Chapter 7: Problem 26
Find \(f^{\prime}(x)\) if \(f(x)\) is the given expression. (a) \(\pi^{\pi}\) (b) \(x^{4}\) (c) \(x^{\pi}\) (d) \(\pi^{x}\) (e) \(x^{2 x}\)
Short Answer
Expert verified
(a) 0, (b) 4x^3, (c) \(\pi x^{\pi - 1}\), (d) \(\pi^{x} \ln(\pi)\), (e) \(2x^{2x}(\ln(x) + 1)\)."
Step by step solution
01
Understanding the Problem
We need to find the derivative \(f^{\prime}(x)\) for various forms of the function \(f(x)\). This requires us to apply different rules of differentiation depending on the form of \(f(x)\).
02
Find \(f^{\prime}(x)\) for \(f(x) = \pi^{\pi}\)
Since \(\pi^{\pi}\) is a constant, the derivative of a constant is 0. Therefore, \(f^{\prime}(x) = 0\).
03
Find \(f^{\prime}(x)\) for \(f(x) = x^{4}\)
To differentiate \(x^{4}\), we use the power rule, which states that \(\frac{d}{dx} x^n = nx^{n-1}\). Thus, \(f^{\prime}(x) = 4x^{3}\).
04
Find \(f^{\prime}(x)\) for \(f(x) = x^{\pi}\)
Applying the power rule where \(n = \pi\), which is a constant, gives us the derivative: \(f^{\prime}(x) = \pi x^{\pi - 1}\).
05
Find \(f^{\prime}(x)\) for \(f(x) = \pi^{x}\)
For functions of the form \(a^x\), the derivative is given by \(\pi^{x} \ln(\pi)\). So, \(f^{\prime}(x) = \pi^{x} \ln(\pi)\).
06
Find \(f^{\prime}(x)\) for \(f(x) = x^{2x}\)
Rewrite \(x^{2x}\) as \(e^{2x \ln(x)}\). Let's set \(u = 2x \ln(x)\), then \(f(x) = e^{u}\). The chain rule gives \(\frac{d}{dx}e^{u} = e^{u} \frac{du}{dx}\). We find \(\frac{du}{dx} = 2\ln(x) + 2\). Therefore, \(f^{\prime}(x) = e^{2x \ln(x)} (2\ln(x) + 2)\), simplifying to \(2x^{2x}(\ln(x) + 1)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
The power rule is a fundamental technique in calculus used to find the derivative of polynomials. It's applicable when you want to differentiate an expression where the variable is raised to a constant power. For a function in the form of \( f(x) = x^n \), the derivative is calculated by bringing down the exponent as a multiplier and then reducing the exponent by one. This is expressed as:
- \( \frac{d}{dx} x^n = nx^{n-1} \)
Chain Rule
The chain rule is a powerful tool for differentiating composite functions, which are functions of a method nested inside another. It is used when you have a composition \( g(f(x)) \) and want to differentiate with respect to \( x \). The formula for the chain rule is:
- \( \frac{d}{dx}g(f(x)) = g^{\prime}(f(x)) \cdot f^{\prime}(x) \)
- The derivative of \( e^{u} \) is \( e^{u} \cdot \frac{du}{dx} \).
Constant Rule
The constant rule of differentiation is the simplest rule but important to remember when differentiating functions. This states that the derivative of a constant function \( a \) is always zero. Mathematically, expressed as:
- \( \frac{d}{dx} c = 0 \)
Derivative of Exponential Functions
Differentiating exponential functions usually involves recognizing the form of the function and applying specific rules. For functions of the type \( f(x) = a^x \), where \( a \) is a constant, the derivative involves the natural logarithm of the base, \( a \). The derivative follows the rule:
- \( \frac{d}{dx}a^x = a^x \ln(a) \)