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Are the statements true or false? Give an explanation for your answer. The solutions of the differential equation \(d y / d x=x^{2}+\) \(y^{2}+1\) are concave up at every point.

Short Answer

Expert verified
False. The second derivative can be negative for some values of \( x \) and \( y \).

Step by step solution

01

Understanding Concavity

Solutions of a differential equation being concave up means their second derivatives are positive. We need to work with the given differential equation to understand this behavior.
02

Given Differential Equation

The differential equation given is \( \frac{dy}{dx} = x^2 + y^2 + 1 \).
03

Second Derivative Implication

To analyze concavity, find the second derivative \( \frac{d^2 y}{d x^2} \). The function is concave up where \( \frac{d^2 y}{d x^2} > 0 \).
04

Find the Second Derivative

To find \( \frac{d^2 y}{d x^2} \), differentiate \( \frac{dy}{dx} = x^2 + y^2 + 1 \) with respect to \( x \). This yields \( \frac{d^2 y}{d x^2} = 2x + 2y \frac{dy}{dx} \).
05

Substitute \( \frac{dy}{dx} \)

Substitute \( \frac{dy}{dx} = x^2 + y^2 + 1 \) into the second derivative: \( \frac{d^2 y}{d x^2} = 2x + 2y(x^2 + y^2 + 1) \).
06

Condition for Concavity

Analyze when \( 2x + 2y(x^2 + y^2 + 1) > 0 \). This is not always true for all \( x \) and \( y \).
07

Conclusion on Concavity

Since \( \frac{d^2 y}{d x^2} = 2x + 2y(x^2 + y^2 + 1) \) can be negative for some values of \( x \) and \( y \), the statement is false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Concavity and its Importance
Concavity is an important concept in calculus that helps us understand the shape of a function's graph. It is related to the curvature or bending of the graph. A function is said to be *concave up* at a point if, when you draw a tangent line at that point, the graph of the function lies above the tangent line. This often resembles a bowl that opens upward. Similarly, a function is *concave down* if the graph lies below the tangent line, resembling a bowl that opens downward.

To determine concavity, we rely on the second derivative of the function. If the second derivative is positive (\( \frac{d^2 y}{d x^2} > 0 \)), the function is concave up at that point. If it is negative (\( \frac{d^2 y}{d x^2} < 0 \)), the function is concave down. This is why the second derivative is crucial for analyzing concavity, as it gives us a precise mathematical tool to determine the nature of the function's curvature.
Understanding the Second Derivative
The second derivative of a function is derived by differentiating the first derivative, essentially capturing changes in the rate of change or the *acceleration* of the function. For any function, let's call it \( y=f(x) \), the first derivative \( \frac{dy}{dx} \) tells us the rate of change or slope of the function at any point. Differentiating this result again, we obtain the second derivative \( \frac{d^2y}{dx^2} \).
  • If \( \frac{d^2y}{dx^2} > 0 \), the function is accelerating and the slope is increasing, suggesting the graph is curving upwards.
  • If \( \frac{d^2y}{dx^2} < 0 \), the function is decelerating, and the slope is decreasing, suggesting the graph is curving downwards.
This is crucial when examining the solutions to differential equations, as it helps identify the concavity and the overall behavior of such solutions without plotting every single point on a graph.
Solving Differential Equations for Shape Insight
When dealing with differential equations, solving them gives us insights into the function \( y \) itself. The example in our exercise involves the equation \( \frac{dy}{dx} = x^2 + y^2 + 1 \). To understand the shape of the solution more deeply, we examine not just the first derivative but also the second derivative.

In the process of analyzing this differential equation, we derived the second derivative as \( \frac{d^2 y}{d x^2} = 2x + 2y(x^2 + y^2 + 1) \). We then explored the conditions under which this expression is greater than zero, as this would imply the solutions are concave up. However, as shown, this inequality does not hold for all values of \( x \) and \( y \), leading us to the conclusion that the function isn't always concave up.

This approach underscores the importance of differential equations as tools for revealing qualitative properties of functions. By understanding both derivatives, students gain a comprehensive view of how solutions behave, leading to better intuition about possible graphs and curves described by these equations.

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Most popular questions from this chapter

Decide whether the statement is true or false. Assume that \(y=f(x)\) is a solution to the equation \(d y / d x=2 x-y .\) Justify your answer. $$f^{\prime}(x)=2 x-f(x)$$

An object of mass \(m\) is thrown vertically upward from the surface of the earth with initial velocity \(v_{0} .\) We will calculate the value of \(v_{0},\) called the escape velocity, with which the object can escape the pull of the gravity and never return to earth. since the object is moving far from the surface of the earth, we must take into account the variation of gravity with altitude. If the acceleration due to gravity at sea level is \(g,\) and \(R\) is the radius of the earth, the gravitational force, \(F\), on the object of mass \(m\) at an altitude \(h\) above the surface of the earth is given by $$F=\frac{m g R^{2}}{(R+h)^{2}}$$. (a) The velocity of the object (measured upward) is \(v\) at time \(t .\) Use Newton's Second Law of Motion to show that $$\frac{d v}{d t}=-\frac{g R^{2}}{(R+h)^{2}}$$. (b) Rewrite this equation with \(h\) instead of \(t\) as the independent variable using the chain rule \(\frac{d v}{d t}=\frac{d v}{d h} \cdot \frac{d h}{d t}\) Hence, show that $$v \frac{d v}{d h}=-\frac{g R^{2}}{(R+h)^{2}}$$. (c) Solve the differential equation in part (b). (d) Find the escape velocity, the smallest value of \(v_{0}\) such that \(v\) is never zero.

Is the statement true or false? Assume that \(y=f(x)\) is a solution to the equation \(d y / d x=g(x) .\) If the statement is true, explain how you know. If the statement is false, give a counterexample. If \(g(x)\) is even, then \(f(x)\) is odd.

According to an article in The New York Times,' ' pigweed has acquired resistance to the weedkiller Roundup. Let \(N\) be the number of acres, in millions, where Roundup-resistant pigweed is found. Suppose the relative growth rate, \((1 / N) d N / d t,\) was \(15 \%\) when \(N=5\) and \(14.5 \%\) when \(N=10 .\) Assuming the relative growth rate is a linear function of \(N,\) write a differential equation to model \(N\) as a function of time, and predict how many acres will eventually be afflicted before the spread of Roundup-resistant pigweed halts.

Is the statement true or false? Assume that \(y=f(x)\) is a solution to the equation \(d y / d x=g(x) .\) If the statement is true, explain how you know. If the statement is false, give a counterexample. If \(g(0)=1\) and \(g(x)\) is increasing for \(x \geq 0,\) then \(f(x)\) is also increasing for \(x \geq 0.\)

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