Chapter 3: Problem 10
Find the derivative. It may be to your advantage to simplify before differentiating. Assume \(a, b, c,\) and \(k\) are constants. $$f(x)=e^{\ln \left(e^{2 x^{2}+3}\right)}$$
Short Answer
Expert verified
The derivative is \( f'(x) = 4x \cdot e^{2x^2 + 3} \).
Step by step solution
01
Recognize the Simplification
Notice that the function involves an exponential and a logarithm base of the same type. Specifically, the function is given as \( f(x) = e^{\ln(e^{2x^2 + 3})} \). This can be simplified directly using the property \( e^{\ln(a)} = a \).
02
Simplify the Function
Apply the exponential and logarithmic property: \( e^{\ln(e^{2x^2 + 3})} = e^{2x^2 + 3} \). Hence, the function simplifies to \( f(x) = e^{2x^2 + 3} \).
03
Differentiate the Simplified Function
Use the chain rule to differentiate \( f(x) = e^{2x^2 + 3} \). The derivative of \( e^{u} \) with respect to \( x \) is \( e^{u} \cdot u' \), where \( u = 2x^2 + 3 \) and \( u' = \frac{d}{dx}(2x^2 + 3) = 4x \).
04
Apply the Chain Rule
Now, apply the chain rule to get the derivative: \( f'(x) = e^{2x^2 + 3} \cdot 4x \).
05
Finalize the Solution
The solution to the derivative is simplified to \( f'(x) = 4x \cdot e^{2x^2 + 3} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a method in calculus used to differentiate composite functions. This rule is particularly helpful when dealing with functions nested within each other. In simpler terms, if you have a function inside another function, you'll need the chain rule to differentiate it.
Let's break it down:
This powerful technique simplifies differentiation when dealing with complex functions.
Let's break it down:
- Imagine you have a function of the form: \( f(g(x)) \).
- To find its derivative, you differentiate the outer function \( f \) as if \( g(x) \) were just a variable, and then multiply by the derivative of the inner function \( g(x) \).
This powerful technique simplifies differentiation when dealing with complex functions.
Exponential Functions
Exponential functions raise a constant base, usually \( e \), to a power, which may involve a variable. These functions have unique properties, making them deeply significant in calculus and mathematical applications.
The function \( f(x) = e^{2x^2 + 3} \) from the original exercise is a prime example of an exponential function:
The function \( f(x) = e^{2x^2 + 3} \) from the original exercise is a prime example of an exponential function:
- It features the constant base \( e \), Euler's number, known for its natural growth occurring in various contexts.
- The exponent \( 2x^2 + 3 \) contains the variable, adding complexity.
- The derivative of \( e^u \) with respect to \( x \) is \( e^u \cdot u' \), where \( u' \) is the derivative of the exponent \( u \).
- This makes exponential functions retain their structure post-differentiation, a fascinating trait in calculus.
Derivative Simplification
Before differentiating, simplifying a function can make the process significantly easier. Simplification reduces clutter and potential errors in complex calculus problems.
In the given exercise, simplifying the function \( f(x) = e^{\ln(e^{2x^2 + 3})} \) initially seems daunting. However, utilizing properties of exponentials and logarithms can help:
In the given exercise, simplifying the function \( f(x) = e^{\ln(e^{2x^2 + 3})} \) initially seems daunting. However, utilizing properties of exponentials and logarithms can help:
- Recall that \( e^{\ln(a)} = a \). This means the composition of an exponential and its inverse logarithm simplifies directly to \( a \).
- Thus, the given function simplifies to \( f(x) = e^{2x^2 + 3} \), a much more straightforward form for differentiation.
- Reduces the complexity of the expression.
- Streamlines the application of the chain rule.