/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Find formulas for the functions ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find formulas for the functions described. A function of the form \(y=a\left(1-e^{-b x}\right)\) with \(a, b>0\) and a horizontal asymptote of \(y=5\).

Short Answer

Expert verified
The formula is \(y=5\left(1-e^{-bx}\right)\), with \(b > 0\).

Step by step solution

01

Identify Horizontal Asymptote

Since we need a horizontal asymptote of \(y=5\), the parameter \(a\) in the function \(y=a\left(1-e^{-bx}\right)\) determines the horizontal asymptote. Therefore, set \(a=5\) because as \(x\) approaches infinity, \(e^{-bx}\) approaches zero, making \(y\rightarrow 5(1-0)=5\).
02

Confirm Conditions for Parameters

Both parameters \(a\) and \(b\) must be positive, i.e., \(a, b > 0\). We've already chosen \(a=5\), which meets this requirement. Any positive \(b\) will satisfy \(b > 0\).
03

Write the Formula

With \(a=5\) and \(b > 0\) (any positive value), the formula for the function becomes \(y=5\left(1-e^{-bx}\right)\), where \(b\) can be any positive number.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Asymptote
In exponential functions, a horizontal asymptote describes the line that the curve approaches but never actually touches. This asymptote acts as a boundary, indicating the eventual value of the function as the input increases or decreases significantly.

For the function given, the horizontal asymptote is determined by the parameter \(a\) in the function \(y = a(1 - e^{-bx})\). As \(x\) becomes very large, the term \(e^{-bx}\) tends toward zero. Thus, \(y\) approaches \(a\).

In our case, with a horizontal asymptote of \(y = 5\), \(a\) must be 5. This means that the function will level out to a value of 5 as \(x\) increases to infinity.
Asymptotic Behavior
Asymptotic behavior refers to how a function behaves as it approaches a specific line or point. In this instance, the behavior of the exponential function \(y = a(1 - e^{-bx})\) is primarily dominated by the \(e^{-bx}\) term.

As \(x\) increases, \(e^{-bx}\) decreases to zero in an exponential manner. This rapid decrease results in \(y\) nearing the horizontal asymptote much faster compared to slower-decaying functions. This characteristic is typical in exponential functions, where growth or decay occurs quickly at first and then slows down progressively.

Understanding this aspect is crucial, as it helps predict how close the function will get to its horizontal asymptote and how fast it gets there.
Parameter Identification
Identifying parameters within a function involves understanding their roles and effects on the graph. In our function \(y = a(1 - e^{-bx})\), the parameters \(a\) and \(b\) are key.

The parameter \(a\) determines the horizontal asymptote, and since we need this asymptote to be \(y = 5\), we establish \(a = 5\). For \(b\), the rate at which the function approaches its asymptote is controlled. Larger values of \(b\) result in a more rapid approach, as \(e^{-bx}\) decreases faster.

Both \(a\) and \(b\) must be positive, ensuring that the function behaves properly and aligns with natural exponential growth or decay models.
Function Formulation
Formulating a function involves putting together all the identified parameters and ensuring they satisfy the required conditions. For this problem, we derive the formula \(y = 5(1 - e^{-bx})\)

Here, \(a = 5\) ensures that the horizontal asymptote is \(y = 5\). The parameter \(b\) remains a positive number, which influences how quickly the function reaches the asymptote.

This formulation highlights the role of each parameter in shaping the graph, allowing modifications based on particular needs, such as adjusting \(b\) to model specific data trends or behaviors. Remember, the accuracy of this model depends on precise parameter values to fit the real-world scenario it aims to represent.

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Most popular questions from this chapter

A hypothetical moon orbits a planet which in turn orbits a star. Suppose that the orbits are circular and that the moon orbits the planet 12 times in the time it takes for the planet to orbit the star once. In this problem we will investigate whether the moon could come to a stop at some instant. (See Figure 4.1 \(12 .)\) (a) Suppose the radius of the moon's orbit around the planet is 1 unit and the radius of the planet's orbit around the star is \(R\) units. Explain why the motion of the moon relative to the star can be described by the parametric equations \(x=R \cos t+\cos (12 t), \quad y=R \sin t+\sin (12 t)\) (b) Find values for \(R\) and \(t\) such that the moon stops relative to the star at time \(t\) (c) On a graphing calculator, plot the path of the moon for the value of \(R\) you obtained in part (b). Experiment with other values for \(\bar{R}\)

If \(a>0, b>0,\) show that \(f(x)=a\left(1-e^{-b x}\right)\) is everywhere increasing and everywhere concave down.

Investigate the given two parameter family of functions. Assume that \(a\) and \(b\) are positive. (a) Graph \(f(x)\) using \(b=1\) and three different values for \(a\). (b) Graph \(f(x)\) using \(a=1\) and three different values for \(b\). (c) In the graphs in parts (a) and (b), how do the critical points of \(f\) appear to move as \(a\) increases? As \(b\) increases? (d) Find a formula for the \(x\) -coordinates of the critical point(s) of \(f\) in terms of \(a\) and \(b\). $$f(x)=\frac{a x}{x^{2}+b}$$

Are the statements true of false? Give an explanation for your answer. If the radius of a circle is increasing at a constant rate, then so is the area.

A ruptured oil tanker causes a circular oil slick on the surface of the ocean. When its radius is 150 meters, the radius of the slick is expanding by 0.1 meter/minute and its thickness is 0.02 meter. At that moment: (a) How fast is the area of the slick expanding? (b) The circular slick has the same thickness everywhere, and the volume of oil spilled remains fixed. How fast is the thickness of the slick decreasing?

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