/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Simplify the expressions complet... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Simplify the expressions completely. $$e^{\ln (1 / 2)}$$

Short Answer

Expert verified
The expression simplifies to \(1/2\).

Step by step solution

01

Recognize the Relationship between Exponentials and Logarithms

The expression provided is \(e^{\ln(1/2)}\). Recall that if we have an expression of the form \(e^{\ln(x)}\), it simplifies to \(x\) because the exponential function \(e^x\) and the natural logarithm \(\ln(x)\) are inverse functions.
02

Apply the Identity to Simplify

Using the identity from Step 1, recognize that \(e^{\ln(1/2)}\) simplifies directly to \(1/2\). Therefore, the expression simplifies to \(1/2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Functions
Inverse functions are pairs of functions that reverse each other's effects. When one function is applied to a value, and then its inverse is applied to the result, you end up back at the original value. This concept is important in many areas of mathematics, especially with exponential and logarithmic functions.
Consider the exponential function, written as \( e^x \) and its inverse, the natural logarithm function, written as \( \ln(x) \). These functions have a special relationship:- When you take an exponential value and apply the natural logarithm to it, you return to the original exponent value: \( \ln(e^x) = x \). - Conversely, if you take the natural logarithm of a number and apply the exponential function, you revert to the original number: \( e^{\ln(x)} = x \) (for \(x > 0\)).
These properties show how inverse functions work, letting us simplify expressions by undoing one operation with the other.
Simplification
Simplifying expressions in mathematics involves reducing them to their most basic form without changing their value. The purpose of simplification is to make expressions easier to understand and work with. In the context of inverse functions, understanding the properties of inverses is crucial for simplification.
For example, given the expression \( e^{\ln(1/2)} \), we can apply our knowledge of inverse functions to simplify it directly:- Identify that the expression is in the form \( e^{\ln(x)} \). - Recognize that due to the inverse relationship, this simplifies directly to \( x \). Therefore, \( e^{\ln(1/2)} \) simplifies to \( 1/2 \).
Understanding how to identify and apply these inverse function properties helps in reducing complex expressions swiftly and correctly.
Natural Logarithm
The natural logarithm, denoted as \( \ln(x) \), is a logarithm with base \(e\), where \(e\) is an irrational constant approximately equal to 2.71828. It's a common logarithmic function used in calculus and higher mathematics due to its unique properties in terms of growth and decay processes.
Some key properties of the natural logarithm include:
  • \( \ln(1) = 0 \), because \( e^0 = 1 \).
  • \( \ln(e) = 1 \), because \( e^1 = e \).
  • The function is defined for positive values of \(x\), meaning \( \ln(x) \) is only valid when \(x > 0\).
The natural logarithm is particularly useful in solving equations involving exponential growth or decay, as it allows us to "bring down" exponents using logarithmic identities. Hence, it's a fundamental tool for manipulation and simplification in equations dealing with exponential forms.

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Most popular questions from this chapter

Suppose \(f\) is an increasing function and \(g\) is a decreasing function. Give an example for \(f\) and \(g\) for which the statement is true, or say why such an example is impossible. \(f(x) g(x)\) is decreasing for all \(x\).

Which of the following statements is a direct consequence of the statement: "If \(f\) and \(g\) are continuous at \(x=a\) and \(g(a) \neq 0\) then \(f / g\) is continuous at \(x=a ?\) (a) If \(f\) and \(g\) are continuous at \(x=a\) and \(f(a) \neq 0\) then \(g / f\) is continuous at \(x=a\) (b) If \(f\) and \(g\) are continuous at \(x=a\) and \(g(a)=0\) then \(f / g\) is not continuous at \(x=a\) (c) If \(f, g,\) are continuous at \(x=a,\) but \(f / g\) is not continuous at \(x=a,\) then \(g(a)=0\) (d) If \(f\) and \(f / g\) are continuous at \(x=a\) and \(g(a) \neq 0\) then \(g\) is continuous at \(x=a\)

Suppose that \(\lim _{x \rightarrow 3} f(x)=7 .\) Are the statements in Problems \(89-95\) true or false? If a statement is true, explain how you know. If a statement is false, give a counterexample. $$\lim _{x \rightarrow 3}(x f(x))=21$$

For the functions in Problems \(46-53,\) do the following: (a) Make a table of values of \(f(x)\) for \(x=0.1,0.01,0.001\) \(0.0001,-0.1,-0.01,-0.001,\) and -0.0001 (b) Make a conjecture about the value of \(\lim _{x \rightarrow 0} f(x)\) (c) Graph the function to see if it is consistent with your answers to parts (a) and (b). (d) Find an interval for \(x\) near 0 such that the difference between your conjectured limit and the value of the function is less than \(0.01 .\) (In other words, find a window of height 0.02 such that the graph exits the sides of the window and not the top or bottom of the window.) $$f(x)=\frac{\sin 2 x}{x}$$

Give an example of: A function with a horizontal asymptote at \(y=-5\) and range \(y>-5\)

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