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True or false? Give an explanation for your answer. If \(f(t)\) is a linear function with positive slope, then an antiderivative, \(F\), is a linear function.

Short Answer

Expert verified
False, the antiderivative is quadratic, not linear.

Step by step solution

01

Identify the Given Function

The problem gives us a function \( f(t) \) which is a linear function with a positive slope. This means we can express \( f(t) \) as \( f(t) = mt + b \), where \( m > 0 \) and \( b \) is a constant.
02

Find the Antiderivative

To find the antiderivative \( F(t) \) of \( f(t) = mt + b \), we integrate this function with respect to \( t \). The integral of \( mt \) is \( \frac{mt^2}{2} \) and the integral of \( b \) is \( bt \). Therefore, the antiderivative is \( F(t) = \frac{mt^2}{2} + bt + C \), where \( C \) is a constant of integration.
03

Examine the Properties of the Antiderivative

The antiderivative \( F(t) = \frac{mt^2}{2} + bt + C \) is a quadratic function because it includes a \( t^2 \) term. This term ensures that \( F(t) \) is not linear since linear functions do not have terms involving powers of \( t \) higher than one.
04

Conclusion

Since the antiderivative \( F(t) = \frac{mt^2}{2} + bt + C \) is quadratic due to the presence of the \( t^2 \) term, \( F(t) \) cannot be a linear function. Thus, the statement is false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Functions
A linear function is one of the most straightforward types of functions in mathematics. It can be represented by the general form \( f(t) = mt + b \), where:
  • \(m\) is the slope of the line, indicating how steep the line is.
  • \(b\) is the y-intercept, the point where the line crosses the y-axis.
The slope, \(m\), plays a crucial role as it dictates the direction and steepness of the line. A positive slope means the function increases as \(t\) increases, whereas a negative slope means it decreases. Linear functions are characterized by having only first degree terms, meaning the variable \(t\) is not raised to any power higher than one.
Quadratic Functions
Quadratic functions add a bit more complexity compared to linear functions. They are typically represented by the form \(f(x) = ax^2 + bx + c\). Here:
  • \(a\), \(b\), and \(c\) are constants.
  • \(a\) cannot be zero, as this would make the function linear instead of quadratic.
  • \(x^2\) is the term that differentiates quadratic from linear functions.
The defining characteristic of a quadratic function is its \(x^2\) term. This presence makes the graph of a quadratic function a parabola, which can open upwards or downwards depending on the sign of \(a\). This distinct feature is what gives a quadratic function a curved shape, different from the straight line of a linear function.
Integration
Integration is a fundamental concept in calculus that is used to find antiderivatives or the area under a curve. When we integrate a function, we are essentially reversing the process of differentiation. For a linear function like \(f(t) = mt + b\), the integration process transforms it as follows:
  • The integral of \(mt\) is \(\frac{mt^2}{2}\).
  • The integral of \(b\) is \(bt\).
The result of this integration is the antiderivative \(F(t) = \frac{mt^2}{2} + bt + C\). This illustrates how integration enables us to find a new function whose derivative would return to the original linear function.
Constant of Integration
In the process of integration, particularly when finding an antiderivative, a very important component arises - the constant of integration, denoted as \(C\). When we integrate, we need to account for the fact that there are infinitely many antiderivatives differing by a constant. This is because the derivative of a constant is zero. Thus, when computing indefinite integrals, this constant \(C\) is appended to capture all potential antiderivative functions.For example, in the antiderivative \(F(t) = \frac{mt^2}{2} + bt + C\), \(C\) is the constant of integration. Without \(C\), the solution would be incomplete, as it would only represent one of infinitely many possible functions that differentiate to \(f(t) = mt + b\).

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