Chapter 4: Problem 22
The parametric equations describe the motion of a particle. Find an equation of the curve along which the particle moves. $$\begin{aligned} &x=t^{2}+3\\\ &y=t^{2}-2 \end{aligned}$$
Short Answer
Expert verified
The Cartesian equation of the curve is \( y = x - 5 \).
Step by step solution
01
Introduction to Parametric Equations
Parametric equations express variables such that both coordinates, usually defined as \( x \) and \( y \), are an outcome of a third variable, typically \( t \). Here, \( x = t^2 + 3 \) and \( y = t^2 - 2 \). We need to find a relationship between \( x \) and \( y \) that doesn't include \( t \).
02
Express \( t^2 \) from \( x \)
From \( x = t^2 + 3 \), solve for \( t^2 \): \[ t^2 = x - 3 \]
03
Express \( t^2 \) from \( y \)
From \( y = t^2 - 2 \), solve for \( t^2 \): \[ t^2 = y + 2 \]
04
Equate the expressions for \( t^2 \)
Now that \( t^2 \) can be represented in terms of \( x \) and \( y \), equate the two expressions: \[ x - 3 = y + 2 \]
05
Solve the equation for \( y \)
Rearrange the equation \( x - 3 = y + 2 \) to express \( y \) in terms of \( x \): \[ y = x - 5 \]
06
Write the Cartesian Equation
The equation \( y = x - 5 \) is the Cartesian equation representing the path of the particle. It describes a straight line with a slope of 1 and a y-intercept at -5.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Motion of a Particle
The motion of a particle can be represented using parametric equations, where a third variable, often denoted as \( t \), dictates the position of the particle over time. In this context, think of \( t \) as time. As time progresses, the values of \( x \) and \( y \) change, plotting a trajectory in the plane. This method helps in illustrating complex movements simply by expressing \( x \) and \( y \) as functions of \( t \).
For example, consider the parametric equations given in the exercise:
Parametric equations are particularly useful because they can describe a wide range of movements, including linear, circular, and more complicated paths.
For example, consider the parametric equations given in the exercise:
- \( x = t^2 + 3 \)
- \( y = t^2 - 2 \)
Parametric equations are particularly useful because they can describe a wide range of movements, including linear, circular, and more complicated paths.
Creating the Cartesian Equation
A Cartesian equation is a familiar form of representing curves, usually in the format \( y = f(x) \). To convert the parametric form into a Cartesian one involves eliminating the parameter \( t \). This allows us to describe the path taken by the particle in terms of only \( x \) and \( y \).
In our exercise, we've derived expressions from the parametric equations by isolating \( t^2 \):
\( x - 3 = y + 2 \)
By rearranging this equation, we convert it into the Cartesian form:
\( y = x - 5 \)
This equation is straightforward and represents a line, giving a clear path for the particle in Cartesian coordinates.
In our exercise, we've derived expressions from the parametric equations by isolating \( t^2 \):
- From \( x = t^2 + 3 \), we find \( t^2 = x - 3 \).
- From \( y = t^2 - 2 \), we find \( t^2 = y + 2 \).
\( x - 3 = y + 2 \)
By rearranging this equation, we convert it into the Cartesian form:
\( y = x - 5 \)
This equation is straightforward and represents a line, giving a clear path for the particle in Cartesian coordinates.
Exploring Curve Tracing
Curve tracing involves mapping out the path of the particle from its parametric description to a recognizable curve. Understanding the path is crucial for visualizing the motion.
Our Cartesian equation \( y = x - 5 \) now describes a straight line in the coordinate plane. By interpreting this:
To trace the particle's motion along this line, consider how the values of \( t \) influence the graph:
Our Cartesian equation \( y = x - 5 \) now describes a straight line in the coordinate plane. By interpreting this:
- The slope is \( 1 \), indicating a diagonal ascent in the positive direction.
- The y-intercept is \(-5\), showing where the line crosses the y-axis.
To trace the particle's motion along this line, consider how the values of \( t \) influence the graph:
- As \( t \) increases, \( x \) and \( y \) increase, with the curve moving diagonally upwards.
- When \( t \) is negative, both \( x \) and \( y \) decrease but remain on the same linear trajectory.