Chapter 9: Problem 29
Evaluate the integral. \(\int \frac{1}{x^{3 / 2}+x^{1 / 2}} d x\)
Short Answer
Expert verified
The integral evaluates to \(2 \arctan(x^{1/2}) + C\).
Step by step solution
01
Simplify the Denominator
First, factor the denominator \(x^{3/2} + x^{1/2}\). Rewrite it as: \[ x^{1/2}(x + 1) \] This simplifies the integral to: \[ \int \frac{1}{x^{1/2}(x + 1)} \, dx \]
02
Use Substitution
Use the substitution \(u = x^{1/2}\), which implies \(x = u^2\) and \(dx = 2u \, du\). Substitute these into the integral:\[ \int \frac{1}{u(u^2 + 1)} \, 2u \, du \]Simplify the integral:\[ \int \frac{2u}{u(u^2 + 1)} \, du = \int \frac{2}{u^2 + 1} \, du \]
03
Integrate the Substituted Function
The integral \(\int \frac{2}{u^2 + 1} \, du\) is a standard form which evaluates to:\[ 2 \arctan(u) + C \] where \(C\) is the constant of integration.
04
Back-substitute to Original Variable
Reverse the substitution by replacing \(u\) with \(x^{1/2}\) from our initial substitutions. Thus, \(\arctan(u)\) becomes \(\arctan(x^{1/2})\). The integral becomes:\[ 2 \arctan(x^{1/2}) + C \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful technique in integration. It's useful for simplifying complex integrals into more manageable forms. When you encounter an integral that looks challenging, try to identify a part of it that can be substituted with a new variable, say, \( u \). This new variable helps to transform the integral into a simpler one.
In the given exercise, we utilized the substitution \( u = x^{1/2} \). This choice was strategic because it helps in reducing the complexity of the expression \( x^{3/2} + x^{1/2} \) into simpler terms. After substitution, remember to express everything in terms of the new variable \( u \), including \( dx = 2u \, du \).
Always perform these steps when using substitution:
In the given exercise, we utilized the substitution \( u = x^{1/2} \). This choice was strategic because it helps in reducing the complexity of the expression \( x^{3/2} + x^{1/2} \) into simpler terms. After substitution, remember to express everything in terms of the new variable \( u \), including \( dx = 2u \, du \).
Always perform these steps when using substitution:
- Identify a component of the integrand to substitute. This should simplify the expression.
- Express \( dx \) or any differential in terms of \( du \).
- Substitute fully into the integral.
- Integrate the new, simpler expression.
- Finally, back-substitute the original variable to complete the solution.
Factorization
Factorization simplifies expressions and opens up multiple pathways for easier integration. It involves rewriting a mathematical expression as a product of its factors.
In our exercise, the expression \( x^{3/2} + x^{1/2} \) was factored by taking out a common factor. This changed it into \( x^{1/2}(x + 1) \). By spotting patterns or common components, you can often simplify what's inside an integral significantly.
Here are essential points to consider when working with factorization:
In our exercise, the expression \( x^{3/2} + x^{1/2} \) was factored by taking out a common factor. This changed it into \( x^{1/2}(x + 1) \). By spotting patterns or common components, you can often simplify what's inside an integral significantly.
Here are essential points to consider when working with factorization:
- Look for common terms in each part of the expression to factor out. This often makes the integral easier to handle.
- When dealing with polynomials, remember techniques like grouping or the difference of squares.
- Simplified terms can reveal substitution opportunities or standard integral forms.
Definite Integrals
Definite integrals allow you to calculate the exact area under a curve between two points \( a \) and \( b \). While our exercise tackled an indefinite integral, the techniques align closely with definite integrals using boundaries.
For definite integrals, consider the additional context:
For definite integrals, consider the additional context:
- Boundaries alter how you interpret the result, moving beyond just a function to a numerical value.
- Solving may include evaluating the antiderivative at these limits and subtracting: \( F(b) - F(a) \).
- Extra care is crucial when substituting because you must also adjust the limits according to the substitution.