Chapter 6: Problem 65
Use the Fundamental Theorem to find the area under \(f(x)=x^{2}\) between \(x=0\) and \(x=3\)
Short Answer
Expert verified
The area under the curve from \(x=0\) to \(x=3\) is 9.
Step by step solution
01
Identify the function and limits
The function given is \(f(x) = x^2\) and we need to find the area under the curve between the limits \(x = 0\) and \(x = 3\). This area can be interpreted as the definite integral of \(f(x)\) from 0 to 3.
02
Set up the definite integral
Set up the definite integral to find the area under the curve of \(f(x) = x^2\) from \(x = 0\) to \(x = 3\). This is written as: \[\int_{0}^{3} x^2 \, dx.\]
03
Integrate the function
Find the antiderivative of \(x^2\). The antiderivative of \(x^n\) is \(\frac{x^{n+1}}{n+1}\), so the antiderivative of \(x^2\) is \(\frac{x^3}{3}\).
04
Evaluate the antiderivative at the upper limit
Substitute \(x = 3\) into the antiderivative \(\frac{x^3}{3}\). \[\frac{3^3}{3} = \frac{27}{3} = 9.\]
05
Evaluate the antiderivative at the lower limit
Substitute \(x = 0\) into the antiderivative \(\frac{x^3}{3}\). \[\frac{0^3}{3} = 0.\]
06
Calculate the definite integral
Subtract the value of the antiderivative at the lower limit from the value at the upper limit. \[9 - 0 = 9.\]Therefore, the area under the curve from \(x = 0\) to \(x = 3\) is 9.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integral
The definite integral is a fundamental concept in calculus that provides a powerful tool for calculating the area under a curve. It involves summing up infinitely small products of the values of a function and tiny increments of the independent variable. This process helps us find the total accumulation of quantities like area, distance, or even probability over a given interval.
The notation \( \int_{a}^{b} f(x) \, dx \) represents the definite integral, where the function \( f(x) \) is integrated from lower limit \( a \) to upper limit \( b \). In the context of our exercise, it helps us sum up all the small areas under the curve \( f(x)=x^2 \) from \( x=0 \) to \( x=3 \).
The notation \( \int_{a}^{b} f(x) \, dx \) represents the definite integral, where the function \( f(x) \) is integrated from lower limit \( a \) to upper limit \( b \). In the context of our exercise, it helps us sum up all the small areas under the curve \( f(x)=x^2 \) from \( x=0 \) to \( x=3 \).
- The lower limit (0 in this case) indicates where we start measuring the area.
- The upper limit (3 here) tells us where to stop.
- The function \( f(x) = x^2 \) gives the height of the curve at any point \( x \).
Antiderivative
An antiderivative, also known as an indefinite integral, is essentially the reverse process of differentiation. It involves finding a function whose derivative is the given function. This concept is key when using the Fundamental Theorem of Calculus to evaluate a definite integral.
For the exercise at hand, finding the antiderivative of \( x^2 \) is crucial for computing the definite integral. The general rule to find an antiderivative of \( x^n \) is \( \frac{x^{n+1}}{n+1} + C \), where \( C \) is the constant of integration that is often omitted in definite integrals.
For the exercise at hand, finding the antiderivative of \( x^2 \) is crucial for computing the definite integral. The general rule to find an antiderivative of \( x^n \) is \( \frac{x^{n+1}}{n+1} + C \), where \( C \) is the constant of integration that is often omitted in definite integrals.
- For \( x^2 \), applying the rule gives \( \frac{x^3}{3} \).
- This antiderivative helps to transition from the process of integration to evaluation.
Area Under the Curve
The concept of finding the area under a curve is central to many problems in mathematics and applied sciences. In simplest terms, it refers to the space between the curve of a function and the x-axis over a specified interval.
In our scenario with \( f(x) = x^2 \), the area under the curve from \( x = 0 \) to \( x = 3 \) is what we're after. This represents the sum total of all the infinitely small sections that lie between the curve \( x^2 \) and the x-axis over the specified range.
In our scenario with \( f(x) = x^2 \), the area under the curve from \( x = 0 \) to \( x = 3 \) is what we're after. This represents the sum total of all the infinitely small sections that lie between the curve \( x^2 \) and the x-axis over the specified range.
- It's practically the same as filling the space under \( y = x^2 \) with tiny, indivisible segments.
- The evaluation of the antiderivative at the bounds gives the accumulated total, which in this case turns out to be 9.