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Families of curves often arise as solutions of differential equations. Match the families of curves with the differential equations of which they are solutions. (a) \(\frac{d y}{d x}=\frac{y}{x}\) (b) \(\frac{d y}{d x}=k y\) (c) \(\frac{d y}{d x}=k y+\frac{y}{x}\) (d) \(\frac{d y}{d x}=\frac{k y}{x}\) (1) \(y=x e^{k x}\) (II) \(y=x^{k}\) (III) \(y=e^{k x}\) (IV) \(y=k x\)

Short Answer

Expert verified
(a)-(IV), (b)-(III), (c)-(1), (d)-(II).

Step by step solution

01

Analyzing Differential Equation (a)

The differential equation is \( \frac{d y}{d x} = \frac{y}{x} \). Recognize this as a separable equation where you can separate the variables to solve. Rewriting it gives \( \frac{1}{y} \, dy = \frac{1}{x} \, dx \). Integrating both sides yields \( \ln |y| = \ln |x| + C \), where \( C \) is the integration constant. Solving for \( y \), we find \( y = Cx \). Since \( y = kx \) (option IV) resembles this form, (a) matches (IV).
02

Analyzing Differential Equation (b)

The differential equation is \( \frac{d y}{d x} = ky \). This is a standard first-order linear differential equation with the known solution \( y = Ce^{kx} \). \( y = Ce^{kx} \) can be a constant multiple of \( y = e^{kx} \), making it similar to option (III) (ignoring \( C \)); hence (b) matches (III).
03

Analyzing Differential Equation (c)

The differential equation is \( \frac{d y}{d x} = ky + \frac{y}{x} \). To solve this, factor \( y \) out: \( \frac{d y}{d x} = y(k + \frac{1}{x}) \). This equation suggests that \( y = x^ke^{kx} \), which can be rewritten to fit (1), if you make adjustable constants align, thus (c) matches (1).
04

Analyzing Differential Equation (d)

The equation given is \( \frac{d y}{d x} = \frac{k y}{x} \). Comparing this to the known form for power functions, \( y = x^k \), suggests a power function is the solution. Therefore, by matching the structure, we identify (d) matches with (II), which is \( y = x^k \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First-Order Differential Equations
Differential equations refer to equations involving derivatives, expressing how a quantity changes in relation to another. Among these, **first-order differential equations** are particularly fundamental because they provide a starting point for solving more complex differential equations. They are called "first-order" because they involve first derivatives, such as \( \frac{dy}{dx} \).In essence, these equations involve a function \( y \) and its derivative. Solving them often involves finding a function \( y(x) \) that satisfies the equation for different potential values of \( x \). A classic example is the linear first-order differential equation \( \frac{dy}{dx} = ky \), where \( k \) is a constant, leading to an exponential solution.
**Why are they important?**- Fundamental building block in differential equations- Useful in describing real-world phenomena like growth ratesTo solve such equations, certain methods are employed, like the integration of separable equations or using integrating factors, especially if the equations are linear. With proper techniques, first-order differential equations provide useful insights into the behavior of dynamic systems.
Separable Equations
**Separable equations** are a specific type of first-order differential equation. These equations can be rewritten so that all terms involving the variable \( x \) and its differential \( dx \) are on one side, while all terms involving \( y \) and \( dy \) are on the other. This is what makes them 'separable'.
For example, consider the differential equation: \( \frac{dy}{dx} = \frac{y}{x} \). It can be rewritten as:
  1. \( \frac{1}{y} \, dy = \frac{1}{x} \, dx \)
  2. Integrate both sides to find: \( \ln|y| = \ln|x| + C \)
  3. Solving for \( y \), we get: \( y = Cx \)
Separation of variables is a powerful technique due to its simplicity and the wide range of problems it can solve.
**Benefits of using separable equations:**
  • Easy to apply method
  • Simplifies solving first-order problems
This technique is pivotal for students as it introduces the practical application of integration to potent mathematical problems.
Linear Differential Equations
**Linear differential equations** are another essential category of first-order differential equations. These equations are characterized by linearity in the unknown function and its derivatives. They take the form \( \frac{dy}{dx} + P(x)y = Q(x) \).A particular subclass is linear first-order equations with constant coefficients, such as \( \frac{dy}{dx} = ky \), where solutions are typically exponential functions like \( y = Ce^{kx} \). An important method for solving these equations involves integrating factors, which transform a non-solvable equation into one that can be integrated directly.
**Key characteristics:**
  • The function and its derivative appear linearly
  • Easy to solve using systematic methods
For example, when you have an equation in the form \( \frac{dy}{dx} = ky + \frac{y}{x} \), it combines aspects of both linearity and separation of terms, demonstrating flexibility in solving strategies. Understanding linear differential equations allows students to advance to more complex dynamics in advanced mathematics and physics applications. They offer straightforward mechanisms to model and predict real-world behaviors.

