Chapter 3: Problem 4
Find the tangent line approximation to \(1 / x\) near \(x=1\).
Short Answer
Expert verified
The tangent line is \(y = -x + 2\) at \(x = 1\).
Step by step solution
01
Identify the function and point of tangency
The function is given as \(f(x) = \frac{1}{x}\), and we need to find the tangent line at \(x = 1\). This means we are looking to approximate \(\frac{1}{x}\) near \(x = 1\).
02
Determine the derivative
To find the tangent line, we first need to compute the derivative of the function \(f(x) = \frac{1}{x}\). The derivative, \(f'(x)\), represents the slope of the tangent line. Use the power rule for derivatives, which gives: \[f'(x) = -\frac{1}{x^2}.\]
03
Evaluate the function and its derivative at the point
Evaluate the function and its derivative at \(x = 1\). 1. \(f(1) = \frac{1}{1} = 1\)2. \(f'(1) = -\frac{1}{1^2} = -1\) This means the function value at \(x=1\) is 1 and the slope of the tangent line is -1.
04
Use the point-slope form to write the equation of the tangent line
The equation of the tangent line can be written using the point-slope form: \(y - y_1 = m(x - x_1)\), where \(m\) is the slope, and \((x_1, y_1)\) is the point of tangency.Substitute \(m = -1\), \(x_1 = 1\), and \(y_1 = 1\):\[y - 1 = -1(x - 1).\]
05
Simplify the equation of the tangent line
Expand and simplify the equation from the previous step:1. Distribute the \(-1\): \[y - 1 = -x + 1.\]2. Rearrange to the more familiar linear form: \[y = -x + 2.\]This equation, \(y = -x + 2\), represents the tangent line approximation of \(f(x) = \frac{1}{x}\) near \(x = 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative of a Function
The derivative of a function is a fundamental concept in calculus that measures how a function changes as its input changes. It describes the rate of change or the slope of the function at any point. For the given function, \( f(x) = \frac{1}{x} \), the derivative helps us find the slope of the tangent line at a specific point. To compute this, we apply the power rule, which is especially handy for functions like \( \frac{1}{x} \).
To use the power rule, rewrite \( f(x) \) as \( x^{-1} \). The power rule states that if \( f(x) = x^n \), then \( f'(x) = nx^{n-1} \). Therefore, the derivative \( f'(x) \) of our function is:
To use the power rule, rewrite \( f(x) \) as \( x^{-1} \). The power rule states that if \( f(x) = x^n \), then \( f'(x) = nx^{n-1} \). Therefore, the derivative \( f'(x) \) of our function is:
- Apply the exponent: \( -1 \times x^{-2} = -\frac{1}{x^2} \).
Point-Slope Form
The point-slope form provides a straightforward way to write the equation of a line when you know a point on the line and the slope. This form is a staple in algebra and calculus for equations of lines. In general, the point-slope form is written as:
For the function \( f(x) = \frac{1}{x} \), we previously calculated that at \( x = 1 \), the slope \( m \) is \( -1 \) and the point of tangency is \( (1, 1) \). Substituting these into the point-slope form, the equation becomes:
- \( y - y_1 = m(x - x_1) \),
For the function \( f(x) = \frac{1}{x} \), we previously calculated that at \( x = 1 \), the slope \( m \) is \( -1 \) and the point of tangency is \( (1, 1) \). Substituting these into the point-slope form, the equation becomes:
- \( y - 1 = -1(x - 1) \).
Linear Approximation
Linear approximation, also known as the tangent line approximation, is a method used to approximate the value of a function at a given point using the tangent line. It provides a simple way to make predictions about a function's value when it's difficult to compute the actual value of a function directly.
The approximation works best when you're close to the point of tangency. In the case of \( f(x) = \frac{1}{x} \) at \( x = 1 \), the tangent line approximation is described by the equation \( y = -x + 2 \). This linear function serves to estimate the values of \( f(x) \) near \( x = 1 \).
Linear approximation essentially replaces the curved behavior of a function with the straight line behavior of the tangent line. This is particularly useful:
The approximation works best when you're close to the point of tangency. In the case of \( f(x) = \frac{1}{x} \) at \( x = 1 \), the tangent line approximation is described by the equation \( y = -x + 2 \). This linear function serves to estimate the values of \( f(x) \) near \( x = 1 \).
Linear approximation essentially replaces the curved behavior of a function with the straight line behavior of the tangent line. This is particularly useful:
- When dealing with small Δx values, where the function doesn't deviate much from the tangent line.
- In contexts where computational simplicity is critical, and linear equations offer that simplicity.