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91Ó°ÊÓ

Write a parameterization for the curves in the \(x y\) -plane. A vertical line through the point (-2,-3).

Short Answer

Expert verified
The parameterization is \((x(t), y(t)) = (-2, t)\).

Step by step solution

01

Identify the equation of a vertical line

A vertical line in the Cartesian plane has a constant x-value because all y-values are permissible. For the given vertical line through the point (-2,-3), the equation is simply \[ x = -2 \].
02

Understand parameterization of a vertical line

Parameterization involves representing the equation using a parameter, typically denoted by \( t \). Since the x-coordinate is fixed, the parameter will be assigned to the y-coordinate.
03

Define parameterization

Assign \( x(t) = -2 \) because the x-coordinate is constant, and allow \( y(t) = t \) to represent all possible y-values. Thus, the parameterization of the curve is:\[(x(t), y(t)) = (-2, t)\], where \( t \in \mathbb{R} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Line
A vertical line is a line that runs up and down on the Cartesian plane. Unlike other lines, a vertical line has no slope. In mathematical terms, the slope of a vertical line is considered undefined. This is because the change in the x-value is zero, and division by zero is undefined.

For any vertical line, the x-coordinate remains constant. This means all points on the line will have the same x-value, regardless of the y-values. For example, if we have a vertical line at x = -2, every point on this line will have an x-coordinate of -2, but the y-coordinate can vary.

In real-world terms, imagine standing still at a specific spot while an elevator travels up and down. Your position left or right doesn't change, just your height, much like how the x-value in a vertical line stays constant while y varies.
Cartesian Plane
The Cartesian plane, named after the mathematician René Descartes, is a two-dimensional plane used for graphing equations and points. It's made up of two perpendicular number lines: the x-axis (horizontal) and the y-axis (vertical). These axes intersect at a point called the origin, designated as (0,0).

Every point in the Cartesian plane can be described by an ordered pair \((x, y)\). The **x-coordinate** signifies horizontal position, while the **y-coordinate** indicates vertical position. Together, they pinpoint a precise location on the plane.

- **Quadrants**: The plane is divided into four sections called quadrants: - Quadrant I: where both x and y are positive - Quadrant II: where x is negative and y is positive - Quadrant III: where both x and y are negative - Quadrant IV: where x is positive and y is negative
- **Vertical and Horizontal Lines**: Vertical lines run parallel to the y-axis, having constant x-values. Horizontal lines run parallel to the x-axis, having constant y-values.

The Cartesian plane is foundational for graphing and studying geometric shapes, lines, and curves. It allows us to visualize mathematical relationships clearly.
Parameter
A parameter is a special kind of variable used to represent a set of quantities within a mathematical function or system. In the context of parameterization, a parameter acts as a "controller" or "driver," defining every point along a curve or line.

When parameterizing a line or curve, we express the coordinates as functions of a parameter, often denoted as \( t \). For instance, in the vertical line's parameterization from the problem, we define:- \(x(t) = -2\) implying the x-value remains fixed.- \(y(t) = t\) permits the y-value to change as the parameter \( t \) varies across all real numbers.
Parameterization offers flexibility, enabling us to describe more than just lines. It's possible to model complex curves, circles, and paths using this method. In computer graphics, parameterization is a key technique within animations and simulations to seamlessly transition shapes across certain trajectories.
In essence, parameters enable the transformation of static mathematical equations into dynamic, explorative tools.

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Most popular questions from this chapter

Given that \(f^{\prime}(x)\) is continuous everywhere and changes from negative to positive at \(x=a,\) which of the following statements must be true? (a) \(a\) is a critical point of \(f(x)\) (b) \(f(a)\) is a local maximum (c) \(f(a)\) is a local minimum (d) \(f^{\prime}(a)\) is a local maximum (e) \(f^{\prime}(a)\) is a local minimum

Give an example of a function \(f\) that makes the statement true, or say why such an example is impossible. Assume that \(f^{\prime \prime}\) exists everywhere. \(f(x) f^{\prime \prime}(x)<0\) for all \(x\).

Give an example of: A family of functions, \(g(x),\) depending on two parameters, \(a\) and \(b,\) such that each member of the family has exactly two critical points and one inflection point. You may want to restrict \(a\) and \(b\).

For positive constants \(A\) and \(B,\) the force, \(F,\) between two atoms in a molecule at a distance \(r\) apart is given by $$F=-\frac{A}{r^{2}}+\frac{B}{r^{3}}$$ (a) How fast does force change as \(r\) increases? What type of units does it have? (b) If at some time \(t\) the distance is changing at a rate \(k\) at what rate is the force changing with time? What type of units does this rate of change have?

An item costs \(\$ 500\) at time \(t=0\) and costs \(\$ P\) in year \(t\) When inflation is \(r \%\) per year, the price is given by $$P=500 e^{r t / 100}$$ (a) If \(r\) is a constant, at what rate is the price rising (in dollars per year) (i) Initially? (ii) After 2 years? (b) Now suppose that \(r\) is increasing by 0.3 per year when \(r=4\) and \(t=2 .\) At what rate (dollars per year) is the price increasing at that time?

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