/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Find the derivatives of the give... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the derivatives of the given functions. Assume that \(a, b, c,\) and \(k\) are constants. $$y=x^{4 / 3}$$

Short Answer

Expert verified
The derivative is \(\frac{dy}{dx} = \frac{4}{3}x^{1/3}\).

Step by step solution

01

Identify the Power Function

The given function is a power function of the form \(y = x^{4/3}\). Here, the exponent \(n = \frac{4}{3}\) is a positive fraction.
02

Apply the Power Rule for Derivatives

The power rule for differentiation states that if \(y = x^n\), then the derivative \(\frac{dy}{dx} = nx^{n-1}\). Apply this rule to the function \(y = x^{4/3}\).
03

Calculate the Derivative

Using the power rule, the derivative of \(y = x^{4/3}\) is \(\frac{dy}{dx} = \frac{4}{3}x^{4/3 - 1}\). Next, simplify the exponent \(4/3 - 1\) to get \(1/3\).
04

Write the Final Derivative

The derivative is \(\frac{dy}{dx} = \frac{4}{3}x^{1/3}\). This is the simplified form of the derivative of the original function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

power function
In mathematics, a power function is one where the variable is raised to a constant power. Simply put, it has the form \( y = x^n \), where \( n \) can be any real number, including fractions like in this example. Unlike in linear functions where the power of \( x \) is 1, in power functions, the exponent \( n \) can be any value such as positive, negative, or fractional. The function \( y = x^{4/3} \) falls into this category because the variable \( x \) is raised to the power of \( 4/3 \). This kind of function is common in algebra and calculus as it provides a foundational structure for more complex equations. An understanding of power functions helps us easily recognize situations where the power rule for derivatives applies.
power rule for derivatives
The power rule for derivatives is a quick and efficient method for finding the derivative of a function involving a power of \( x \). This rule states that if you have a function \( y = x^n \), the derivative, denoted as \( \frac{dy}{dx} \), is found using the formula \( nx^{n-1} \). Here’s how it works: you take the exponent \( n \), multiply by \( x \), and then reduce the exponent by 1. For our function \( y = x^{4/3} \), by applying the power rule:
  • First, identify \( n = 4/3 \).
  • Then, multiply the whole expression by \( 4/3 \), getting \( \frac{4}{3}x \).
  • Finally, subtract 1 from the exponent to achieve \( x^{1/3} \).
This procedure efficiently simplifies complex differentiation tasks. It's a fundamental rule that makes handling polynomial and power functions much simpler in calculus.
differentiation
Differentiation is a process in calculus used to find the rate at which a function is changing at any given point. In simple terms, it's about finding the derivative; which tells us how one quantity changes with another. Differentiation is crucial in understanding trends in mathematics, physics, engineering, and economics.When dealing with power functions, differentiation becomes straightforward with the power rule. For example, in the problem \( y = x^{4/3} \), differentiating involves systematically applying the power rule to find \( \frac{dy}{dx} \), which gives the slope of the tangent line at any point on the curve of the given function. Differentiation is not just about calculating derivatives; it helps understand the behavior of functions. Whether a function is increasing, decreasing, or maintaining a constant slope is determined through its derivative. Thus, understanding the differentiation process means being able to solve real-world problems by analyzing how values change in relation to each other.

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Most popular questions from this chapter

Suppose that \(f^{\prime \prime}\) and \(g^{\prime \prime}\) exist and that \(f\) and \(g\) are concave up for all \(x .\) Are the statements in Problems \(91-92\) true or false for all such \(f\) and \(g\) ? If a statement is true, explain how you know. If a statement is false, give a counterexample. \(f(x)-g(x)\) cannot be concave up for all \(x\)

Find the equations of the tangent lines to the graph of \(f(x)=\sin x\) at \(x=0\) and at \(x=\pi / 3 .\) Use each tangent line to approximate \(\sin (\pi / 6) .\) Would you expect these results to be equally accurate, since they are taken equally far away from \(x=\pi / 6\) but on opposite sides? If the accuracy is different, can you account for the difference?

The number of years, \(T\), it takes an investment of \(\$ 1000\) to grow to \(\$ F\) in an account which pays \(5 \%\) interest compounded continuously is given by $$T=g(F)=20 \ln (0.001 F)$$ Find \(g(5000)\) and \(g^{\prime}(5000) .\) Give units with your answers and interpret them in terms of money in the account.

If \(x=\cosh t\) and \(y=\sinh t,\) explain why the point \((x, y)\) always lies on the curve \(x^{2}-y^{2}=1 .\) (This curve is called a hyperbola and gave this family of functions its name.)

(a) Find the equation of the best quadratic approximation to \(y=\ln x\) at \(x=1 .\) The best quadratic approximation has the same first and second derivatives as \(y=\ln x\) at \(x=1\) (b) Use a computer or calculator to graph the approximation and \(y=\ln x\) on the same set of axes. What do you notice? (c) Use your quadratic approximation to calculate approximate values for \(\ln (1.1)\) and \(\ln (2)\)

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