen in our exercise. Here, recognizing the integral function allowed us to apply the known formula quickly, leading to the solution.
Trigonometric Substitution
Trigonometric substitution is a technique used in calculus to simplify integrals involving square roots. This method involves substituting a trigonometric function for a variable, making the integral easier to evaluate. It's particularly useful when the integral involves expressions like \( \sqrt{a^2 - x^2} \) or \( \sqrt{x^2 - a^2} \).
For our exercise, we employed trigonometric substitution to simplify the integral \( \int \frac{dx}{\sqrt{25 - 16x^2}} \). We used the substitution \( u = 4x \) leading to \( du = 4dx \), and transformed the integral to an easier form.
  • Identify which trigonometric function to use based on the structure of the square root expression. Typically, use \( x = a \sin(\theta) \) for \( \sqrt{a^2 - x^2} \).
  • Convert the integral in terms of the new variable and the differential \( du \).
  • Integrate using known trigonometric identities or a table of integrals.
  • Once the integral is calculated, substitute back the original variables.
This approach converts the integral into a simpler form that can directly use a known integral result, streamlining the process. Once mastered, trigonometric substitution becomes a powerful tool in tackling complex integrals.

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Most popular questions from this chapter

(a) Find \(\int \sin \theta \cos \theta d \theta\). (b) You probably solved part (a) by making the substitution \(w=\sin \theta\) or \(w=\cos \theta .\) (If not, go back and do it that way.) Now find \(\int \sin \theta \cos \theta d \theta\) by making the other substitution. (c) There is yet another way of finding this integral which involves the trigonometric identities \(\sin (2 \theta)=2 \sin \theta \cos \theta\) \(\cos (2 \theta)=\cos ^{2} \theta-\sin ^{2} \theta\). Find \(\int \sin \theta \cos \theta d \theta\) using one of these identities and then the substitution \(w=2 \theta\). (d) You should now have three different expressions for the indefinite integral \(\int \sin \theta \cos \theta d \theta .\) Are they really different? Are they all correct? Explain.

Decide whether the statements are true or false. Give an explanation for your answer. \(\int x^{-1}\left((\ln x)^{2}+(\ln x)^{3}\right) d x\) is a polynomial with \(\ln x\) as the variable.

Decide whether the statements are true or false. Give an explanation for your answer. \(\int 1 /\left(x^{2}+4 x+5\right) d x\) involves a natural logarithm.

Give an example of: An indefinite integral involving sin \(x\) that can be evaluated with a reduction formula.

Throughout much of the \(20^{\text {th }}\) century, the yearly consumption of electricity in the US increased exponentially at a continuous rate of \(7 \%\) per year. Assume this trend continues and that the electrical energy consumed in 1900 was 1.4 million megawatt-hours. (a) Write an expression for yearly electricity consumption as a function of time, \(t,\) in years since 1900 (b) Find the average yearly electrical consumption throughout the \(20^{\text {th }}\) century. (c) During what year was electrical consumption closest to the average for the century? (d) Without doing the calculation for part (c), how could you have predicted which half of the century the answer would be in?

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