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Pick out which functions are solutions to which differential equations. (Note: Functions may be solutions to more than one equation or to none; an equation may have more than one solution.) (a) \(\frac{d y}{d x}=-2 y\) (b) \(\frac{d y}{d x}=2 y\) (c) \(\frac{d^{2} y}{d x^{2}}=4 y\) (d) \(\frac{d^{2} y}{d x^{2}}=-4 y\) (I) \(y=2 \sin x\) (II) \(y=\sin 2 x\) (III) \(y=e^{2 x}\) (IV) \(y=e^{-2 x}\)

Short Answer

Expert verified
(a) IV; (b) III; (c) III; (d) I, IV.

Step by step solution

01

Check y=2sin(x) for each differential equation

For differential equation (a) \( \frac{d y}{d x} = -2y \), calculate the derivative \( \frac{d}{dx}(2\sin{x}) = 2\cos{x} \). Substituting back, we get \( 2\cos{x} = -2(2\sin{x}) \), which is False. Repeat for other equations. Only (d) \( \frac{d^2 y}{d x^2} = -4y \) with \( \frac{d^2}{dx^2} (2\sin{x}) = -2\sin{x} \) holds.
02

Check y=sin(2x) for each differential equation

For differential equation (a), calculate \( \frac{d}{dx}(\sin{2x}) = 2\cos{2x} \). Substituting back, we get \( 2\cos{2x} = -2(\sin{2x}) \), which is False. Check other equations similarly. None satisfy the given equations.
03

Check y=e^{2x} for each differential equation

For differential equation (b) \( \frac{d y}{d x} = 2 y \), calculate \( \frac{d}{dx}(e^{2x}) = 2e^{2x} \). Substituting back, we find \( 2e^{2x} = 2e^{2x} \), which is True. Also check (c) \( \frac{d^2 y}{d x^2} = 4 y \). Both equations work with this function.
04

Check y=e^{-2x} for each differential equation

For differential equation (a), \( \frac{d}{dx}(e^{-2x}) = -2e^{-2x} \), which satisfies \( \frac{d y}{d x} = -2y \). Also check equation (d) \( \frac{d^2 y}{d x^2} = -4 y \). Both equations hold

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solutions to Differential Equations
Differential equations describe relationships between functions and their derivatives, and solutions to these equations are functions that satisfy these relationships. To check if a function is a solution to a particular differential equation, you need to plug it into the equation and see if equality holds.
Typically, the process involves taking derivatives of the proposed solution function and substituting them back into the differential equation. If both sides of the equation are equal after substitution, the function can be considered a solution.
  • For example, if we have the differential equation \( \frac{d y}{d x} = 2 y \) and a candidate solution \( y = e^{2x} \), by differentiating and substituting, we verify if the function is valid.
  • In problem-solving, multiple functions might satisfy a single differential equation, and each function can often be a solution to more than one equation.
Second-Order Differential Equations
A second-order differential equation involves the second derivative of a function. Such equations are critically important in modeling various physical systems, including motion, waves, and many more phenomena.
To check a function against a second-order differential equation, calculate both the first and second derivatives, then substitute into the equation.
For instance, given the second-order differential equation \( \frac{d^2 y}{d x^2} = -4 y \), to confirm that \( y = 2 \sin x \) is a solution, compute the second derivative and substitute back, checking if both sides match.
  • This principal function showcases how solutions might involve sinusoidal (trigonometric) functions when the equation itself has a harmonic form.
  • Second-order differential equations are often solved using characteristic equations, particularly when they have constant coefficients.
Exponential Functions
Exponential functions are frequently encountered in the solutions of differential equations due to their distinct property of self-derivative resemblance. Specifically, functions like \( e^{kx} \) (where \( k \) is a constant) maintain their form even after differentiation.
In the domain of differential equations, this property makes them ideal candidates for solutions involving both growth and decay processes.
  • An example includes solving \( \frac{d y}{d x} = 2 y \) with \( y = e^{2x} \), where differentiation leads to a result directly proportional to the original function.
  • Also, the characteristic of exponential functions aids in solving both ordinary and partial differential equations, especially those representing financial models and natural phenomena.
Trigonometric Functions
Trigonometric functions, like sine and cosine, are inextricably linked with differential equations, especially ones dealing with periodic phenomena such as waves and oscillations. These functions provide solutions primarily because their derivatives are cyclic or periodic.
When a differential equation has solutions of the form \( y = \sin(x) \) or \( y = \cos(x) \), it often implies the equation involves rotating or oscillatory motion.
  • The equation \( \frac{d^2 y}{d x^2} = -4 y \) demonstrates this, with solutions involving sine and cosine functions due to their natural cycles.
  • Trigonometric function solutions are essential in physics and engineering for describing and predicting wave patterns, harmonic oscillators, and signal analysis.

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Most popular questions from this chapter

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