Chapter 7: Problem 7
Evaluate the integral. (a) $$\int \tan 2 x d x$$ (b) $$\int_{0}^{\pi / 8} \tan 2 x d x$$
Short Answer
Expert verified
(a) \( \frac{1}{2} \ln |\sec 2x| + C \). (b) \( \frac{1}{4} \ln 2 \).
Step by step solution
01
Recall the Integral Formula for Tangent
The integral of \( \tan u \) with respect to \( u \) is \( \ln |\sec u| + C \). We need to use this formula, but first, the argument of \( \tan \) needs to be adjusted.
02
Use Substitution Method
Let \( u = 2x \), which implies \( du = 2dx \) or \( dx = \frac{1}{2} du \). This transforms the integral \( \int \tan 2x \, dx \) into \( \frac{1}{2} \int \tan u \, du \).
03
Integrate the Transformed Integral
Apply the integral formula for tangent: \( \int \tan u \, du = \ln |\sec u| + C \). Therefore, \( \frac{1}{2} \int \tan u \, du = \frac{1}{2} (\ln |\sec u| + C) = \frac{1}{2} \ln |\sec u| + C' \), where \( C' = \frac{1}{2}C \).
04
Substitute Back the Original Variable
Replace \( u \) with \( 2x \) in the antiderivative. Thus, the indefinite integral becomes \( \frac{1}{2} \ln |\sec 2x| + C' \).
05
Setup the Definite Integral
To solve \( \int_{0}^{\pi / 8} \tan 2x \, dx \), use the antiderivative \( \frac{1}{2} \ln |\sec 2x| \) and evaluate it at \( x = 0 \) and \( x = \pi/8 \).
06
Evaluate the Antiderivative at Upper Limit
Calculate \( \frac{1}{2} \ln |\sec(2 \times \frac{\pi}{8})| = \frac{1}{2} \ln |\sec(\frac{\pi}{4})| = \frac{1}{2} \ln \sqrt{2} \).
07
Evaluate the Antiderivative at Lower Limit
Calculate \( \frac{1}{2} \ln |\sec(2 \times 0)| = \frac{1}{2} \ln |\sec 0| = \frac{1}{2} \ln 1 = 0 \).
08
Compute the Definite Integral Result
Subtract the value at the lower limit from the value at the upper limit: \( \frac{1}{2} \ln \sqrt{2} - 0 = \frac{1}{2} \ln \sqrt{2} = \frac{1}{4} \ln 2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent Function
The tangent function, often denoted as \( \tan(x) \), represents a crucial concept in trigonometry. It is the ratio of the sine to the cosine of an angle. In simpler terms, for a given angle \( x \), the tangent function is defined as:
- \( \tan(x) = \frac{\sin(x)}{\cos(x)} \)
- Its graph shows repeating patterns called periods, with a typical period of \( \pi \) radians.
- As an odd function, it is symmetrical about the origin; thus, \( \tan(-x) = -\tan(x) \).
- It has vertical asymptotes wherever the cosine of \( x \) is zero, due to division by zero.
Integration by Substitution
Integration by substitution is a powerful technique to solve complex integrals. Essentially, it simplifies integrals by transforming them into a more workable form. This involves substituting part of the integral with a new variable, which often turns the integral into something more straightforward.
In this exercise, the substitution involved setting \( u = 2x \) and hence \( du = 2dx \), which transforms the given integral into:
This method shines particularly in cases where the integrand (the function being integrated) transforms into a familiar form, allowing us to apply basic integration formulas and then revert using the original variables.
In this exercise, the substitution involved setting \( u = 2x \) and hence \( du = 2dx \), which transforms the given integral into:
- \( \int \tan 2x \, dx = \frac{1}{2} \int \tan u \, du \)
This method shines particularly in cases where the integrand (the function being integrated) transforms into a familiar form, allowing us to apply basic integration formulas and then revert using the original variables.
Definite Integral
A definite integral computes the accumulation of quantities, like areas under curves, between specific limits. The integral from \( a \) to \( b \) of a function \( f(x) \) is denoted by the symbol:
- \( \int_{a}^{b} f(x) \, dx \)
- Evaluating the antiderivative at the upper limit (\( x = \pi/8 \)).
- Evaluating the antiderivative at the lower limit (\( x = 0 \)).
- Subtracting the lower limit result from the upper limit result.
Indefinite Integral
Indefinite integrals are solutions to differential equations and represent a family of functions. Unlike definite integrals, they don't have set limits and include an added constant \( C \), referred to as the constant of integration.
For the tangent function, integrating \( \int \tan u \, du \) provided us the result as:
For the tangent function, integrating \( \int \tan u \, du \) provided us the result as:
- \( \ln |\sec u| + C \)
- Representing general solutions rather than specific values.
- Including the constant acknowledges any number of vertical shifts of the elementary antiderivative function.