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Most popular questions from this chapter

Decide whether the statement is true or false. Assume that \(y=f(x)\) is a solution to the equation \(d y / d x=2 x-y .\) Justify your answer. If \(f(1)=5,\) then (1,5) could be a critical point of \(f\)

Sketch solution curves with a variety of initial values for the differential equations. You do not need to find an equation for the solution. \(\frac{d y}{d t}=\alpha-y,\) where \(\alpha\) is a positive constant.

(a) A cup of coffee is made with boiling water and stands in a room where the temperature is \(20^{\circ} \mathrm{C}\) If \(H(t)\) is the temperature of the coffee at time \(t,\) in minutes, explain what the differential equation $$\frac{d H}{d t}=-k(H-20)$$ says in everyday terms. What is the sign of \(k ?\) (b) Solve this differential equation. If the coffee cools to \(90^{\circ} \mathrm{C}\) in 2 minutes, how long will it take to cool to \(60^{\circ} \mathrm{C}\) degrees?

The amount of radioactive carbon- 14 in a sample is measured using a Geiger counter, which records each disintegration of an atom. Living tissue disintegrates at a rate of about 13.5 atoms per minute per gram of carbon. In 1977 a charcoal fragment found at Stonehenge, England, recorded 8.2 disintegrations per minute per gram of carbon. Assuming that the half-life of carbon- 14 is 5730 years and that the charcoal was formed during the building of the site, estimate the date at which Stonehenge was built.

Consider a conflict between two armies of \(x\) and \(y\) soldiers, respectively. During World War I, F. W. Lanchester assumed that if both armies are fighting a conventional battle within sight of one another, the rate at which soldiers in one army are put out of action (killed or wounded) is proportional to the amount of fire the other army can concentrate on them, which is in turn proportional to the number of soldiers in the opposing army. Thus Lanchester assumed that if there are no reinforcements and \(t\) represents time since the start of the battle, then \(x\) and \(y\) obey the differential equations $$\begin{array}{l} \frac{d x}{d t}=-a y \\ \frac{d y}{d t}=-b x \quad a, b>0 \end{array}$$. Near the end of World War II a fierce battle took place between US and Japanese troops over the island of Iwo Jima, off the coast of Japan. Applying Lanchester's analysis to this battle, with \(x\) representing the number of US troops and \(y\) the number of Japanese troops, it has been estimated \(^{31}\) that \(a=0.05\) and \(b=0.01\) (a) Using these values for \(a\) and \(b\) and ignoring reinforcements, write a differential equation involving \(d y / d x\) and sketch its slope field. (b) Assuming that the initial strength of the US forces was 54,000 and that of the Japanese was 21,500 draw the trajectory which describes the battle. What outcome is predicted? (That is, which side do the differential equations predict will win?) (c) Would knowing that the US in fact had 19,000 reinforcements, while the Japanese had none, alter the outcome predicted?

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