Chapter 9: Problem 47
Evaluate the integral. \(\int \sqrt{x} \sin \sqrt{x} d x\)
Short Answer
Expert verified
The integral evaluates to
\[ -x \cos(\sqrt{x}) + 2 \sqrt{x} \sin(\sqrt{x}) + 2 \cos(\sqrt{x}) + C \].
Step by step solution
01
Substitution
To simplify the integral, let's make a substitution. Let \( u = \sqrt{x} \). Then, \( x = u^2 \) and the differential \( dx = 2u \, du \). Consequently, the integral becomes \( \int \sqrt{x} \sin(\sqrt{x}) \, dx = \int u \sin u \, 2u \, du = 2 \int u^2 \sin u \, du \).
02
Integration by Parts Setup
We will use integration by parts to solve the integral \( 2 \int u^2 \sin u \, du \). Recall the formula for integration by parts: \( \int u \, dv = uv - \int v \, du \). Let's choose \( u = u^2 \) and \( dv = \sin u \, du \).
03
Differentiate and Integrate Parts
Differentiate \( u = u^2 \) to get \( du = 2u \, du \). Integrate \( dv = \sin u \, du \) to get \( v = -\cos u \). Now, apply the integration by parts formula: \( \int u^2 \sin u \, du = -u^2 \cos u + \int -2u \cos u \, du \).
04
Integration by Parts Again
The integral \( \int 2u \cos u \, du \) requires another application of integration by parts. Set \( u = 2u \) and \( dv = \cos u \, du \). Then, \( du = 2 \, du \) and \( v = \sin u \). The integral becomes \( 2(u \sin u - \int \sin u \, du) = 2(u \sin u + \cos u) \).
05
Combine Parts
Substitute back into the equation from Step 3, and simplify: \( -u^2 \cos u + (2u \sin u + 2\cos u) \). Factor out 2 to get: \( 2\left(-\frac{1}{2}u^2 \cos u + u \sin u + \cos u\right) \).
06
Resubstitute Original Variable
Remember \( u = \sqrt{x} \) from the original substitution \( u = \sqrt{x} \). Substitute back to get: \( -\sqrt{x}^2 \cos(\sqrt{x}) + 2 \sqrt{x} \sin(\sqrt{x}) + 2 \cos(\sqrt{x}) \). Simplify to \( -x \cos(\sqrt{x}) + 2 \sqrt{x} \sin(\sqrt{x}) + 2 \cos(\sqrt{x}) \).
07
Add Constant of Integration
Finally, don't forget to add the constant of integration \( C \) to represent the family of solutions. The final solution is: \( -x \cos(\sqrt{x}) + 2 \sqrt{x} \sin(\sqrt{x}) + 2 \cos(\sqrt{x}) + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
To tackle complex integrals, the substitution method is a handy tool that simplifies the integration process. The key idea behind substitution is to transform the original variable into a new one, making the integral easier to solve. In the case of the given problem, \(u = \sqrt{x}\) is chosen as the substitution. This transforms \(x\) into \(u^2\), which simplifies to: \(x = u^2\). The differential \(dx\) is converted using the derivative of \(u\), resulting in \(dx = 2u \, du\). Applying these changes to the integral results in:
- \(\int \sqrt{x} \sin(\sqrt{x}) \, dx = 2 \int u^2 \sin(u) \, du\)
Integration by Parts
Integration by parts is a powerful technique used to integrate products of functions. Based on the product rule for differentiation, it's perfect for integrals involving products like \(u^2 \sin u\), seen in the transformed integral from substitution. The integration by parts formula is:\[\int u \, dv = uv - \int v \, du\]In this problem, we choose:
- \(u = u^2\) with a differential of \(du = 2u \, du\)
- \(dv = \sin u \, du\), resulting in \(v = -\cos u\)
Definite and Indefinite Integrals
Understanding the distinction between definite and indefinite integrals is crucial in calculus. Both have unique roles:- **Indefinite Integrals**: These represent the family of all antiderivatives of a function. They are expressed with a constant \(C\), since any antiderivative plus a constant gives another antiderivative. The solution to our problem, \(-x \cos(\sqrt{x}) + 2 \sqrt{x} \sin(\sqrt{x}) + 2 \cos(\sqrt{x}) + C\), is an indefinite integral, noting the constant \(C\). - **Definite Integrals**: These compute the net area under a curve between specific limits. It results in a numerical value rather than an algebraic expression. Applying these concepts, the integral in the problem is indefinite, as there are no specified bounds. This allows the solution to express a general antiderivative of the integrand. Adding the constant \(C\) acknowledges the entire set of possible solutions that differ by a constant.