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Explain what is wrong with the statement. A function \(f\) that is not differentiable at \(x=0\) has a graph with a sharp corner at \(x=0\).

Short Answer

Expert verified
The statement is incorrect; non-differentiability can also arise from vertical tangents or discontinuities, not just sharp corners.

Step by step solution

01

Understand Differentiability

A function is said to be differentiable at a point if the derivative exists at that point. Geometrically, this means that the graph of the function has a well-defined tangent line at that point.
02

Examine Sharp Corners

A sharp corner in the graph of a function at a certain point implies that the function is not differentiable at that point. This is because at a sharp corner, the slope of the tangent line is not defined due to the abrupt change in direction.
03

Consider Other Cases of Non-Differentiability

A function might be non-differentiable at a point for reasons other than sharp corners. For instance, a vertical tangent or a discontinuity at the point can also make a function non-differentiable.
04

Analyze the Error in the Statement

The error in the statement is the implication that the only reason for a function to not be differentiable at a point is due to a sharp corner. While sharp corners do cause non-differentiability, they are not the sole reason. Therefore, the statement is too restrictive and does not cover other cases of non-differentiability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sharp Corners
In understanding differentiability, sharp corners are a key concept. When a function's graph has a **sharp corner** at a point, it indicates that the function is not differentiable there. This occurs because the slope of the tangent line changes abruptly, resulting in an undefined derivative at that point.
For example, consider the absolute value function, \[f(x) = |x|\]This function has a sharp corner at \(x = 0\), where it transitions from a slope of -1 to a slope of 1. Because of this sudden direction change, it's impossible to draw a single tangent line at this point that perfectly matches the graph.
In summary:
  • A sharp corner results in non-differentiability.
  • The slope of the tangent line is undefined at sharp corners.
Thus, while sharp corners do indeed render a function non-differentiable at a point, remember, they're not the only reason.
Vertical Tangent
A vertical tangent presents another situation where differentiability fails. Unlike sharp corners, where the slope is undefined due to abrupt changes, vertical tangents have a slope that tends to infinity.
Imagine examining a curve that shoots nearly vertically up or down as you approach a particular point. At such points, the tangent line, though existent, rises straight up and thus has an infinite slope.Consider the function:\[f(x) = \sqrt[3]{x}\]At \(x = 0\), the graph of the function has a vertical tangent. The derivative, approaching this point, becomes extremely large and undefined (infinite in magnitude), rendering the function non-differentiable at that spot.
Key points to remember include:
  • Vertical tangents lead to an undefined infinite slope.
  • These occur when the graph of the function sharply turns inward, making differentiability impossible at those points.
Discontinuity
Discontinuity provides yet another insight into the concept of non-differentiability. A function can be non-differentiable at points where it is discontinuous. This means if there's a "jump" or "break" in the graph at a certain point, the function cannot possess a derivative there.
For instance, any point on a step function has a discontinuity that results in the absence of any tangent line, as the graph literally breaks or jumps at those points.
Think of discontinuity in these terms:
  • Discontinuities prevent a smooth connection in the graph.
  • If a function is not continuous at a point, it cannot be differentiable at that point.
Each of these concepts—sharp corners, vertical tangents, and discontinuities—serve as valid instances where a function can lack differentiability, demonstrating that it's not just sharp corners that lead to such conditions.

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Most popular questions from this chapter

Are the statements true or false? If a statement is true, give an example illustrating it. If a statement is false, give a counterexample. If a function is not differentiable, then it is not continuous.

The table gives the number of passenger cars, \(C=f(t)\) in millions, \(^{13}\) in the US in the year \(t\) (a) Do \(f^{\prime}(t)\) and \(f^{\prime \prime}(t)\) appear to be positive or negative during the period \(1975-1990 ?\) (b) Do \(f^{\prime}(t)\) and \(f^{\prime \prime}(t)\) appear to be positive or negative during the period \(1990-2000 ?\) (c) Estimate \(f^{\prime}(2005) .\) Using units, interpret your answer in terms of passenger cars. $$\begin{array}{c|c|c|c|c|c|c|c} \hline t & 1975 & 1980 & 1985 & 1990 & 1995 & 2000 & 2005 \\ \hline C & 106.7 & 121.6 & 127.9 & 133.7 & 128.4 & 133.6 & 136.6 \\ \hline \end{array}$$

The cost, \(C\) (in dollars), to produce \(q\) quarts of ice cream is \(C=f(q) .\) In each of the following statements, what are the units of the two numbers? In words, what does each statement tell us? (a) \(\quad f(200)=600\) (b) \(\quad f^{\prime}(200)=2\)

Give an example of: A function giving the position of a particle that has the same speed at \(t=-1\) and \(t=1\) but different velocities.

An economist is interested in how the price of a certain item affects its sales. At a price of \(p\), a quantity, \(q,\) of the item is sold. If \(q=f(p),\) explain the meaning of each of the following statements: (a) \(\quad f(150)=2000\) (b) \(\quad f^{\prime}(150)=-25\)

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