Chapter 6: Problem 76
Sketch the parabola \(y=x(x-\pi)\) and the curve \(y=\) \(\sin x,\) showing their points of intersection. Find the exact area between the two graphs.
Short Answer
Expert verified
The area between the curves is \( -\frac{\pi^3}{6} + 2 \), which simplifies to \( 2 - \frac{\pi^3}{6} \).
Step by step solution
01
Set up the Equations
We have two functions: \( y = x(x - \pi) \) and \( y = \sin x \). Our goal is to find their points of intersection and the area between them.
02
Find Points of Intersection
To find the points of intersection, set \( x(x - \pi) = \sin x \) and solve for \( x \). This involves solving a trigonometric equation, which can have multiple solutions. Through analysis, find that they intersect at \( x = 0 \) and \( x = \pi \).
03
Plan the Area Calculation
The area between the curves can be found by integrating the difference between the functions from \(x = 0\) to \(x = \pi\). Specifically, integrate \(| x(x - \pi) - \sin x |\) from 0 to \(\pi\).
04
Set Up the Integral
The integral to calculate the area is: \[ \int_{0}^{\pi} | x(x - \pi) - \sin x | \, dx \] Determine the dominant function over this interval to simplify this into definite integrals without the absolute value.
05
Simplify the Integral into Two Parts
From \( 0 \) to \( \pi \), find that \( \sin x \) is always less than \( x(x - \pi) \). Therefore, the absolute value can be removed, and the integral becomes: \[ \int_{0}^{\pi} ( x(x - \pi) - \sin x ) \, dx \]
06
Calculate the Integral
Calculate the integral \[ \int_{0}^{\pi} (x^2 - \pi x - \sin x) \, dx \] This involves separate integrals: 1. \( \int_{0}^{\pi} x^2 \, dx = \frac{x^3}{3} \bigg|_0^\pi \) 2. \( \int_{0}^{\pi} -\pi x \, dx = -\frac{\pi x^2}{2} \bigg|_0^\pi \) 3. \( \int_{0}^{\pi} -\sin x \, dx = \cos x \bigg|_0^\pi \)
07
Solve the Integrals
Evaluate each: 1. \( \frac{\pi^3}{3} - 0 = \frac{\pi^3}{3} \)2. \(-\frac{\pi (\pi^2)}{2} - 0 = -\frac{\pi^3}{2} \)3. \((-\cos \pi) - (-\cos 0) = 2 \)
08
Compute the Area
Add the results together: \( \frac{\pi^3}{3} - \frac{\pi^3}{2} + 2 \). Use a common denominator to simplify: \( \frac{2\pi^3 - 3\pi^3 }{6} + 2 = -\frac{\pi^3}{6} + 2 \) for total area.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
A parabola is a U-shaped curve that can open upwards or downwards, and it is represented by a quadratic function. The function for a parabola typically takes the form of
- \( y = ax^2 + bx + c \).
- Vertex: The highest or lowest point of the parabola, determined by the axis of symmetry.
- Axis of Symmetry: A vertical line that divides the parabola into two identical halves.
- Direction: If \( a > 0 \), it opens upwards; if \( a < 0 \), it opens downwards.
Trigonometric Functions
Trigonometric functions are fundamental in understanding relations involving angles and lengths, especially in periodic phenomena. The sine function, \( y = \sin x \), is one of the primary trigonometric functions. Key characteristics of the sine function include:
- Periodicity: It repeats every \( 2\pi \) radians, which corresponds to 360 degrees.
- Amplitude: The maximum value is 1, and the minimum value is -1.
- Zero Crossings: Occur at integer multiples of \( \pi \).
Definite Integral
The definite integral is a fundamental concept in calculus used to calculate the area under or between curves. In this exercise, the definite integral is used to find the area between the parabola \( y = x(x - \pi) \) and the sine wave \( y = \sin x \). The process includes:
- Setting up the integral: Identifying the limits of integration — in this case, from \( x = 0 \) to \( x = \pi \).
- Evaluating the integral: Calculating the integral \( \int_{0}^{\pi} (x^2 - \pi x - \sin x) \, dx \), by breaking it down into simpler parts:
- 1. \( \int x^2 \, dx \)
- 2. \( \int -\pi x \, dx \)
- 3. \( \int -\sin x \, dx \)